Chapter 8, Problem 3D

Question

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Answer 1

Expert Solution & Answer

Chapter 8, Problem 3D

Explanation of Solution

a.

Sum of “n” numbers using “while” loop:

Program:

#set the values

s = 0

i = 0

#get the input from the user

n = eval (input ("Enter the n value: "))

#check "i" is greater than or equal to "n"

while i <= n:

  #sum all the numbers

  s = s + i

  #increment the value

  ...

Explanation of Solution

b.

Sum first “n” odd numbers using “while” loop:

Program:

#set the values

s = 0

i = 1

#get the input from the user

n = eval (input ("Enter the n value: "))

#check "i" is greater than or equal to "n"

while i <= n:

  #sum all the numbers

  s = s + i

  #increment the value

...

Explanation of Solution

c.

Sum of “n” numbers using “while” loop:

Program:

#set the values

s = 0

#check the condition

while True:

  #get the input from the user

  n= eval(input("Enter a value: "))

  #check "n" is equal to 999

  if n == 999:

    #break the statement

    break

�...

Explanation of Solution

d.

Displaying the number of times a whole number “n” can be divided by 2 using “while” loop:

Program:

#get the input from the user

n = int(input("Enter number: "))

#set the value

count = 0

#check "n" is greater than 1

while(n>1):

  #divide the "n" by 2

  n = n // 2

  #incremen...

Expert Solution & Answer

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Check out a sample textbook solution

See solution

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Answer 2

Expert Solution & Answer

Chapter 8, Problem 3D

Explanation of Solution

a.

Sum of “n” numbers using “while” loop:

Program:

#set the values

s = 0

i = 0

#get the input from the user

n = eval (input ("Enter the n value: "))

#check "i" is greater than or equal to "n"

while i <= n:

  #sum all the numbers

  s = s + i

  #increment the value

  ...

Explanation of Solution

b.

Sum first “n” odd numbers using “while” loop:

Program:

#set the values

s = 0

i = 1

#get the input from the user

n = eval (input ("Enter the n value: "))

#check "i" is greater than or equal to "n"

while i <= n:

  #sum all the numbers

  s = s + i

  #increment the value

...

Explanation of Solution

c.

Sum of “n” numbers using “while” loop:

Program:

#set the values

s = 0

#check the condition

while True:

  #get the input from the user

  n= eval(input("Enter a value: "))

  #check "n" is equal to 999

  if n == 999:

    #break the statement

    break

�...

Explanation of Solution

d.

Displaying the number of times a whole number “n” can be divided by 2 using “while” loop:

Program:

#get the input from the user

n = int(input("Enter number: "))

#set the value

count = 0

#check "n" is greater than 1

while(n>1):

  #divide the "n" by 2

  n = n // 2

  #incremen...

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Expert Solution & Answer

Chapter 8, Problem 3D

Explanation of Solution

a.

Sum of “n” numbers using “while” loop:

Program:

#set the values

s = 0

i = 0

#get the input from the user

n = eval (input ("Enter the n value: "))

#check "i" is greater than or equal to "n"

while i <= n:

  #sum all the numbers

  s = s + i

  #increment the value

  ...

Explanation of Solution

b.

Sum first “n” odd numbers using “while” loop:

Program:

#set the values

s = 0

i = 1

#get the input from the user

n = eval (input ("Enter the n value: "))

#check "i" is greater than or equal to "n"

while i <= n:

  #sum all the numbers

  s = s + i

  #increment the value

...

Explanation of Solution

c.

Sum of “n” numbers using “while” loop:

Program:

#set the values

s = 0

#check the condition

while True:

  #get the input from the user

  n= eval(input("Enter a value: "))

  #check "n" is equal to 999

  if n == 999:

    #break the statement

    break

�...

Explanation of Solution

d.

Displaying the number of times a whole number “n” can be divided by 2 using “while” loop:

Program:

#get the input from the user

n = int(input("Enter number: "))

#set the value

count = 0

#check "n" is greater than 1

while(n>1):

  #divide the "n" by 2

  n = n // 2

  #incremen...

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Expert Solution & Answer

Chapter 8, Problem 3D

Explanation of Solution

a.

Sum of “n” numbers using “while” loop:

Program:

#set the values

s = 0

i = 0

#get the input from the user

n = eval (input ("Enter the n value: "))

#check "i" is greater than or equal to "n"

while i <= n:

  #sum all the numbers

  s = s + i

  #increment the value

  ...

Explanation of Solution

b.

