The average velocity of the water.

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Answer 1

Question

Chapter 9, Problem 1P

To determine

The average velocity of the water.

Expert Solution & Answer

Explanation of Solution

Given:

The pressure drop (dpdx) is 100 Pa.

The temperature of the water (T) is 20°C.

Calculation:

Consider the flow is laminar.

Since the plates are fixed, dhdx=0.

Refer Appendix A, “Physical Properties of Water vs. Temperature (SI Units)” at 20°C,

The density of the water (ρ) is 998.3 kg/m3.

The dynamic viscosity of water (μ) is 1.00×10−3 N⋅s/m2.

Calculate the average velocity.

V=−a212μdpdx=(4 m)212[1.00(10−3)N⋅s/m2](−100 Pa0.9m)=(4 m×1 m1000 mm)212[1.00(10−3)N⋅s/m2](−100 Pa× 1 N/m2Pa0.9m)=0.148 m/s

Thus, the average velocity is 0.148 m/s_.

Checks the assumption by calculate the Reynolds number.

Re==ρVaμ=(998.3kg/m3)(0.1481m/s)(0.004m)1.00(10−3)N⋅s/m2=592<1400

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Answer 2

Question

Chapter 9, Problem 1P

To determine

The average velocity of the water.

Expert Solution & Answer

Explanation of Solution

Given:

The pressure drop (dpdx) is 100 Pa.

The temperature of the water (T) is 20°C.

Calculation:

Consider the flow is laminar.

Since the plates are fixed, dhdx=0.

Refer Appendix A, “Physical Properties of Water vs. Temperature (SI Units)” at 20°C,

The density of the water (ρ) is 998.3 kg/m3.

The dynamic viscosity of water (μ) is 1.00×10−3 N⋅s/m2.

Calculate the average velocity.

V=−a212μdpdx=(4 m)212[1.00(10−3)N⋅s/m2](−100 Pa0.9m)=(4 m×1 m1000 mm)212[1.00(10−3)N⋅s/m2](−100 Pa× 1 N/m2Pa0.9m)=0.148 m/s

Thus, the average velocity is 0.148 m/s_.

Checks the assumption by calculate the Reynolds number.

Re==ρVaμ=(998.3kg/m3)(0.1481m/s)(0.004m)1.00(10−3)N⋅s/m2=592<1400

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Answer 3

Question

Chapter 9, Problem 1P

To determine

The average velocity of the water.

Expert Solution & Answer

Explanation of Solution

Given:

The pressure drop (dpdx) is 100 Pa.

The temperature of the water (T) is 20°C.

Calculation:

Consider the flow is laminar.

Since the plates are fixed, dhdx=0.

Refer Appendix A, “Physical Properties of Water vs. Temperature (SI Units)” at 20°C,

The density of the water (ρ) is 998.3 kg/m3.

The dynamic viscosity of water (μ) is 1.00×10−3 N⋅s/m2.

Calculate the average velocity.

V=−a212μdpdx=(4 m)212[1.00(10−3)N⋅s/m2](−100 Pa0.9m)=(4 m×1 m1000 mm)212[1.00(10−3)N⋅s/m2](−100 Pa× 1 N/m2Pa0.9m)=0.148 m/s

Thus, the average velocity is 0.148 m/s_.

Checks the assumption by calculate the Reynolds number.

Re==ρVaμ=(998.3kg/m3)(0.1481m/s)(0.004m)1.00(10−3)N⋅s/m2=592<1400

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Answer 4

Question

Chapter 9, Problem 1P

To determine

The average velocity of the water.

Expert Solution & Answer

Explanation of Solution

Given:

The pressure drop (dpdx) is 100 Pa.

The temperature of the water (T) is 20°C.

Calculation:

Consider the flow is laminar.

Since the plates are fixed, dhdx=0.

Refer Appendix A, “Physical Properties of Water vs. Temperature (SI Units)” at 20°C,

The density of the water (ρ) is 998.3 kg/m3.

The dynamic viscosity of water (μ) is 1.00×10−3 N⋅s/m2.

