reviewed
approved
reviewed
approved
proposed
reviewed
editing
proposed
For n = 152, there are two solutions: 152 = 5^3 + 3^3 = 19 * 2^3, thus a(152) = 2. This is also the first point where the sequence obtains value larger than one. - Antti Karttunen, Aug 31 2017
Antti Karttunen, <a href="/A279760/b279760.txt">Table of n, a(n) for n = 0..2055</a>
(PARI) A279760(n, m=8) = { my(s=0, p); if(!n, 1, for(c=m, n, if((ispower(c, 3, &p)&&isprime(p)), s+=A279760(n-c, c))); (s)); }; \\ Antti Karttunen, Aug 31 2017
approved
editing
editing
approved
M. Bernstein and N. J. A. Sloane, <a href="/A003633/a003633_1.pdf">Some canonical sequences of integers</a>, Linear Alg. Applications, 226-228 (1995), 57-72; erratum 320 (2000), 210. [Link to Lin. Alg. Applic. version together with omitted figures]
approved
editing
M. Bernstein and N. J. A. Sloane, <a href="http://arXiv.org/abs/math.CO/0205301">Some canonical sequences of integers</a>, Linear Alg. Applications, 226-228 (1995), 57-72; erratum 320 (2000), 210. [Link to arXiv version]
proposed
approved
editing
proposed