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Robert Israel, <a href="/A272230/b272230.txt">Table of n, a(n) for n = 0..418</a>
S:= series(2*exp(x)/(exp(2*x)+1+2*x), x, 31):
seq(coeff(S, x, j)*j!, j=0..30); # Robert Israel, May 24 2016
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a(n) = 1-2n*a(n-1)-Sum_{k=0..n-2}binomial(n,k)*2^(n-k-1)*a(k)
a(n) = Sum_{k=0..n} Sum_{j=0..k} Sum_{i=0..n} binomial(n,k)*binomial(k+i,i)*binomial(n,i)(i!*(-1)^(i+j)*(2j+1)^(n-i))/(2^k)
E.g.f.: 2*exp(x)/(exp(2*x)+1+2*x).
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a(n)=Sum_{k=0..n}Sum_{j=0..k}Sum_{i=0..n}binomial(n,k)*binomial(k+i,i)*binomial(n
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It appears that Empirically, for odd n, n|a(n) and for even n, (n-1)|a(n).
a(n)=1-2n*a(n-1)-Sum_{k=0..n-2}binomial(n,k)*2^(n-k-1)*a(k)
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