LMS Integrated for MindTap Engineering, 2 terms (12 months) Printed Access Card for Moavni's Engineering Fundamentals: An Introduction to Engineering, 5th
LMS Integrated for MindTap Engineering, 2 terms (12 months) Printed Access Card for Moavni's Engineering Fundamentals: An Introduction to Engineering, 5th
5th Edition
ISBN: 9781305110366
Author: Saeed Moaveni
Publisher: Cengage Learning
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Concept explainers

Alloys
An alloy is an admixture of two or more metals or a metal and a non-metal. Since ancient times, man has been using alloys. Alloying helps to retain the properties of the parent matter, such as hardness, strength, toughness, ductility and is corrosion-res…
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Chapter 6, Problem 35P
To determine

Convert the strength of selected materials from MPa to ksi.

Expert Solution & Answer
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Answer to Problem 35P

The conversion for the strength of selected materials given in accompanying table from MPa to ksi as follows:

MaterialUltimate strength (MPa)Ultimate strength (ksi)
Aluminum alloys100−55014.5−79.7

Concrete

(compression)

10−70

1.4−10.1

Stee1  
Machine550−86079.7−124.7
Spring700−1,900101.5−275.5
Stainless400−1,00058.0−145.0
Tool900130.5
Structural Steel340−83049.3−120.3
Titanium alloys900−1,200130.5−174.0
Wood (Bending)  
Douglas fir50−807.2−11.6
Oak50−1007.2−14.5
Southern pine50−1007.2−14.5

Explanation of Solution

Given data:

Refer to Problem 6.35 in textbook for the accompanying table.

1 ksi=1000 lbfin.2 (1)

Formula used:

Convert N to lbf,

1 N=224.809×10−3 lbf

Convert meter to foot,

1 m=3.2808 ft

Convert foot to inches,

1 ft=12 in.

Calculation:

Rearrange the equation (1) for conversion of unit as follows,

1 lbfin.2=11000 ksi (2)

Case 1:

For Aluminum alloys:

Ultimate strength=100 MPa=100×106 Pa (3)

Substitute the unit Nm2 for Pa in equation (3).

Ultimate strength=100×106 Nm2 (4)

Substitute the units 224.809×10−3 lbf for 1 N and 3.2808 ft for 1 m in equation (4).

Ultimate strength=100×106 (224.809×10−3 lbf)(3.2808 ft)2=(100×106)(224.809×10−3)3.28082 lbfft2=2088594.746 lbfft2 (5)

Substitute the unit 12 in. for 1 ft in equation (5).

Ultimate strength=2088594.746 lbf(12 in.)2=2088594.746122 lbfin.2=14504.13 lbfin.2 (6)

Substitute the unit 11000 ksi for 1 lbfin.2 in equation (6).

Ultimate strength=14504.13×11000 ksi=14.5 ksi (7)

For Aluminum alloys:

Ultimate strength=550 MPa=550×106 Pa (8)

Substitute the unit Nm2 for Pa in equation (8).

Ultimate strength=550×106 Nm2 (9)

Substitute the units 224.809×10−3 lbf for 1 N and 3.2808 ft for 1 m in equation (9).

Ultimate strength=550×106 (224.809×10−3 lbf)(3.2808 ft)2=(550×106)(224.809×10−3)3.28082 lbfft2=11487271.1 lbfft2 (10)

Substitute the unit 12 in. for 1 ft in equation (10).

Ultimate strength=11487271.1 lbf(12 in.)2=11487271.1122 lbfin.2=79772.716 lbfin.2 (11)

Substitute the unit 11000 ksi for 1 lbfin.2 in equation (11).

Ultimate strength=79772.716×11000 ksi=79.7 ksi (12)

Case 2:

For Concrete (compression):

Ultimate strength=10 MPa=10×106 Pa (13)

Substitute the unit Nm2 for Pa in equation (13).

Ultimate strength=10×106 Nm2 (14)

Substitute the units 224.809×10−3 lbf for 1 N and 3.2808 ft for 1 m in equation (14).

