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Equals triangle A152205 as an infinite lower triangular matrix * the triangular numbers: [1, 3, 6, ...]. - Gary W. Adamson, Feb 14 2010
a(n) = (n+4)*(2*n^4 + 32*n^3 + 172*n^2 + 352*n + 15*(-1)^n + 225)/960. - R. J. Mathar, Apr 01 2010
(MAGMAMagma) [(n+4)*(2*n^4+32*n^3+172*n^2+352*n+15*(-1)^n+225)/960: n in [0..40]]; // Vincenzo Librandi, Feb 14 2016
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<a href="/index/Rec#order_08">Index entries for linear recurrences with constant coefficients</a>, signature (4, -4, -4, 10, -4, -4, 4, -1).
LinearRecurrence[{4, -4, -4, 10, -4, -4, 4, -1}, {1, 4, 12, 28, 58, 108, 188, 308}, 100] (* _G. C. Greubel_, Nov 25 2016 *)
108, 188, 308}, 100] (* G. C. Greubel, Nov 25 2016 *)
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a(n) is the number of partitions of n into four kinds of parts 1 and two kinds of parts 2. [_- _Joerg Arndt_, Mar 09 2016]
a(n) = (n+4)*(2*n^4 +32*n^3 +172*n^2 +352*n +15*(-1)^n +225)/960. [_- _R. J. Mathar_, Apr 01 2010]
LinearRecurrence[{4, -4, -4, 10, -4, -4, 4, -1}, {1, 4, 12, 28, 58,
108, 188, 308}, 100] (* G. C. Greubel, Nov 25 2016 *)
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a(n) = Sum_{i = 0..n} A002624(i). - Antal Pinter, May 05 2016
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