A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN: 9780134753119
Author: Sheldon Ross
Publisher: PEARSON
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Chapter 8, Problem 8.1P

Suppose that X is a random variable with mean and variance both equal to 20. What can be said about P { 0 < X < 40 } ?

Expert Solution & Answer
Check Mark
To determine

To find: P(0<X<40)

Answer to Problem 8.1P

  P(0<X<40)=1920

Explanation of Solution

Given:

  Population mean(μ)=20Population variance(σ2)=40

Calculation:

  P(0<X<40)can be calculated as:

  P(0<X<40)=P(0μ<Xμ<40μ)m=P(020<Xμ<4020)=P(20<Xμ<20)=P(|Xμ|20)

Now,

  P(|Xμ|20)=P(P(|Xμ|20×20))11(20)21920

Thus, the required probability is 1920 .

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Chapter 8 Solutions

A First Course in Probability (10th Edition)

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