Solve the following exercises based on Principles 11-14, although an exercise may require the application of two or more of any of the principles. Round the answers to 3 decimal places where necessary unless otherwise stated. a. If A B = 5.378 " and A C = 3.782 " , find (1) DB (2) A C B . ⌢ b If D B = 3.017 " and A C B ⌢ = 7.308 " , find (1) AB (2) C B . ⌢

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Answer 1

Textbook Question

Chapter 55, Problem 20A

Solve the following exercises based on Principles 11-14, although an exercise may require the application of two or more of any of the principles. Round the answers to 3 decimal places where necessary unless otherwise stated.
a. If A B = 5.378 " and A C = 3.782 " , find (1) DB (2) A C B . ⌢

b If D B = 3.017 " and A C B ⌢ = 7.308 " , find (1) AB (2) C B . ⌢

Chapter 55, Problem 20A, Solve the following exercises based on Principles 11-14, although an exercise may require the

Expert Solution

To determine

(a)

The value of DB and arc ACB⌢.

Answer to Problem 20A

The value of DB is DB=2.689.

Explanation of Solution

Given information:

AB = 5.378"

AC⌢=3.782"

Mathematics For Machine Technology, Chapter 55, Problem 20A , additional homework tip 1

If the radius of the circle is perpendicular to the chord, it always divides the chord in two equal parts.

In the figure given above, the radius is perpendicular to the chord; hence, the parts AD will be equal to DB. Each portion AD and DB is half the value of part AB.

AD=DB=AB2

DB=AB2=5.3782=2.689DB=2.689

The value of DB is DB=2.689

If the radius of the circle is perpendicular to the chord, it always divides the chord and the arc cut off by the chord in two equal parts.

In the figure given above, the radius is perpendicular to the chord; hence, the parts AD will be equal to DB. Each portion AD and DB is half the value of part AB. Also, the arc cut off by the chord is divided in two equal parts.

AC⌢=CB⌢=ACB⌢2

AC⌢=CB⌢= ACB⌢2AC⌢=3.782"ACB⌢=2×3.782"=7.564"ACB⌢=7.564"

The value of DB is DB=2.689 and the value of arc is ACB⌢=7.564".

Conclusion:

Thus, the value of DB is DB=2.689 and the value of arc is ACB⌢=7.564".

Expert Solution

To determine

(b)

The value of AB and arc CB⌢.

Answer to Problem 20A

The value of AB is AB=6.034" and the value of arc is CB⌢=3.654".

Explanation of Solution

Given information:

AB = 3.017"

ACB⌢=7.308"

Mathematics For Machine Technology, Chapter 55, Problem 20A , additional homework tip 2

If the radius of the circle is perpendicular to the chord, it always divides the chord in two equal parts.

In the figure given above, the radius is perpendicular to the chord; hence, the parts AD will be equal to DB. Each portion AD and DB is half the value of part AB.

AD=DB=AB2

AB=2×DBAB=2×3.017"AB=6.034"

The value of AB is AB=6.034"

If the radius of the circle is perpendicular to the chord, it always divides the chord and the arc cut off by the chord in two equal parts.

In the figure given above, the radius is perpendicular to the chord; hence, the parts AD will be equal to DB. Each portion AD and DB is half the value of part AB. Also, the arc cut off by the chord is divided in two equal parts.

AC⌢=CB⌢=ACB⌢2

AC⌢=CB⌢= ACB⌢2ACB⌢=7.308"CB⌢=7.308"2CB⌢=3.654"

The value of AB is AB=6.034" and the value of arc is CB⌢=3.654"

Conclusion:

Thus, the value of AB is AB=6.034" and the value of arc is CB⌢=3.654".

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Answer 2

Textbook Question

Chapter 55, Problem 20A

Solve the following exercises based on Principles 11-14, although an exercise may require the application of two or more of any of the principles. Round the answers to 3 decimal places where necessary unless otherwise stated.
a. If A B = 5.378 " and A C = 3.782 " , find (1) DB (2) A C B . ⌢

b If D B = 3.017 " and A C B ⌢ = 7.308 " , find (1) AB (2) C B . ⌢

Chapter 55, Problem 20A, Solve the following exercises based on Principles 11-14, although an exercise may require the

Expert Solution

To determine

(a)

The value of DB and arc ACB⌢.

Answer to Problem 20A

The value of DB is DB=2.689.

Explanation of Solution

Given information:

AB = 5.378"

AC⌢=3.782"

Mathematics For Machine Technology, Chapter 55, Problem 20A , additional homework tip 1

If the radius of the circle is perpendicular to the chord, it always divides the chord in two equal parts.

In the figure given above, the radius is perpendicular to the chord; hence, the parts AD will be equal to DB. Each portion AD and DB is half the value of part AB.

AD=DB=AB2

DB=AB2=5.3782=2.689DB=2.689

The value of DB is DB=2.689

If the radius of the circle is perpendicular to the chord, it always divides the chord and the arc cut off by the chord in two equal parts.