Sum first “n” odd numbers using “while” loop:

Program:

#set the values

s = 0

i = 1

#get the input from the user

n = eval (input ("Enter the n value: "))

#check "i" is greater than or equal to "n"

while i <= n:

  #sum all the numbers

  s = s + i

  #increment the value

...

Explanation of Solution

c.

Sum of “n” numbers using “while” loop:

Program:

#set the values

s = 0

#check the condition

while True:

  #get the input from the user

  n= eval(input("Enter a value: "))

  #check "n" is equal to 999

  if n == 999:

    #break the statement

    break

�...

Explanation of Solution

d.

Displaying the number of times a whole number “n” can be divided by 2 using “while” loop:

Program:

#get the input from the user

n = int(input("Enter number: "))

#set the value

count = 0

#check "n" is greater than 1

while(n>1):

  #divide the "n" by 2

  n = n // 2

  #incremen...

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 5

Expert Solution & Answer

Answer 6

Expert Solution & Answer

Answer 7

Chapter 8, Problem 3D

Explanation of Solution

a.

Sum of “n” numbers using “while” loop:

Program:

#set the values

s = 0

i = 0

#get the input from the user

n = eval (input ("Enter the n value: "))

#check "i" is greater than or equal to "n"

while i <= n:

  #sum all the numbers

  s = s + i

  #increment the value

  ...

Explanation of Solution

b.

Sum first “n” odd numbers using “while” loop:

Program:

#set the values

s = 0

i = 1

#get the input from the user

n = eval (input ("Enter the n value: "))

#check "i" is greater than or equal to "n"

while i <= n:

  #sum all the numbers

  s = s + i

  #increment the value

...

Explanation of Solution

c.

Sum of “n” numbers using “while” loop:

Program:

#set the values

s = 0

#check the condition

while True:

  #get the input from the user

  n= eval(input("Enter a value: "))

  #check "n" is equal to 999

  if n == 999:

    #break the statement

    break

�...

Explanation of Solution

d.

Displaying the number of times a whole number “n” can be divided by 2 using “while” loop:

Program:

#get the input from the user

n = int(input("Enter number: "))

#set the value

count = 0

#check "n" is greater than 1

while(n>1):

  #divide the "n" by 2

  n = n // 2

  #incremen...

Answer 8

Chapter 8, Problem 3D

Explanation of Solution

a.

Sum of “n” numbers using “while” loop:

Program:

#set the values

s = 0

i = 0

#get the input from the user

n = eval (input ("Enter the n value: "))

#check "i" is greater than or equal to "n"

while i <= n:

  #sum all the numbers

  s = s + i

  #increment the value

  ...

Answer 9

Chapter 8, Problem 3D

Explanation of Solution

a.

Sum of “n” numbers using “while” loop:

Program:

#set the values

s = 0

i = 0

#get the input from the user

n = eval (input ("Enter the n value: "))

#check "i" is greater than or equal to "n"

while i <= n:

  #sum all the numbers

  s = s + i

  #increment the value

  ...

Answer 10

Explanation of Solution

b.

Sum first “n” odd numbers using “while” loop:

Program:

#set the values

s = 0

i = 1

#get the input from the user

n = eval (input ("Enter the n value: "))

#check "i" is greater than or equal to "n"

while i <= n:

  #sum all the numbers

  s = s + i

  #increment the value

...

Answer 11

Explanation of Solution

b.

Sum first “n” odd numbers using “while” loop:

Program:

#set the values

s = 0

i = 1

#get the input from the user

n = eval (input ("Enter the n value: "))

#check "i" is greater than or equal to "n"

while i <= n:

  #sum all the numbers

  s = s + i

  #increment the value

...

Answer 12

Explanation of Solution

c.

Sum of “n” numbers using “while” loop:

Program:

#set the values

s = 0

#check the condition

while True:

  #get the input from the user

  n= eval(input("Enter a value: "))

  #check "n" is equal to 999

  if n == 999:

    #break the statement

    break

�...

Answer 13

Explanation of Solution

c.

Sum of “n” numbers using “while” loop:

Program:

#set the values

s = 0

#check the condition

while True:

  #get the input from the user

  n= eval(input("Enter a value: "))

  #check "n" is equal to 999

  if n == 999:

    #break the statement

    break

�...

Answer 14

Explanation of Solution

d.

Displaying the number of times a whole number “n” can be divided by 2 using “while” loop:

Program:

#get the input from the user

n = int(input("Enter number: "))

#set the value

count = 0

#check "n" is greater than 1

while(n>1):

  #divide the "n" by 2

  n = n // 2

  #incremen...

Answer 15

Explanation of Solution

d.

