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a(n) and FibFibonacci(n) are congruent modulo 9 which implies that (a(n) mod 9) is equal to (FibFibonacci(n) mod 9) A007887(n). Thus (a(n) mod 9) is periodic with the Pisano period A001175(9) = 24. - Hieronymus Fischer, Jun 25 2007
It appears that a(n) - n stays negative for n > 5832, which explains why A020995 is finite. - T. D. Noe, Mar 19 2012
a(n) = FibFibonacci(n) - 9*sumSum_{k>0, } floor(FibFibonacci(n)/10^k)}. - Hieronymus Fischer, Jun 25 2007
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(MAGMAMagma) [&+Intseq(Fibonacci(n)): n in [0..80] ]; // Vincenzo Librandi, Jun 18 2015
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Cf. A068500.
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Cf. A261587.
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