Ultimate strength=10×106 (224.809×10−3 lbf)(3.2808 ft)2=(10×106)(224.809×10−3)3.28082 lbfft2=208859.475 lbfft2 (15)

Substitute the unit 12 in. for 1 ft in equation (15).

Ultimate strength=208859.475 lbf(12 in.)2=208859.475122 lbfin.2=1450.413 lbfin.2 (16)

Substitute the unit 11000 ksi for 1 lbfin.2 in equation (16).

Ultimate strength=1450.413×11000 ksi=1.4 ksi (17)

For Concrete (compression):

Ultimate strength=70 MPa=70×106 Pa (18)

Substitute the unit Nm2 for Pa in equation (18).

Ultimate strength=70×106 Nm2 (19)

Substitute the units 224.809×10−3 lbf for 1 N and 3.2808 ft for 1 m in equation (19).

Ultimate strength=70×106 (224.809×10−3 lbf)(3.2808 ft)2=(70×106)(224.809×10−3)3.28082 lbfft2=1462016.322 lbfft2 (20)

Substitute the unit 12 in. for 1 ft in equation (20).

Ultimate strength=1462016.322 lbf(12 in.)2=1462016.322122 lbfin.2=10152.89 lbfin.2 (21)

Substitute the unit 11000 ksi for 1 lbfin.2 in equation (21).

Ultimate strength=10152.89×11000 ksi=10.1 ksi (22)

Case 3:

For Steel-Machine:

Ultimate strength=550 MPa=550×106 Pa (23)

Substitute the unit Nm2 for Pa in equation (23).

Ultimate strength=550×106 Nm2 (24)

Substitute the units 224.809×10−3 lbf for 1 N and 3.2808 ft for 1 m in equation (24).

Ultimate strength=550×106 (224.809×10−3 lbf)(3.2808 ft)2=(550×106)(224.809×10−3)3.28082 lbfft2=11487271.1 lbfft2 (25)

Substitute the unit 12 in. for 1 ft in equation (25).

Ultimate strength=11487271.1 lbf(12 in.)2=11487271.1122 lbfin.2=79772.716 lbfin.2 (26)

Substitute the unit 11000 ksi for 1 lbfin.2 in equation (26).

Ultimate strength=79772.716×11000 ksi=79.7 ksi (27)

For Steel-Machine:

Ultimate strength=860 MPa=860×106 Pa (28)

Substitute the unit Nm2 for Pa in equation (28).

Ultimate strength=860×106 Nm2 (29)

Substitute the units 224.809×10−3 lbf for 1 N and 3.2808 ft for 1 m in equation (29).

Ultimate strength=860×106 (224.809×10−3 lbf)(3.2808 ft)2=(860×106)(224.809×10−3)3.28082 lbfft2=17961914.82 lbfft2 (30)

Substitute the unit 12 in. for 1 ft in equation (30).

Ultimate strength=17961914.82 lbf(12 in.)2=17961914.82122 lbfin.2=124735.519 lbfin.2 (31)

Substitute the unit 11000 ksi for 1 lbfin.2 in equation (31).

Ultimate strength=124735.519×11000 ksi=124.7 ksi (32)

For Steel-Spring:

Ultimate strength=700 MPa=700×106 Pa (33)

Substitute the unit Nm2 for Pa in equation (33).

Ultimate strength=700×106 Nm2 (34)

Substitute the units 224.809×10−3 lbf for 1 N and 3.2808 ft for 1 m in equation (34).

Ultimate strength=700×106 (224.809×10−3 lbf)(3.2808 ft)2=(700×106)(224.809×10−3)3.28082 lbfft2=14620163.22 lbfft2 (35)

Substitute the unit 12 in. for 1 ft in equation (35).

Ultimate strength=14620163.22 lbf(12 in.)2=14620163.22122 lbfin.2=101528.9113 lbfin.2 (36)

Substitute the unit 11000 ksi for 1 lbfin.2 in equation (36).

Ultimate strength=101528.9113×11000 ksi=101.5 ksi (37)

For Steel-Spring:

Ultimate strength=1900 MPa=1900×106 Pa (38)

Substitute the unit Nm2 for Pa in equation (38).