Displaying the number of times a whole number “n” can be divided by 2 using “while” loop:

Program:

#get the input from the user

n = int(input("Enter number: "))

#set the value

count = 0

#check "n" is greater than 1

while(n>1):

  #divide the "n" by 2

  n = n // 2

  #incremen...

Answer 16

Expert Solution & Answer

Answer 17

Expert Solution & Answer

Answer 18

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Check out a sample textbook solution

See solution

Answer 19

Chapter 8, Problem 1TF Chapter 8, Problem 2TF Chapter 8, Problem 3TF Chapter 8, Problem 4TF Chapter 8, Problem 5TF Chapter 8, Problem 6TF Chapter 8, Problem 7TF Chapter 8, Problem 8TF Chapter 8, Problem 9TF Chapter 8, Problem 10TF

Chapter 8, Problem 3D

Solution Summary: The author explains how the "while" loop is used to check "i" is greater than or equal to "n"

Concept explainers

Videos

Explanation of Solution

a.

Sum of “n” numbers using “while” loop:

Program:

#set the values

s = 0

i = 0

#get the input from the user

n = eval (input ("Enter the n value: "))

#check "i" is greater than or equal to "n"

while i <= n:

  #sum all the numbers

  s = s + i

  #increment the value

  ...

Explanation of Solution

b.

Sum first “n” odd numbers using “while” loop:

Program:

#set the values

s = 0

i = 1

#get the input from the user

n = eval (input ("Enter the n value: "))

#check "i" is greater than or equal to "n"

while i <= n:

  #sum all the numbers

  s = s + i

  #increment the value

...

Explanation of Solution

c.

Sum of “n” numbers using “while” loop:

Program:

#set the values

s = 0

#check the condition

while True:

  #get the input from the user

  n= eval(input("Enter a value: "))

  #check "n" is equal to 999

  if n == 999:

    #break the statement

    break

�...

Explanation of Solution

d.

Displaying the number of times a whole number “n” can be divided by 2 using “while” loop:

Program:

#get the input from the user

n = int(input("Enter number: "))

#set the value

count = 0

#check "n" is greater than 1

while(n>1):

  #divide the "n" by 2

  n = n // 2

  #incremen...

Want to see the full answer?

Chapter 8 Solutions

Chapter 8, Problem 3D

Solution Summary: The author explains how the "while" loop is used to check "i" is greater than or equal to "n"

Concept explainers

Videos

Explanation of Solution

a. Sum of “n” numbers using “while” loop: Program: #set the values s = 0 i = 0 #get the input from the user n = eval (input ("Enter the n value: ")) #check "i" is greater than or equal to "n" while i <= n: #sum all the numbers s = s + i #increment the value ...

Explanation of Solution

b. Sum first “n” odd numbers using “while” loop: Program: #set the values s = 0 i = 1 #get the input from the user n = eval (input ("Enter the n value: ")) #check "i" is greater than or equal to "n" while i <= n: #sum all the numbers s = s + i #increment the value ...

Explanation of Solution

c. Sum of “n” numbers using “while” loop: Program: #set the values s = 0 #check the condition while True: #get the input from the user n= eval(input("Enter a value: ")) #check "n" is equal to 999 if n == 999: #break the statement break �...

Explanation of Solution

d. Displaying the number of times a whole number “n” can be divided by 2 using “while” loop: Program: #get the input from the user n = int(input("Enter number: ")) #set the value count = 0 #check "n" is greater than 1 while(n>1): #divide the "n" by 2 n = n // 2 #incremen...

Want to see the full answer?

Chapter 8 Solutions

a.

Sum of “n” numbers using “while” loop:

Program:

#set the values

s = 0

i = 0

#get the input from the user

n = eval (input ("Enter the n value: "))

#check "i" is greater than or equal to "n"

while i <= n:

#sum all the numbers

s = s + i

#increment the value

...

b.

Sum first “n” odd numbers using “while” loop:

Program:

#set the values

s = 0

i = 1

#get the input from the user

n = eval (input ("Enter the n value: "))

#check "i" is greater than or equal to "n"

while i <= n:

#sum all the numbers

s = s + i

#increment the value

...

c.

Sum of “n” numbers using “while” loop:

Program:

#set the values

s = 0

#check the condition

while True:

#get the input from the user

n= eval(input("Enter a value: "))

#check "n" is equal to 999

if n == 999:

#break the statement

break

�...

d.

Displaying the number of times a whole number “n” can be divided by 2 using “while” loop:

Program:

#get the input from the user

n = int(input("Enter number: "))

#set the value

count = 0

#check "n" is greater than 1

while(n>1):

#divide the "n" by 2

n = n // 2

#incremen...