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Revision History for A072393

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Showing entries 1-10 | older changes
Numbers n such that n - reverse(n) = phi(n).
(history; published version)
#13 by N. J. A. Sloane at Tue Feb 11 19:09:01 EST 2014
AUTHOR

_Joseph L. Pe (JosephL.Pe(AT)hotmail.com), _, Jul 21 2002

Discussion
Tue Feb 11
19:09
OEIS Server: https://oeis.org/edit/global/2120
#12 by N. J. A. Sloane at Sun Oct 28 13:20:28 EDT 2012
STATUS

proposed

approved

#11 by Giovanni Resta at Sun Oct 28 12:20:29 EDT 2012
STATUS

editing

proposed

#10 by Giovanni Resta at Sun Oct 28 12:20:17 EDT 2012
COMMENTS

a(51) > 10^12. - Giovanni Resta, Oct 28 2012

LINKS

Giovanni Resta, <a href="/A072393/b072393.txt">Table of n, a(n) for n = 1..50</a>

STATUS

approved

editing

#9 by Russ Cox at Fri Mar 30 17:37:41 EDT 2012
COMMENTS

If m>1 and p=2*10^m+3 is prime then n=27*p is in the sequence because n-reversal(n)=27*(2*10^m+3)-reversal(27*(2*10^m+3))= (54*10^m+81)-(18*10^m+45)=36*10^m+36=18*(2*10^m+2)=phi(27)* phi(2*10^m+3)=phi(27*(2*10^m+3))=phi(n). Also if m>2 and p=(389*10^m+109)/3 is prime then 7*p is in the sequence (the proof is easy). Next term is greater than 2*10^8. - _Farideh Firoozbakht (mymontain(AT)yahoo.com), _, Jan 27 2006

EXTENSIONS

More terms from _Farideh Firoozbakht (mymontain(AT)yahoo.com), _, Jan 27 2006

Discussion
Fri Mar 30
17:37
OEIS Server: https://oeis.org/edit/global/181
#8 by Russ Cox at Fri Mar 30 17:34:49 EDT 2012
EXTENSIONS

a(22)-a(29) from _Donovan Johnson (donovan.johnson(AT)yahoo.com), _, Dec 04 2011

Discussion
Fri Mar 30
17:34
OEIS Server: https://oeis.org/edit/global/163
#7 by T. D. Noe at Sun Dec 04 18:43:39 EST 2011
STATUS

proposed

approved

#6 by Donovan Johnson at Sun Dec 04 18:33:02 EST 2011
STATUS

editing

proposed

#5 by Donovan Johnson at Sun Dec 04 18:32:31 EST 2011
DATA

91, 874, 3411, 9093, 40112, 44252, 54081, 67284, 80224, 90933, 91503, 4961782, 5400081, 5726691, 8750834, 9076921, 9155055, 54000081, 62023914, 90766921, 93079231, 430770922, 540000081, 636355044, 808618664, 907666921, 928709013, 4050394312, 4262971312

EXTENSIONS

a(22)-a(29) from Donovan Johnson (donovan.johnson(AT)yahoo.com), Dec 04 2011

STATUS

approved

editing

#4 by N. J. A. Sloane at Sun Jun 29 03:00:00 EDT 2008
COMMENTS

If m>1 and p=2*10^m+3 is prime then n=27*p is in the sequence because n-reversal(n)=27*(2*10^m+3)-reversal(27*(2*10^m+3))= (54*10^m+81)-(18*10^m+45)=36*10^m+36=18*(2*10^m+2)=phi(27)* phi(2*10^m+3)=phi(27*(2*10^m+3))=phi(n). Also if m>2 and p=(389*10^m+109)/3 is prime then 7*p is in the sequence (the proof is easy). Next term is greater than 2*10^8. - Farideh Firoozbakht (mymontain(AT)yahoo.com), Jan 27 2006

KEYWORD

base,nonn,new