Chapter 7, Problem 18PE

Question

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Answer 1

Question

Chapter 7, Problem 18PE

Expert Solution & Answer

Program Plan Intro

Validation of date input

Program plan:

Define the “leap_Year()” function,
- Check whether the year is not divisible by "4",
  - If the condition is “True”, return “False”.
  - Otherwise, check whether the year is divisible by "100",
    - If it is “True”, check whether the year is divisible by "400",
      - If it is “True”, return “True”.
      - Otherwise, return “False”.
    - Otherwise, return “True”.
Define the “main()” function,
- Execute the “try” statement to raise the exception if it is occurred.
  - Get the input from the user.
  - Split the user input based on "/" using “split()”.
  - Convert the string type inputs into integer type.
  - Check whether either the month is greater than “12” or day is greater than “12”,
    - If it is “True”, print the string “This date is invalid”
    - Otherwise, check whether the day is less than or equal to “28”,
      - If it is “True”, print the string as “This date is valid”.
      - Otherwise, check whether the month is "2" and "29",
      - If it is “True”, check whether the Boolean value return from “leap_Year()” is “False”.
        
        If it is “True”, print “This date is invalid”.
        
        Otherwise, print “This date is valid”.
        
        Otherwise, check whether the day is “31”,
        
        If it “True”, check whether the month is either "2" or "4" or "6" or "11",
        
        If the above condition is “True”, print invalid.
        
        Otherwise, print valid.
        
        Otherwise, print “This date is valid”.
      - Catch the exception using “except ValueError” statement, if the exception of type “ValueError” occurs.
    - Handle the exception.
  - Catch the exception using “except” statement, if any type of exception occurs.
- Call the function “main()”.

Program Description Answer

This Python program is to add decisions and exception handling as required making it truly robust.

Explanation of Solution

Program:

File name: “year.py”

#Define the function

def leap_Year(yr):

#Check whether the year is not divisible by "4"

if (yr % 4) != 0:

#Return the boolean value

return False

#Otherwise

else:

#Check whether the year is divisible by "100"

if (yr % 100) == 0:

#Check whether the year is divisible by "400"

if (yr % 400) ==0:

#Return boolean value

return True

#Otherwise

else:

#Return boolean value

return False

#Otherwise

else:

#Return boolean value

return True

#Define the function

def main():

#Make a try

try:

#Get the input from the user

date_Str = input("Enter a date in the form MM/DD/YYYY: ")

#Split the user input based on "/" using split()

month_Str, day_Str, year_Str = date_Str.split("/")

#Convert the string into integer

mon = int(month_Str)

#Convert the string into integer

d = int(day_Str)

#Convert the string into integer

yr = int(year_Str)

#Execute the condition

if mon > 12 or d > 31:

#Print the string

print("This date is invalid.")

#Otherwise

else:

#Check whether the day is less than or equal to 28

if d <= 28:

#Print the string

print("This date is valid.")

#Check whether the month is "2" and "29"

elif mon == 2 and d == 29:

#Check whether the boolean value return from "leap_Year()" is "False"

if leap_Year(yr) == False:

#Print the string

print("This date is invalid.")

#Otherwise

else:

#Print the string

print("This date is valid.")

#Check whether the day is "31"

elif d == 31:

'''Check whether the month is either "2" or "4" or "6" or "11"'''

if mon == 2 or 4 or 6 or 11:

#Print the string

print("This date is invalid")

#Otherwise

else:

#Print the string

print("This date is valid")

#Otherwise

else:

#Print the string

print("The date is valid.")

#Catch the exception

except ValueError:

#Handle the exception

print("Your input was not in the correct form.")

#Catch the exception

except:

#Handle the exception

print("Something went wrong!")

#Call the function

main()

Sample Output

Output:

Enter a date in the form MM/DD/YYYY: 02/30/2000

The date is valid.

>>>

Additional output:

Enter a date in the form MM/DD/YYYY: 02-05-2000

Your input was not in the correct form.

