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a(n) = (1/2)*((1151-240*sqrt(23))^n + (1151+240*sqrt(23))^n), with n >= 0. - Paolo P. Lava, Nov 24 2008
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a(n) = (1/2)*((1151-240*sqrt(23))^n + (1151+240*sqrt(23))^n), with n >= 0. - Paolo P. Lava, Nov 24 2008
easy,nonn,changed
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a(n) = (1/2)*((1151-240*sqrt(23))^n + (1151+240*sqrt(23))^n), with n >= 0. - Paolo P. Lava, Nov 24 2008
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Author?, Bob Jacobs, <a href="https://web.archive.org/web/20070203021412/httpTitle?The Nature of Mathematics and Mathematicians</a>
John Robertson, <a href="https://web.archive.org/web/20190501092519/http
<a href="/index/Rec#order_02">Index entries for linear recurrences with constant coefficients</a>, signature (2302, -1).
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