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Revision History for A187681

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Rank transform of the sequence floor(n/3); complement of A187682.
(history; published version)
#6 by N. J. A. Sloane at Sun Dec 04 19:46:24 EST 2016
MATHEMATICA

(*by _Peter J. C. Moses, _, Mar 12 2011*)

Discussion
Sun Dec 04
19:46
OEIS Server: https://oeis.org/edit/global/2576
#5 by Russ Cox at Fri Mar 30 18:57:19 EDT 2012
AUTHOR

_Clark Kimberling (ck6(AT)evansville.edu), _, Mar 12 2011

Discussion
Fri Mar 30
18:57
OEIS Server: https://oeis.org/edit/global/285
#4 by T. D. Noe at Sat Mar 12 19:01:59 EST 2011
STATUS

proposed

approved

#3 by Clark Kimberling at Sat Mar 12 14:49:28 EST 2011
NAME

allocated for Clark KimberlingRank transform of the sequence floor(n/3); complement of A187682.

DATA

1, 2, 3, 4, 5, 7, 8, 9, 11, 12, 13, 15, 16, 17, 19, 20, 21, 23, 24, 25, 26, 27, 28, 30, 31, 32, 34, 35, 36, 38, 39, 40, 41, 42, 43, 45, 46, 47, 49, 50, 51, 53, 54, 55, 56, 57, 58, 60, 61, 62, 64, 65, 66, 68, 69, 70, 71, 72, 73, 75, 76, 77, 79, 80, 81, 83, 84, 85, 86, 87, 88, 90, 91, 92, 94, 95, 96, 98, 99, 100, 102, 103, 104, 106, 107, 108, 110, 111, 112, 113, 114, 115, 117, 118, 119, 121, 122

OFFSET

1,2

COMMENTS

See A187224.

MATHEMATICA

seqA = Table[Floor[n/3], {n, 1, 220}]

seqB = Table[n, {n, 1, 220}]; (*A000027*)

jointRank[{seqA_,

seqB_}] := {Flatten@Position[#1, {_, 1}],

Flatten@Position[#1, {_, 2}]} &[

Sort@Flatten[{{#1, 1} & /@ seqA, {#1, 2} & /@ seqB}, 1]];

limseqU =

FixedPoint[jointRank[{seqA, #1[[1]]}] &,

jointRank[{seqA, seqB}]][[1]] (*A187681*)

Complement[Range[Length[seqA]], limseqU] (*A187682*)

(*by Peter Moses, Mar 12 2011*)

CROSSREFS
KEYWORD

allocated

nonn

AUTHOR

Clark Kimberling (ck6(AT)evansville.edu), Mar 12 2011

STATUS

approved

proposed

#2 by Clark Kimberling at Sat Mar 12 14:43:05 EST 2011
KEYWORD

allocating

allocated

#1 by Clark Kimberling at Sat Mar 12 14:43:05 EST 2011
NAME

allocated for Clark Kimberling

KEYWORD

allocating

STATUS

approved