Java: An Introduction to Problem Solving and Programming (7th Edition)
Java: An Introduction to Problem Solving and Programming (7th Edition)
7th Edition
ISBN: 9780133766264
Author: Walter Savitch
Publisher: PEARSON
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Chapter 7, Problem 15E

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Static method definition for selection sort:

The static method definition for selection is given below. This below complete Java program is used to sort an array of characters.

// Define "CharacterArrayTest" class

public class CharacterArrayTest

{

/* Method definition for sorting the array using selection sort */

    public static void selectionSort(Character[] arr)

    {

        /* Sort the array using "for" loop */

        for (int idx = 0; idx < arr.length - 1; idx++)

        {

/* Place the correct value in arr[index] by calling "findIndexOfSmallestChar" method */

int nextLowestIndex = findIndexOfSmallestChar(idx, arr);

            /* Call interChangeCharacter() method */

interChangeCharacter(idx, nextLowestIndex, arr);

        }

    }

/* Method definition for gets index of smallest element */

private static int findIndexOfSmallestChar(int beginIndex, Character[] a)

    {

        /* Assign minimum value */

        Character min = a[beginIndex];

        /* Assign index of minimum value */

        int minimumIndex = beginIndex;

/* Compute the index of minimum value using "for" loop */

for (int index = beginIndex + 1; index < a.length; index++)

        {

            if (a[index] < min)

            {

                min = a[index];

                minimumIndex = index;

            }

        }

        /* Return index of minimum element */

        return minimumIndex;

    }

/* Method definition for interChangeCharacter value of array */

private static void interChangeCharacter(int i, int j, Character[] a)

    {

        Character t = a[i];

        a[i] = a[j];

        a[j] = t;

    }

    //Define main function

    public static void main(String[] args)

    {

        //Initializes the values for "myArray"

Character[] myArray = {'b', 'd',...

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Given a relation schema R = (A, B, C, D, E,G) with a set of functional dependencies F {ABCD BC → DE B→ D D→ A}. (a) Show that R is not in BCNF using the functional dependency A → BCD. (b) Show that AG is a superkey for R (c) Compute a canonical cover Fc for the set of functional dependencies F. Show your work. (d) Give a 3NF decomposition of R based on the canonical cover found in (c). Show your work. (e) Give a BCNF decomposition of R using F. Show your work.

Chapter 7 Solutions

Java: An Introduction to Problem Solving and Programming (7th Edition)

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9.1: What is an Array? - Processing Tutorial; Author: The Coding Train;https://www.youtube.com/watch?v=NptnmWvkbTw;License: Standard Youtube License