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Also, number of x n X n orthogonal matrices over GF(3) with determinant 1. - Max Alekseyev, Nov 06 2022
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a(n) = (1/2 times the ) * (number of n X n 0..2 matrices M with MM' mod 3 = I, where M' is the transpose of M and I is the n X n identity matrix).
a(2k+1) = 3^k * Prod_Product_{i=0..k-1} (3^(2k) - 3^(2i)); a(2k) = (3^k + (-1)^(k+1)) * Prod_Product_{i=1..k-1} (3^(2k) - 3^(2i)) (see MacWilliams, 1969). - Max Alekseyev, Nov 06 2022
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Jessie MacWilliams, <a href="https://doi.org/10.2307/2317262">Orthogonal Matrices Over Finite Fields</a>, The American Mathematical Monthly 76:2 (1969), 152-164.
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Even though the sequence has only 7 known terms (as of the time of this note), the conjecture below is based on the work (formulas, comments, etc.) by Jianing Song for sequence A318609. - Petros Hadjicostas, Dec 18 2019
Conjecture: a(n+1) = a(n) * A318609(n+1) for n >= 1. - _conjectured by _Petros Hadjicostas_, Dec 18 2019; proved based on the explicit formula by _Max Alekseyev_, Nov 06 2022