Ultimate strength=1900×106 Nm2 (39)

Substitute the units 224.809×10−3 lbf for 1 N and 3.2808 ft for 1 m in equation (39).

Ultimate strength=1900×106 (224.809×10−3 lbf)(3.2808 ft)2=(1900×106)(224.809×10−3)3.28082 lbfft2=39683300.18 lbfft2 (40)

Substitute the unit 12 in. for 1 ft in equation (40).

Ultimate strength=39683300.18 lbf(12 in.)2=39683300.18122 lbfin.2=275578.474 lbfin.2 (41)

Substitute the unit 11000 ksi for 1 lbfin.2 in equation (41).

Ultimate strength=275578.474×11000 ksi=275.5 ksi (42)

For Steel-Stainless:

Ultimate strength=400 MPa=400×106 Pa (43)

Substitute the unit Nm2 for Pa in equation (43).

Ultimate strength=400×106 Nm2 (44)

Substitute the units 224.809×10−3 lbf for 1 N and 3.2808 ft for 1 m in equation (44).

Ultimate strength=400×106 (224.809×10−3 lbf)(3.2808 ft)2=(400×106)(224.809×10−3)3.28082 lbfft2=8354378.985 lbfft2 (45)

Substitute the unit 12 in. for 1 ft in equation (45).

Ultimate strength=8354378.985 lbf(12 in.)2=8354378.985122 lbfin.2=58016.521 lbfin.2 (46)

Substitute the unit 11000 ksi for 1 lbfin.2 in equation (46).

Ultimate strength=58016.521×11000 ksi=58.0 ksi (47)

For Steel-Stainless:

Ultimate strength=1000 MPa=1000×106 Pa (48)

Substitute the unit Nm2 for Pa in equation (48).

Ultimate strength=1000×106 Nm2 (49)

Substitute the units 224.809×10−3 lbf for 1 N and 3.2808 ft for 1 m in equation (49).

Ultimate strength=1000×106 (224.809×10−3 lbf)(3.2808 ft)2=(1000×106)(224.809×10−3)3.28082 lbfft2=20885947.46 lbfft2 (50)

Substitute the unit 12 in. for 1 ft in equation (50).

Ultimate strength=20885947.46 lbf(12 in.)2=20885947.46122 lbfin.2=145041.302 lbfin.2 (51)

Substitute the unit 11000 ksi for 1 lbfin.2 in equation (51).

Ultimate strength=145041.302×11000 ksi=145.0 ksi (52)

For Steel-Tool:

Ultimate strength=900 MPa=900×106 Pa (53)

Substitute the unit Nm2 for Pa in equation (53).

Ultimate strength=900×106 Nm2 (54)

Substitute the units 224.809×10−3 lbf for 1 N and 3.2808 ft for 1 m in equation (54).

Ultimate strength=900×106 (224.809×10−3 lbf)(3.2808 ft)2=(900×106)(224.809×10−3)3.28082 lbfft2=18797352.72 lbfft2 (55)

Substitute the unit 12 in. for 1 ft in equation (55).

Ultimate strength=18797352.72 lbf(12 in.)2=18797352.72122 lbfin.2=130537.172 lbfin.2 (56)

Substitute the unit 11000 ksi for 1 lbfin.2 in equation (56).

Ultimate strength=130537.172×11000 ksi=130.5 ksi (57)

For Steel-Structural Steel:

Ultimate strength=340 MPa=340×106 Pa (58)

Substitute the unit Nm2 for Pa in equation (58).

Ultimate strength=340×106 Nm2 (59)

Substitute the units 224.809×10−3 lbf for 1 N and 3.2808 ft for 1 m in equation (59).

Ultimate strength=340×106 (224.809×10−3 lbf)(3.2808 ft)2=(340×106)(224.809×10−3)3.28082 lbfft2=7101222.137 lbfft2 (60)

Substitute the unit 12 in. for 1 ft in equation (60).