>>>

Additional output:

Enter a date in the form MM/DD/YYYY: 06/31/2000

This date is invalid

>>>

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Answer 2

Question

Chapter 7, Problem 18PE

Expert Solution & Answer

Program Plan Intro

Validation of date input

Program plan:

Define the “leap_Year()” function,
- Check whether the year is not divisible by "4",
  - If the condition is “True”, return “False”.
  - Otherwise, check whether the year is divisible by "100",
    - If it is “True”, check whether the year is divisible by "400",
      - If it is “True”, return “True”.
      - Otherwise, return “False”.
    - Otherwise, return “True”.
Define the “main()” function,
- Execute the “try” statement to raise the exception if it is occurred.
  - Get the input from the user.
  - Split the user input based on "/" using “split()”.
  - Convert the string type inputs into integer type.
  - Check whether either the month is greater than “12” or day is greater than “12”,
    - If it is “True”, print the string “This date is invalid”
    - Otherwise, check whether the day is less than or equal to “28”,
      - If it is “True”, print the string as “This date is valid”.
      - Otherwise, check whether the month is "2" and "29",
      - If it is “True”, check whether the Boolean value return from “leap_Year()” is “False”.
        
        If it is “True”, print “This date is invalid”.
        
        Otherwise, print “This date is valid”.
        
        Otherwise, check whether the day is “31”,
        
        If it “True”, check whether the month is either "2" or "4" or "6" or "11",
        
        If the above condition is “True”, print invalid.
        
        Otherwise, print valid.
        
        Otherwise, print “This date is valid”.
      - Catch the exception using “except ValueError” statement, if the exception of type “ValueError” occurs.
    - Handle the exception.
  - Catch the exception using “except” statement, if any type of exception occurs.
- Call the function “main()”.

Program Description Answer

This Python program is to add decisions and exception handling as required making it truly robust.

Explanation of Solution

Program:

File name: “year.py”

#Define the function

def leap_Year(yr):

#Check whether the year is not divisible by "4"

if (yr % 4) != 0:

#Return the boolean value

return False

#Otherwise

else:

#Check whether the year is divisible by "100"

if (yr % 100) == 0:

#Check whether the year is divisible by "400"

if (yr % 400) ==0:

#Return boolean value

return True

#Otherwise

else:

#Return boolean value

return False

#Otherwise

else:

#Return boolean value

return True

#Define the function

def main():

#Make a try

try:

#Get the input from the user

date_Str = input("Enter a date in the form MM/DD/YYYY: ")

#Split the user input based on "/" using split()

month_Str, day_Str, year_Str = date_Str.split("/")

#Convert the string into integer

mon = int(month_Str)

#Convert the string into integer

d = int(day_Str)

#Convert the string into integer

yr = int(year_Str)

#Execute the condition

if mon > 12 or d > 31:

#Print the string

print("This date is invalid.")

#Otherwise

else:

#Check whether the day is less than or equal to 28

if d <= 28:

#Print the string

print("This date is valid.")

#Check whether the month is "2" and "29"

elif mon == 2 and d == 29:

#Check whether the boolean value return from "leap_Year()" is "False"

if leap_Year(yr) == False:

#Print the string

print("This date is invalid.")

#Otherwise

else:

#Print the string

print("This date is valid.")

#Check whether the day is "31"

elif d == 31:

'''Check whether the month is either "2" or "4" or "6" or "11"'''

if mon == 2 or 4 or 6 or 11:

#Print the string

print("This date is invalid")

#Otherwise

else:

#Print the string

print("This date is valid")

#Otherwise

else:

#Print the string

print("The date is valid.")

#Catch the exception

except ValueError:

#Handle the exception

print("Your input was not in the correct form.")

#Catch the exception

except:

#Handle the exception

print("Something went wrong!")

#Call the function

main()

Sample Output

Output:

Enter a date in the form MM/DD/YYYY: 02/30/2000

The date is valid.

>>>

Additional output:

Enter a date in the form MM/DD/YYYY: 02-05-2000

Your input was not in the correct form.

