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A052275
Number of distinct 6th powers mod n.
13
1, 2, 2, 2, 3, 4, 2, 2, 2, 6, 6, 4, 3, 4, 6, 3, 9, 4, 4, 6, 4, 12, 12, 4, 11, 6, 4, 4, 15, 12, 6, 5, 12, 18, 6, 4, 7, 8, 6, 6, 21, 8, 8, 12, 6, 24, 24, 6, 8, 22, 18, 6, 27, 8, 18, 4, 8, 30, 30, 12, 11, 12, 4, 9, 9, 24, 12, 18, 24, 12, 36, 4, 13, 14, 22, 8, 12, 12
OFFSET
1,2
COMMENTS
This sequence is multiplicative [Li]. - Leon P Smith, Apr 16 2005
Same as the number of distinct elements that are both squares and cubes mod n. - Steven Finch, Mar 01 2006
LINKS
S. R. Finch and Pascal Sebah, Squares and Cubes Modulo n (arXiv:math.NT/0604465).
S. Li, On the number of elements with maximal order in the multiplicative group modulo n, Acta Arithm. 86 (2) (1998) 113, see proof of theorem 2.1
FORMULA
Conjecture: a(2^n) = 1,2,2,2,3,5,9,18,... with g.f. ( 1-2*x^2-2*x^3-x^4-x^5-2*x^6 ) / ( (x-1)*(2*x-1)*(1+x)*(1+x+x^2)*(x^2-x+1) ). - R. J. Mathar, Sep 28 2017
Conjecture: a(3^n) = 1,2,2,4,10,28,82,.... with g.f. ( 1-x-4*x^2-2*x^3-2*x^4-2*x^5-3*x^6 ) / ( (x-1)*(3*x-1)*(1+x)*(x^2-x+1)*(1+x+x^2) ). - R. J. Mathar, Sep 28 2017
MAPLE
A052275 := proc(m)
{seq( modp(b^6, m), b=0..m-1) };
nops(%) ;
end proc:
seq(A052275(m), m=1..100) ; # R. J. Mathar, Sep 22 2017
MATHEMATICA
Length[Union[#]]&/@Table[PowerMod[k, 6, n], {n, 100}, {k, n}] (* Zak Seidov, Feb 17 2013 *)
PROG
(PARI) a(n)=my(f=factor(n)); prod(i=1, #f[, 1], my(k=f[i, 1]^f[i, 2]); #vecsort(vector(k, i, i^6%k), , 8)) \\ Charles R Greathouse IV, Sep 05 2013
CROSSREFS
Cf. A000224 (squares), A046530 (cubic residues), A052273 (4th powers), A052274 (5th powers), A085310 (7th powers), A085311 (8th powers), A085312 (9th powers), A085313 (10th powers), A085314 (11th powers), A228849 (12th powers).
Sequence in context: A238279 A282933 A328576 * A338139 A244798 A308253
KEYWORD
nonn,mult
AUTHOR
N. J. A. Sloane, Feb 05 2000
STATUS
approved