Ultimate strength=7101222.137 lbf(12 in.)2=7101222.137122 lbfin.2=49314.043 lbfin.2 (61)

Substitute the unit 11000 ksi for 1 lbfin.2 in equation (61).

Ultimate strength=49314.043×11000 ksi=49.3 ksi (62)

For Steel-Structural Steel:

Ultimate strength=830 MPa=830×106 Pa (63)

Substitute the unit Nm2 for Pa in equation (63).

Ultimate strength=830×106 Nm2 (64)

Substitute the units 224.809×10−3 lbf for 1 N and 3.2808 ft for 1 m in equation (64).

Ultimate strength=830×106 (224.809×10−3 lbf)(3.2808 ft)2=(830×106)(224.809×10−3)3.28082 lbfft2=17335336.39 lbfft2 (65)

Substitute the unit 12 in. for 1 ft in equation (65).

Ultimate strength=17335336.39 lbf(12 in.)2=17335336.39122 lbfin.2=120384.281 lbfin.2 (66)

Substitute the unit 11000 ksi for 1 lbfin.2 in equation (66).

Ultimate strength=120384.281×11000 ksi=120.3 ksi (67)

For Steel-Titanium alloys:

Ultimate strength=900 MPa=900×106 Pa (68)

Substitute the unit Nm2 for Pa in equation (68).

Ultimate strength=900×106 Nm2 (69)

Substitute the units 224.809×10−3 lbf for 1 N and 3.2808 ft for 1 m in equation (69).

Ultimate strength=900×106 (224.809×10−3 lbf)(3.2808 ft)2=(900×106)(224.809×10−3)3.28082 lbfft2=18797352.72 lbfft2 (70)

Substitute the unit 12 in. for 1 ft in equation (70).

Ultimate strength=18797352.72 lbf(12 in.)2=18797352.72122 lbfin.2=130537.172 lbfin.2 (71)

Substitute the unit 11000 ksi for 1 lbfin.2 in equation (71).

Ultimate strength=130537.172×11000 ksi=130.5 ksi (72)

For Steel-Titanium alloys:

Ultimate strength=1200 MPa=1200×106 Pa (73)

Substitute the unit Nm2 for Pa in equation (73).

Ultimate strength=1200×106 Nm2 (74)

Substitute the units 224.809×10−3 lbf for 1 N and 3.2808 ft for 1 m in equation (74).

Ultimate strength=1200×106 (224.809×10−3 lbf)(3.2808 ft)2=(1200×106)(224.809×10−3)3.28082 lbfft2=25063136.96 lbfft2 (75)

Substitute the unit 12 in. for 1 ft in equation (75).

Ultimate strength=25063136.96 lbf(12 in.)2=25063136.96122 lbfin.2=174049.562 lbfin.2 (76)

Substitute the unit 11000 ksi for 1 lbfin.2 in equation (76).

Ultimate strength=174049.562×11000 ksi=174.0 ksi (77)

Case 4:

For Wood (Bending)-Douglas fir:

Ultimate strength=50 MPa=50×106 Pa (78)

Substitute the unit Nm2 for Pa in equation (78).

Ultimate strength=50×106 Nm2 (79)

Substitute the units 224.809×10−3 lbf for 1 N and 3.2808 ft for 1 m in equation (79).

Ultimate strength=50×106 (224.809×10−3 lbf)(3.2808 ft)2=(50×106)(224.809×10−3)3.28082 lbfft2=1044297.373 lbfft2 (80)

Substitute the unit 12 in. for 1 ft in equation (80).

Ultimate strength=1044297.373 lbf(12 in.)2=1044297.373122 lbfin.2=7252.065 lbfin.2 (81)

Substitute the unit 11000 ksi for 1 lbfin.2 in equation (81).

Ultimate strength=7252.065×11000 ksi=7.2 ksi (82)

For Wood (Bending)-Douglas fir:

Ultimate strength=80 MPa=80×106 Pa (83)

Substitute the unit Nm2 for Pa in equation (83).

Ultimate strength=80×106 Nm2 (84)

Substitute the units 224.809×10−3 lbf for 1 N and 3.2808 ft for 1 m in equation (84).

