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Conjecture: a(n) ~ c n^2 log(n) for some positive constant c. - Robert Israel, Oct 26 2015
proposed
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if n::odd then delta:= 2*n
else delta:= n
fi:
for q from a[n] + delta by delta while not isprime(q) do od:
a[n+1]:= q
proposed
editing
editing
proposed
a[1]:= 2: a[2]:= 3:
for n from 2 to 1000 do
if n::odd then delta:= 2*n
else delta:= n
fi:
for q from a[n] + delta by delta while not isprime(q) do od:
a[n+1]:= q
od:
seq(a[i], i=1..1000); # Robert Israel, Oct 26 2015
approved
editing