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A166516
A product of consecutive doubled Fibonacci numbers.
6
1, 1, 2, 4, 10, 25, 65, 169, 442, 1156, 3026, 7921, 20737, 54289, 142130, 372100, 974170, 2550409, 6677057, 17480761, 45765226, 119814916, 313679522, 821223649, 2149991425, 5628750625, 14736260450, 38580030724, 101003831722
OFFSET
0,3
FORMULA
G.f.: (1-2*x-x^2+x^3) / ( (1-x)*(1+x)*(1-3*x+x^2) ).
a(n) = Fibonacci(2*floor(n/2) + 1)*Fibonacci(2*floor((n-1)/2) + 1).
a(n) = Fibonacci(A166514(2*n))^2 + Fibonacci(A166514(2*n+1))^2.
a(n) = Fibonacci(n)^2 * (1-(-1)^n)/2 + Fibonacci(n-1)*Fibonacci(n+1) * (1+(-1)^n)/2.
a(n+1)*a(n+3) - a(n+2)^2 = Fibonacci(n+2)^2 * (1-(-1)^n)/2.
a(n) = 3*a(n-1) - 3*a(n-3) + a(n-4). - G. C. Greubel, May 15 2016
MATHEMATICA
CoefficientList[Series[(1-2x-x^2+x^3)/((1-x)(1+x)(1-3x+x^2)), {x, 0, 30}], x] (* or *) LinearRecurrence[{3, 0, -3, 1}, {1, 1, 2, 4}, 30] (* Harvey P. Dale, Dec 26 2013 *)
PROG
(Magma)
A166516:= func< n | (n mod 2)*Fibonacci(n)^2 +((n+1) mod 2)*Fibonacci(n-1)*Fibonacci(n+1) >;
[A166516(n): n in [0..40]]; // G. C. Greubel, Aug 03 2024
(SageMath)
f=fibonacci
def A166516(n): return (n%2)*f(n)^2 +((n+1)%2)*f(n-1)*f(n+1)
[A166516(n) for n in range(41)] # G. C. Greubel, Aug 03 2024
CROSSREFS
Cf. A000045, A001654 (first differences), A166514.
Sequence in context: A026269 A000645 A005958 * A230552 A230555 A189912
KEYWORD
easy,nonn
AUTHOR
Paul Barry, Oct 16 2009
STATUS
approved