Ultimate strength=80×106 (224.809×10−3 lbf)(3.2808 ft)2=(80×106)(224.809×10−3)3.28082 lbfft2=1670875.797 lbfft2 (85)

Substitute the unit 12 in. for 1 ft in equation (85).

Ultimate strength=1670875.797 lbf(12 in.)2=1670875.797122 lbfin.2=11603.304 lbfin.2 (86)

Substitute the unit 11000 ksi for 1 lbfin.2 in equation (86).

Ultimate strength=11603.304×11000 ksi=11.6 ksi (87)

For Wood (Bending)-Oak:

Ultimate strength=50 MPa=50×106 Pa (88)

Substitute the unit Nm2 for Pa in equation (88).

Ultimate strength=50×106 Nm2 (89)

Substitute the units 224.809×10−3 lbf for 1 N and 3.2808 ft for 1 m in equation (89).

Ultimate strength=50×106 (224.809×10−3 lbf)(3.2808 ft)2=(50×106)(224.809×10−3)3.28082 lbfft2=1044297.373 lbfft2 (90)

Substitute the unit 12 in. for 1 ft in equation (90).

Ultimate strength=1044297.373 lbf(12 in.)2=1044297.373122 lbfin.2=7252.065 lbfin.2 (91)

Substitute the unit 11000 ksi for 1 lbfin.2 in equation (91).

Ultimate strength=7252.065×11000 ksi=7.2 ksi (92)

For Wood (Bending)-Oak:

Ultimate strength=100 MPa=100×106 Pa (93)

Substitute the unit Nm2 for Pa in equation (93).

Ultimate strength=100×106 Nm2 (94)

Substitute the units 224.809×10−3 lbf for 1 N and 3.2808 ft for 1 m in equation (94).

Ultimate strength=100×106 (224.809×10−3 lbf)(3.2808 ft)2=(100×106)(224.809×10−3)3.28082 lbfft2=2088594.746 lbfft2 (95)

Substitute the unit 12 in. for 1 ft in equation (95).

Ultimate strength=2088594.746 lbf(12 in.)2=2088594.746122 lbfin.2=14504.13 lbfin.2 (96)

Substitute the unit 11000 ksi for 1 lbfin.2 in equation (96).

Ultimate strength=14504.13×11000 ksi=14.5 ksi (97)

For Wood (Bending)-Southern pine:

Ultimate strength=50 MPa=50×106 Pa (98)

Substitute the unit Nm2 for Pa in equation (98).

Ultimate strength=50×106 Nm2 (99)

Substitute the units 224.809×10−3 lbf for 1 N and 3.2808 ft for 1 m in equation (99).

Ultimate strength=50×106 (224.809×10−3 lbf)(3.2808 ft)2=(50×106)(224.809×10−3)3.28082 lbfft2=1044297.373 lbfft2 (100)

Substitute the unit 12 in. for 1 ft in equation (100).

Ultimate strength=1044297.373 lbf(12 in.)2=1044297.373122 lbfin.2=7252.065 lbfin.2 (101)

Substitute the unit 11000 ksi for 1 lbfin.2 in equation (101).

Ultimate strength=7252.065×11000 ksi=7.2 ksi (102)

For Wood (Bending)-Southern pine;

Ultimate strength=100 MPa=100×106 Pa (103)

Substitute the unit Nm2 for Pa in equation (103).

Ultimate strength=100×106 Nm2 (104)

Substitute the units 224.809×10−3 lbf for 1 N and 3.2808 ft for 1 m in equation (104).

Ultimate strength=100×106 (224.809×10−3 lbf)(3.2808 ft)2=(100×106)(224.809×10−3)3.28082 lbfft2=2088594.746 lbfft2 (105)

Substitute the unit 12 in. for 1 ft in equation (105).

Ultimate strength=2088594.746 lbf(12 in.)2=2088594.746122 lbfin.2=14504.13 lbfin.2 (106)

Substitute the unit 11000 ksi for 1 lbfin.2 in equation (106).