>>>

Additional output:

Enter a date in the form MM/DD/YYYY: 06/31/2000

This date is invalid

>>>

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Answer 3

Question

Chapter 7, Problem 18PE

Expert Solution & Answer

Program Plan Intro

Validation of date input

Program plan:

Define the “leap_Year()” function,
- Check whether the year is not divisible by "4",
  - If the condition is “True”, return “False”.
  - Otherwise, check whether the year is divisible by "100",
    - If it is “True”, check whether the year is divisible by "400",
      - If it is “True”, return “True”.
      - Otherwise, return “False”.
    - Otherwise, return “True”.
Define the “main()” function,
- Execute the “try” statement to raise the exception if it is occurred.
  - Get the input from the user.
  - Split the user input based on "/" using “split()”.
  - Convert the string type inputs into integer type.
  - Check whether either the month is greater than “12” or day is greater than “12”,
    - If it is “True”, print the string “This date is invalid”
    - Otherwise, check whether the day is less than or equal to “28”,
      - If it is “True”, print the string as “This date is valid”.
      - Otherwise, check whether the month is "2" and "29",
      - If it is “True”, check whether the Boolean value return from “leap_Year()” is “False”.
        
        If it is “True”, print “This date is invalid”.
        
        Otherwise, print “This date is valid”.
        
        Otherwise, check whether the day is “31”,
        
        If it “True”, check whether the month is either "2" or "4" or "6" or "11",
        
        If the above condition is “True”, print invalid.
        
        Otherwise, print valid.
        
        Otherwise, print “This date is valid”.
      - Catch the exception using “except ValueError” statement, if the exception of type “ValueError” occurs.
    - Handle the exception.
  - Catch the exception using “except” statement, if any type of exception occurs.
- Call the function “main()”.

Program Description Answer

This Python program is to add decisions and exception handling as required making it truly robust.

Explanation of Solution

Program:

File name: “year.py”

#Define the function

def leap_Year(yr):

#Check whether the year is not divisible by "4"

if (yr % 4) != 0:

#Return the boolean value

return False

#Otherwise

else:

#Check whether the year is divisible by "100"

if (yr % 100) == 0:

#Check whether the year is divisible by "400"

if (yr % 400) ==0:

#Return boolean value

return True

#Otherwise

else:

#Return boolean value

return False

#Otherwise

else:

#Return boolean value

return True

#Define the function

def main():

#Make a try

try:

#Get the input from the user

date_Str = input("Enter a date in the form MM/DD/YYYY: ")

#Split the user input based on "/" using split()

month_Str, day_Str, year_Str = date_Str.split("/")

#Convert the string into integer

mon = int(month_Str)

#Convert the string into integer

d = int(day_Str)

#Convert the string into integer

yr = int(year_Str)

#Execute the condition

if mon > 12 or d > 31:

#Print the string

print("This date is invalid.")

#Otherwise

else:

#Check whether the day is less than or equal to 28

if d <= 28:

#Print the string

print("This date is valid.")

#Check whether the month is "2" and "29"

elif mon == 2 and d == 29:

#Check whether the boolean value return from "leap_Year()" is "False"

if leap_Year(yr) == False:

#Print the string

print("This date is invalid.")

#Otherwise

else:

#Print the string

print("This date is valid.")

#Check whether the day is "31"

elif d == 31:

'''Check whether the month is either "2" or "4" or "6" or "11"'''

if mon == 2 or 4 or 6 or 11:

#Print the string

print("This date is invalid")

#Otherwise

else:

#Print the string

print("This date is valid")

#Otherwise

else:

#Print the string

print("The date is valid.")

#Catch the exception

except ValueError:

#Handle the exception

print("Your input was not in the correct form.")

#Catch the exception

except:

#Handle the exception

print("Something went wrong!")

#Call the function

main()

Sample Output

Output:

Enter a date in the form MM/DD/YYYY: 02/30/2000

The date is valid.

>>>

Additional output:

Enter a date in the form MM/DD/YYYY: 02-05-2000

Your input was not in the correct form.

