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6, 16, 44, 122, 268, 556, 886, 1446, 1964, 2900
a(12) from Charles R Greathouse IV, Jul 30 2015
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6, 16, 44, 122, 268, 556, 886, 1446, 1964
a(11) from Charles R Greathouse IV, Jul 28 2015
(PARI) a(n)=my(P=2*prod(i=1, n, prime(i)), r, last=P); forprime(p=2, P/2, if(isprime(P-p), if(last, r=max(r, p-last)); last=p)); r \\ Charles R Greathouse IV, Jul 24 2015
6, 16, 44, 122, 268, 556, 886, 1446
(PARI) lstp(n) = {my(v = []); pn = prod(i=1, n, prime(i)); forprime(p=1, pn-1, if (isprime(2*pn-p), v = concat(v, p))); my(w = vector(#v-1, k, v[k+1] - v[k])); vecmax(w); } \\ Michel Marcus, Jul 24 2015
(PARI) a(n)=my(P=2*prod(i=1, n, prime(i)), r, last); forprime(p=2, P/2, if(isprime(P-p), if(last, r=max(r, p-last)); last=p)); r \\ Charles R Greathouse IV, Jul 24 2015
a(10) from Charles R Greathouse IV, Jul 24 2015
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For n=3, primorial(3)=A002110(3) is 30 and P3 is (7, 13, 17, 19, 23, 29) because (53, 47, 43, 41, 37, 31) are all prime . The maximum gap between two consecutive terms of P3 is 6, obtained for (7,13) or (23,29), so a(3)=6.
(PARI) lstp(n) = {my(v = []); pn = prod(i=1, n, prime(i)); forprime(p=1, pn-1, if (isprime(2*pn-p), v = concat(v, p))); my(w = vector(#v-1, k, v[k+1] - v[k])); vecmax(w); } \\ Michel Marcus, Jul 24 2015
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