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a(n) = (1/(n+1)) * [x^n] ( 1/( (1+x) * (1-x)^3 )^(n+1). - Seiichi Manyama, Feb 16 2024
Cf. A352373.
a(n) = (1/(n+1)) * [x^n] ( 1/(1+x) * (1-x)^3 )^(n+1). - Seiichi Manyama, Feb 16 2024
approved
editing
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proposed
reviewed
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proposed
<a href="/index/Res#revert">Index entries for reversions of series</a>
a(n) = (1/(n+1)) * Sum_{k=0..floor(n/2)} binomial(n+k,k) * binomial(3*n-2*k+1,n-2*k). - Seiichi Manyama, Jan 18 2024
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