>>>

Additional output:

Enter a date in the form MM/DD/YYYY: 06/31/2000

This date is invalid

>>>

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Answer 4

Question

Chapter 7, Problem 18PE

Expert Solution & Answer

Program Plan Intro

Validation of date input

Program plan:

Define the “leap_Year()” function,
- Check whether the year is not divisible by "4",
  - If the condition is “True”, return “False”.
  - Otherwise, check whether the year is divisible by "100",
    - If it is “True”, check whether the year is divisible by "400",
      - If it is “True”, return “True”.
      - Otherwise, return “False”.
    - Otherwise, return “True”.
Define the “main()” function,
- Execute the “try” statement to raise the exception if it is occurred.
  - Get the input from the user.
  - Split the user input based on "/" using “split()”.
  - Convert the string type inputs into integer type.
  - Check whether either the month is greater than “12” or day is greater than “12”,
    - If it is “True”, print the string “This date is invalid”
    - Otherwise, check whether the day is less than or equal to “28”,
      - If it is “True”, print the string as “This date is valid”.
      - Otherwise, check whether the month is "2" and "29",
      - If it is “True”, check whether the Boolean value return from “leap_Year()” is “False”.
        
        If it is “True”, print “This date is invalid”.
        
        Otherwise, print “This date is valid”.
        
        Otherwise, check whether the day is “31”,
        
        If it “True”, check whether the month is either "2" or "4" or "6" or "11",
        
        If the above condition is “True”, print invalid.
        
        Otherwise, print valid.
        
        Otherwise, print “This date is valid”.
      - Catch the exception using “except ValueError” statement, if the exception of type “ValueError” occurs.
    - Handle the exception.
  - Catch the exception using “except” statement, if any type of exception occurs.
- Call the function “main()”.

Program Description Answer

This Python program is to add decisions and exception handling as required making it truly robust.

Explanation of Solution

Program:

File name: “year.py”

#Define the function

def leap_Year(yr):

#Check whether the year is not divisible by "4"

if (yr % 4) != 0:

#Return the boolean value

return False

#Otherwise

else:

#Check whether the year is divisible by "100"

if (yr % 100) == 0:

#Check whether the year is divisible by "400"

if (yr % 400) ==0:

#Return boolean value

return True

#Otherwise

else:

#Return boolean value

return False

#Otherwise

else:

#Return boolean value

return True

#Define the function

def main():

#Make a try

try:

#Get the input from the user

date_Str = input("Enter a date in the form MM/DD/YYYY: ")

#Split the user input based on "/" using split()

month_Str, day_Str, year_Str = date_Str.split("/")

#Convert the string into integer

mon = int(month_Str)

#Convert the string into integer

d = int(day_Str)

#Convert the string into integer

yr = int(year_Str)

#Execute the condition

if mon > 12 or d > 31:

#Print the string

print("This date is invalid.")

#Otherwise

else:

#Check whether the day is less than or equal to 28

if d <= 28:

#Print the string

print("This date is valid.")

#Check whether the month is "2" and "29"

elif mon == 2 and d == 29:

#Check whether the boolean value return from "leap_Year()" is "False"

if leap_Year(yr) == False:

#Print the string

print("This date is invalid.")

#Otherwise

else:

#Print the string

print("This date is valid.")

#Check whether the day is "31"

elif d == 31:

'''Check whether the month is either "2" or "4" or "6" or "11"'''

if mon == 2 or 4 or 6 or 11:

#Print the string

print("This date is invalid")

#Otherwise

else:

#Print the string

print("This date is valid")

#Otherwise

else:

#Print the string

print("The date is valid.")

#Catch the exception

except ValueError:

#Handle the exception

print("Your input was not in the correct form.")

#Catch the exception

except:

#Handle the exception

print("Something went wrong!")

#Call the function

main()

Sample Output

Output:

Enter a date in the form MM/DD/YYYY: 02/30/2000

The date is valid.

>>>

Additional output:

Enter a date in the form MM/DD/YYYY: 02-05-2000

Your input was not in the correct form.