Ultimate strength=14504.13×11000 ksi=14.5 ksi (107)

Thus, the conversion for the strength of selected materials from MPa to ksi is tabulated in Table 1.

Table 1

MaterialUltimate strength (MPa)Ultimate strength (ksi)
Aluminum alloys100−55014.5−79.7

Concrete

(compression)

10−70

1.4−10.1

Stee1  
Machine550−86079.7−124.7
Spring700−1,900101.5−275.5
Stainless400−1,00058.0−145.0
Tool900130.5
Structural Steel340−83049.3−120.3
Titanium alloys900−1,200130.5−174.0
Wood (Bending)  
Douglas fir50−807.2−11.6
Oak50−1007.2−14.5
Southern pine50−1007.2−14.5

Conclusion:

Hence, the conversion for the strength of selected materials from MPa to ksi has been explained.

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Chapter 6 Solutions

LMS Integrated for MindTap Engineering, 2 terms (12 months) Printed Access Card for Moavni's Engineering Fundamentals: An Introduction to Engineering, 5th

Ch. 6.1 - Prob. 1BYGCh. 6.1 - Prob. 2BYGCh. 6.1 - Prob. 3BYGCh. 6.1 - Prob. 4BYGCh. 6.1 - Prob. BYGVCh. 6.2 - Prob. 1BYGCh. 6.2 - Prob. 2BYGCh. 6.2 - Prob. 3BYGCh. 6.2 - Prob. 4BYGCh. 6.2 - Prob. 5BYG
Ch. 6.2 - Prob. 6BYGCh. 6.2 - Prob. BYGVCh. 6.3 - Prob. 1BYGCh. 6.3 - Prob. 2BYGCh. 6.3 - Prob. 3BYGCh. 6.3 - Prob. 4BYGCh. 6.3 - Prob. BYGVCh. 6.5 - Prob. 1BYGCh. 6.5 - Prob. 2BYGCh. 6.5 - Prob. 3BYGCh. 6.5 - Prob. 4BYGCh. 6.5 - Prob. BYGVCh. 6.6 - Prob. 1BYGCh. 6.6 - Prob. 2BYGCh. 6.6 - Prob. 3BYGCh. 6.6 - Prob. BYGVCh. 6 - Prob. 1PCh. 6 - Prob. 2PCh. 6 - Prob. 3PCh. 6 - Prob. 4PCh. 6 - Prob. 5PCh. 6 - Prob. 6PCh. 6 - Prob. 7PCh. 6 - Prob. 8PCh. 6 - Prob. 9PCh. 6 - Prob. 10PCh. 6 - Prob. 11PCh. 6 - Prob. 12PCh. 6 - Prob. 13PCh. 6 - Prob. 14PCh. 6 - Prob. 15PCh. 6 - Prob. 16PCh. 6 - Prob. 17PCh. 6 - Prob. 18PCh. 6 - Prob. 19PCh. 6 - Prob. 20PCh. 6 - Prob. 21PCh. 6 - Prob. 22PCh. 6 - Prob. 23PCh. 6 - The air resistance to the motion of a vehicle is...Ch. 6 - Prob. 25PCh. 6 - Prob. 26PCh. 6 - Prob. 27PCh. 6 - Prob. 28PCh. 6 - Prob. 29PCh. 6 - Prob. 30PCh. 6 - Prob. 31PCh. 6 - Prob. 32PCh. 6 - Prob. 33PCh. 6 - The calorie is defined as the amount of heat...Ch. 6 - Prob. 35PCh. 6 - Prob. 36PCh. 6 - Prob. 37PCh. 6 - Prob. 38PCh. 6 - Prob. 39PCh. 6 - Prob. 40PCh. 6 - For the fin equation described in Problem 6.25, if...Ch. 6 - Prob. 42PCh. 6 - Prob. 43PCh. 6 - Prob. 44PCh. 6 - Prob. 45PCh. 6 - Prob. 46PCh. 6 - Prob. 47PCh. 6 - Prob. 48PCh. 6 - Prob. 49PCh. 6 - Prob. 50PCh. 6 - Prob. 51P
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