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a(n) = (1/3)*(cos(n*(2/3)*Pi) + 1/2)*(1+(-1)^n) with n>=0. - Paolo P. Lava, Aug 23 2006
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This formula can be used to produce any periodic sequence of 6 numbers b,c,d,e,f,g: a(n)= b*(1/3)*(cos(n*(2/3)*Pi) + 1/2)*(1+(-1)^n) + c*(1/3)*(cos((n+5)*(2/3)*Pi) + 1/2)*(1+(-1)^(n+5)) + d*(1/3)*(cos((n+4)*(2/3)*Pi) + 1/2)*(1+(-1)^(n+4)) + e*(1/3)*(cos((n+3)*(2/3)*Pi) + 1/2)*(1+(-1)^(n+3))+ f*(1/3)*(cos((n+2)*(2/3)*Pi) + 1/2)*(1+(-1)^(n+2)) + g*(1/3)*(cos((n+1)*(2/3)*Pi) + 1/2)*(1+(-1)^(n+1)). - Paolo P. Lava, Aug 23 2006
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(MAGMAMagma) &cat[[1, 0^^5]^^30];
(MAGMAMagma) A079979 := func<n|IsDivisibleBy(n, 6)select 1 else 0>; [A079979:n in [0..59]]; // Jason Kimberley, Oct 10 2011
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Recurrence: a(n) = a(n-6).
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