>>>

Additional output:

Enter a date in the form MM/DD/YYYY: 06/31/2000

This date is invalid

>>>

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Answer 5

Expert Solution & Answer

Program Plan Intro

Validation of date input

Program plan:

Define the “leap_Year()” function,
- Check whether the year is not divisible by "4",
  - If the condition is “True”, return “False”.
  - Otherwise, check whether the year is divisible by "100",
    - If it is “True”, check whether the year is divisible by "400",
      - If it is “True”, return “True”.
      - Otherwise, return “False”.
    - Otherwise, return “True”.
Define the “main()” function,
- Execute the “try” statement to raise the exception if it is occurred.
  - Get the input from the user.
  - Split the user input based on "/" using “split()”.
  - Convert the string type inputs into integer type.
  - Check whether either the month is greater than “12” or day is greater than “12”,
    - If it is “True”, print the string “This date is invalid”
    - Otherwise, check whether the day is less than or equal to “28”,
      - If it is “True”, print the string as “This date is valid”.
      - Otherwise, check whether the month is "2" and "29",
      - If it is “True”, check whether the Boolean value return from “leap_Year()” is “False”.
        
        If it is “True”, print “This date is invalid”.
        
        Otherwise, print “This date is valid”.
        
        Otherwise, check whether the day is “31”,
        
        If it “True”, check whether the month is either "2" or "4" or "6" or "11",
        
        If the above condition is “True”, print invalid.
        
        Otherwise, print valid.
        
        Otherwise, print “This date is valid”.
      - Catch the exception using “except ValueError” statement, if the exception of type “ValueError” occurs.
    - Handle the exception.
  - Catch the exception using “except” statement, if any type of exception occurs.
- Call the function “main()”.

Program Description Answer

This Python program is to add decisions and exception handling as required making it truly robust.

Explanation of Solution

Program:

File name: “year.py”

#Define the function

def leap_Year(yr):

#Check whether the year is not divisible by "4"

if (yr % 4) != 0:

#Return the boolean value

return False

#Otherwise

else:

#Check whether the year is divisible by "100"

if (yr % 100) == 0:

#Check whether the year is divisible by "400"

if (yr % 400) ==0:

#Return boolean value

return True

#Otherwise

else:

#Return boolean value

return False

#Otherwise

else:

#Return boolean value

return True

#Define the function

def main():

#Make a try

try:

#Get the input from the user

date_Str = input("Enter a date in the form MM/DD/YYYY: ")

#Split the user input based on "/" using split()

month_Str, day_Str, year_Str = date_Str.split("/")

#Convert the string into integer

mon = int(month_Str)

#Convert the string into integer

d = int(day_Str)

#Convert the string into integer

yr = int(year_Str)

#Execute the condition

if mon > 12 or d > 31:

#Print the string

print("This date is invalid.")

#Otherwise

else:

#Check whether the day is less than or equal to 28

if d <= 28:

#Print the string

print("This date is valid.")

#Check whether the month is "2" and "29"

elif mon == 2 and d == 29:

#Check whether the boolean value return from "leap_Year()" is "False"

if leap_Year(yr) == False:

#Print the string

print("This date is invalid.")

#Otherwise

else:

#Print the string

print("This date is valid.")

#Check whether the day is "31"

elif d == 31:

'''Check whether the month is either "2" or "4" or "6" or "11"'''

if mon == 2 or 4 or 6 or 11:

#Print the string

print("This date is invalid")

#Otherwise

else:

#Print the string

print("This date is valid")

#Otherwise

else:

#Print the string

print("The date is valid.")

#Catch the exception

except ValueError:

#Handle the exception

print("Your input was not in the correct form.")

#Catch the exception

except:

#Handle the exception

print("Something went wrong!")

#Call the function

main()

Sample Output

Output:

Enter a date in the form MM/DD/YYYY: 02/30/2000

The date is valid.

>>>

Additional output:

Enter a date in the form MM/DD/YYYY: 02-05-2000

Your input was not in the correct form.

