AUTHOR
_Zak Seidov (zakseidov(AT)yahoo.com), _, Jul 27 2009
_Zak Seidov (zakseidov(AT)yahoo.com), _, Jul 27 2009
Numbers n with property that n^2 is a sum of three successive cubes.
0, 3, 6, 204
0,2
n^2=m^3+(m+1)^3+(m+2)^3 =3*(1 + m)*(3 + 2*m + m^2),
n = 0, 3, 6, 204 for m = -1, 0, 1, 23.
fini,full,nonn
Zak Seidov (zakseidov(AT)yahoo.com), Jul 27 2009
approved