Calculate the average velocity.

V=−a212μdpdx=(4 m)212[1.00(10−3)N⋅s/m2](−100 Pa0.9m)=(4 m×1 m1000 mm)212[1.00(10−3)N⋅s/m2](−100 Pa× 1 N/m2Pa0.9m)=0.148 m/s

Thus, the average velocity is 0.148 m/s_.

Checks the assumption by calculate the Reynolds number.

Re==ρVaμ=(998.3kg/m3)(0.1481m/s)(0.004m)1.00(10−3)N⋅s/m2=592<1400

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Answer 5

Chapter 9, Problem 1P

To determine

The average velocity of the water.

Expert Solution & Answer

Explanation of Solution

Given:

The pressure drop (dpdx) is 100 Pa.

The temperature of the water (T) is 20°C.

Calculation:

Consider the flow is laminar.

Since the plates are fixed, dhdx=0.

Refer Appendix A, “Physical Properties of Water vs. Temperature (SI Units)” at 20°C,

The density of the water (ρ) is 998.3 kg/m3.

The dynamic viscosity of water (μ) is 1.00×10−3 N⋅s/m2.

Calculate the average velocity.

V=−a212μdpdx=(4 m)212[1.00(10−3)N⋅s/m2](−100 Pa0.9m)=(4 m×1 m1000 mm)212[1.00(10−3)N⋅s/m2](−100 Pa× 1 N/m2Pa0.9m)=0.148 m/s

Thus, the average velocity is 0.148 m/s_.

Checks the assumption by calculate the Reynolds number.

Re==ρVaμ=(998.3kg/m3)(0.1481m/s)(0.004m)1.00(10−3)N⋅s/m2=592<1400

Answer 6

Chapter 9, Problem 1P

To determine

The average velocity of the water.

Expert Solution & Answer

Explanation of Solution

Given:

The pressure drop (dpdx) is 100 Pa.

The temperature of the water (T) is 20°C.

Calculation:

Consider the flow is laminar.

Since the plates are fixed, dhdx=0.

Refer Appendix A, “Physical Properties of Water vs. Temperature (SI Units)” at 20°C,

The density of the water (ρ) is 998.3 kg/m3.

The dynamic viscosity of water (μ) is 1.00×10−3 N⋅s/m2.

Calculate the average velocity.

V=−a212μdpdx=(4 m)212[1.00(10−3)N⋅s/m2](−100 Pa0.9m)=(4 m×1 m1000 mm)212[1.00(10−3)N⋅s/m2](−100 Pa× 1 N/m2Pa0.9m)=0.148 m/s

Thus, the average velocity is 0.148 m/s_.

Checks the assumption by calculate the Reynolds number.

Re==ρVaμ=(998.3kg/m3)(0.1481m/s)(0.004m)1.00(10−3)N⋅s/m2=592<1400

Answer 7

Chapter 9, Problem 1P

To determine

The average velocity of the water.

Answer 8

Expert Solution & Answer

Explanation of Solution

Given:

The pressure drop (dpdx) is 100 Pa.

The temperature of the water (T) is 20°C.

Calculation:

Consider the flow is laminar.

Since the plates are fixed, dhdx=0.

Refer Appendix A, “Physical Properties of Water vs. Temperature (SI Units)” at 20°C,

The density of the water (ρ) is 998.3 kg/m3.

The dynamic viscosity of water (μ) is 1.00×10−3 N⋅s/m2.

Calculate the average velocity.

V=−a212μdpdx=(4 m)212[1.00(10−3)N⋅s/m2](−100 Pa0.9m)=(4 m×1 m1000 mm)212[1.00(10−3)N⋅s/m2](−100 Pa× 1 N/m2Pa0.9m)=0.148 m/s

Thus, the average velocity is 0.148 m/s_.

Checks the assumption by calculate the Reynolds number.

Re==ρVaμ=(998.3kg/m3)(0.1481m/s)(0.004m)1.00(10−3)N⋅s/m2=592<1400

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

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The average velocity of the water.

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The average velocity of the water.

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