>>>

Additional output:

Enter a date in the form MM/DD/YYYY: 06/31/2000

This date is invalid

>>>

Answer 6

Expert Solution & Answer

Program Plan Intro

Validation of date input

Program plan:

Define the “leap_Year()” function,
- Check whether the year is not divisible by "4",
  - If the condition is “True”, return “False”.
  - Otherwise, check whether the year is divisible by "100",
    - If it is “True”, check whether the year is divisible by "400",
      - If it is “True”, return “True”.
      - Otherwise, return “False”.
    - Otherwise, return “True”.
Define the “main()” function,
- Execute the “try” statement to raise the exception if it is occurred.
  - Get the input from the user.
  - Split the user input based on "/" using “split()”.
  - Convert the string type inputs into integer type.
  - Check whether either the month is greater than “12” or day is greater than “12”,
    - If it is “True”, print the string “This date is invalid”
    - Otherwise, check whether the day is less than or equal to “28”,
      - If it is “True”, print the string as “This date is valid”.
      - Otherwise, check whether the month is "2" and "29",
      - If it is “True”, check whether the Boolean value return from “leap_Year()” is “False”.
        
        If it is “True”, print “This date is invalid”.
        
        Otherwise, print “This date is valid”.
        
        Otherwise, check whether the day is “31”,
        
        If it “True”, check whether the month is either "2" or "4" or "6" or "11",
        
        If the above condition is “True”, print invalid.
        
        Otherwise, print valid.
        
        Otherwise, print “This date is valid”.
      - Catch the exception using “except ValueError” statement, if the exception of type “ValueError” occurs.
    - Handle the exception.
  - Catch the exception using “except” statement, if any type of exception occurs.
- Call the function “main()”.

Program Description Answer

This Python program is to add decisions and exception handling as required making it truly robust.

Explanation of Solution

Program:

File name: “year.py”

#Define the function

def leap_Year(yr):

#Check whether the year is not divisible by "4"

if (yr % 4) != 0:

#Return the boolean value

return False

#Otherwise

else:

#Check whether the year is divisible by "100"

if (yr % 100) == 0:

#Check whether the year is divisible by "400"

if (yr % 400) ==0:

#Return boolean value

return True

#Otherwise

else:

#Return boolean value

return False

#Otherwise

else:

#Return boolean value

return True

#Define the function

def main():

#Make a try

try:

#Get the input from the user

date_Str = input("Enter a date in the form MM/DD/YYYY: ")

#Split the user input based on "/" using split()

month_Str, day_Str, year_Str = date_Str.split("/")

#Convert the string into integer

mon = int(month_Str)

#Convert the string into integer

d = int(day_Str)

#Convert the string into integer

yr = int(year_Str)

#Execute the condition

if mon > 12 or d > 31:

#Print the string

print("This date is invalid.")

#Otherwise

else:

#Check whether the day is less than or equal to 28

if d <= 28:

#Print the string

print("This date is valid.")

#Check whether the month is "2" and "29"

elif mon == 2 and d == 29:

#Check whether the boolean value return from "leap_Year()" is "False"

if leap_Year(yr) == False:

#Print the string

print("This date is invalid.")

#Otherwise

else:

#Print the string

print("This date is valid.")

#Check whether the day is "31"

elif d == 31:

'''Check whether the month is either "2" or "4" or "6" or "11"'''

if mon == 2 or 4 or 6 or 11:

#Print the string

print("This date is invalid")

#Otherwise

else:

#Print the string

print("This date is valid")

#Otherwise

else:

#Print the string

print("The date is valid.")

#Catch the exception

except ValueError:

#Handle the exception

print("Your input was not in the correct form.")

#Catch the exception

except:

#Handle the exception

print("Something went wrong!")

#Call the function

main()

Sample Output

Output:

Enter a date in the form MM/DD/YYYY: 02/30/2000

The date is valid.

>>>

Additional output:

Enter a date in the form MM/DD/YYYY: 02-05-2000

Your input was not in the correct form.

>>>

Additional output:

Enter a date in the form MM/DD/YYYY: 06/31/2000

This date is invalid

>>>

Answer 7

Expert Solution & Answer

Answer 8

Expert Solution & Answer

Answer 9

Program Plan Intro

Validation of date input

Program plan:

Define the “leap_Year()” function,
- Check whether the year is not divisible by "4",
  - If the condition is “True”, return “False”.
  - Otherwise, check whether the year is divisible by "100",
    - If it is “True”, check whether the year is divisible by "400",
      - If it is “True”, return “True”.
      - Otherwise, return “False”.
    - Otherwise, return “True”.
Define the “main()” function,
- Execute the “try” statement to raise the exception if it is occurred.
  - Get the input from the user.
  - Split the user input based on "/" using “split()”.
  - Convert the string type inputs into integer type.
  - Check whether either the month is greater than “12” or day is greater than “12”,
    - If it is “True”, print the string “This date is invalid”
    - Otherwise, check whether the day is less than or equal to “28”,
      - If it is “True”, print the string as “This date is valid”.
      - Otherwise, check whether the month is "2" and "29",
      - If it is “True”, check whether the Boolean value return from “leap_Year()” is “False”.
        
        If it is “True”, print “This date is invalid”.
        
        Otherwise, print “This date is valid”.
        
        Otherwise, check whether the day is “31”,
        
        If it “True”, check whether the month is either "2" or "4" or "6" or "11",
        
        If the above condition is “True”, print invalid.
        
        Otherwise, print valid.
        
        Otherwise, print “This date is valid”.
      - Catch the exception using “except ValueError” statement, if the exception of type “ValueError” occurs.
    - Handle the exception.
  - Catch the exception using “except” statement, if any type of exception occurs.
- Call the function “main()”.

Answer 10

Program Description Answer

This Python program is to add decisions and exception handling as required making it truly robust.

Answer 11

Explanation of Solution

Program:

File name: “year.py”

#Define the function

def leap_Year(yr):

#Check whether the year is not divisible by "4"

if (yr % 4) != 0:

#Return the boolean value

return False

#Otherwise

else:

#Check whether the year is divisible by "100"

if (yr % 100) == 0:

#Check whether the year is divisible by "400"

if (yr % 400) ==0:

#Return boolean value

return True

#Otherwise

else:

#Return boolean value

return False

#Otherwise

else:

#Return boolean value

return True

#Define the function

def main():

#Make a try

try:

#Get the input from the user

date_Str = input("Enter a date in the form MM/DD/YYYY: ")

#Split the user input based on "/" using split()

month_Str, day_Str, year_Str = date_Str.split("/")

#Convert the string into integer

mon = int(month_Str)

#Convert the string into integer

d = int(day_Str)

#Convert the string into integer

yr = int(year_Str)

#Execute the condition

if mon > 12 or d > 31:

#Print the string

print("This date is invalid.")

#Otherwise

else:

#Check whether the day is less than or equal to 28

if d <= 28:

#Print the string

print("This date is valid.")

#Check whether the month is "2" and "29"

elif mon == 2 and d == 29:

#Check whether the boolean value return from "leap_Year()" is "False"

if leap_Year(yr) == False:

#Print the string

print("This date is invalid.")

#Otherwise

else:

#Print the string

print("This date is valid.")

#Check whether the day is "31"

elif d == 31:

'''Check whether the month is either "2" or "4" or "6" or "11"'''

if mon == 2 or 4 or 6 or 11:

#Print the string

print("This date is invalid")

#Otherwise

else:

#Print the string

print("This date is valid")

#Otherwise

else:

#Print the string

print("The date is valid.")

#Catch the exception

except ValueError:

#Handle the exception

print("Your input was not in the correct form.")

#Catch the exception

except:

#Handle the exception

print("Something went wrong!")

#Call the function

main()

Answer 12

Sample Output

Output:

Enter a date in the form MM/DD/YYYY: 02/30/2000

The date is valid.

>>>

Additional output:

Enter a date in the form MM/DD/YYYY: 02-05-2000

Your input was not in the correct form.

>>>

Additional output:

Enter a date in the form MM/DD/YYYY: 06/31/2000

This date is invalid

>>>

Answer 13

Chapter 7, Problem 1TF Chapter 7, Problem 2TF Chapter 7, Problem 3TF Chapter 7, Problem 4TF Chapter 7, Problem 5TF Chapter 7, Problem 6TF Chapter 7, Problem 7TF Chapter 7, Problem 8TF Chapter 7, Problem 9TF Chapter 7, Problem 10TF

Chapter 7, Problem 18PE

Concept explainers

Explanation of Solution

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