In the figure given above, the radius is perpendicular to the chord; hence, the parts AD will be equal to DB. Each portion AD and DB is half the value of part AB. Also, the arc cut off by the chord is divided in two equal parts.

AC⌢=CB⌢=ACB⌢2

AC⌢=CB⌢= ACB⌢2AC⌢=3.782"ACB⌢=2×3.782"=7.564"ACB⌢=7.564"

The value of DB is DB=2.689 and the value of arc is ACB⌢=7.564".

Conclusion:

Thus, the value of DB is DB=2.689 and the value of arc is ACB⌢=7.564".

Expert Solution

To determine

(b)

The value of AB and arc CB⌢.

Answer to Problem 20A

The value of AB is AB=6.034" and the value of arc is CB⌢=3.654".

Explanation of Solution

Given information:

AB = 3.017"

ACB⌢=7.308"

Mathematics For Machine Technology, Chapter 55, Problem 20A , additional homework tip 2

If the radius of the circle is perpendicular to the chord, it always divides the chord in two equal parts.

In the figure given above, the radius is perpendicular to the chord; hence, the parts AD will be equal to DB. Each portion AD and DB is half the value of part AB.

AD=DB=AB2

AB=2×DBAB=2×3.017"AB=6.034"

The value of AB is AB=6.034"

If the radius of the circle is perpendicular to the chord, it always divides the chord and the arc cut off by the chord in two equal parts.

In the figure given above, the radius is perpendicular to the chord; hence, the parts AD will be equal to DB. Each portion AD and DB is half the value of part AB. Also, the arc cut off by the chord is divided in two equal parts.

AC⌢=CB⌢=ACB⌢2

AC⌢=CB⌢= ACB⌢2ACB⌢=7.308"CB⌢=7.308"2CB⌢=3.654"

The value of AB is AB=6.034" and the value of arc is CB⌢=3.654"

Conclusion:

Thus, the value of AB is AB=6.034" and the value of arc is CB⌢=3.654".

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Answer 3

Textbook Question

Chapter 55, Problem 20A

Solve the following exercises based on Principles 11-14, although an exercise may require the application of two or more of any of the principles. Round the answers to 3 decimal places where necessary unless otherwise stated.
a. If A B = 5.378 " and A C = 3.782 " , find (1) DB (2) A C B . ⌢

b If D B = 3.017 " and A C B ⌢ = 7.308 " , find (1) AB (2) C B . ⌢

Chapter 55, Problem 20A, Solve the following exercises based on Principles 11-14, although an exercise may require the

Expert Solution

To determine

(a)

The value of DB and arc ACB⌢.

Answer to Problem 20A

The value of DB is DB=2.689.

Explanation of Solution

Given information:

AB = 5.378"

AC⌢=3.782"

Mathematics For Machine Technology, Chapter 55, Problem 20A , additional homework tip 1

If the radius of the circle is perpendicular to the chord, it always divides the chord in two equal parts.

In the figure given above, the radius is perpendicular to the chord; hence, the parts AD will be equal to DB. Each portion AD and DB is half the value of part AB.

AD=DB=AB2

DB=AB2=5.3782=2.689DB=2.689

The value of DB is DB=2.689

If the radius of the circle is perpendicular to the chord, it always divides the chord and the arc cut off by the chord in two equal parts.

In the figure given above, the radius is perpendicular to the chord; hence, the parts AD will be equal to DB. Each portion AD and DB is half the value of part AB. Also, the arc cut off by the chord is divided in two equal parts.

AC⌢=CB⌢=ACB⌢2

AC⌢=CB⌢= ACB⌢2AC⌢=3.782"ACB⌢=2×3.782"=7.564"ACB⌢=7.564"

The value of DB is DB=2.689 and the value of arc is ACB⌢=7.564".

Conclusion:

Thus, the value of DB is DB=2.689 and the value of arc is ACB⌢=7.564".

Expert Solution

To determine

(b)

The value of AB and arc CB⌢.

Answer to Problem 20A

The value of AB is AB=6.034" and the value of arc is CB⌢=3.654".

Explanation of Solution

Given information:

AB = 3.017"

ACB⌢=7.308"

Mathematics For Machine Technology, Chapter 55, Problem 20A , additional homework tip 2

If the radius of the circle is perpendicular to the chord, it always divides the chord in two equal parts.

In the figure given above, the radius is perpendicular to the chord; hence, the parts AD will be equal to DB. Each portion AD and DB is half the value of part AB.

AD=DB=AB2

AB=2×DBAB=2×3.017"AB=6.034"

The value of AB is AB=6.034"

If the radius of the circle is perpendicular to the chord, it always divides the chord and the arc cut off by the chord in two equal parts.

In the figure given above, the radius is perpendicular to the chord; hence, the parts AD will be equal to DB. Each portion AD and DB is half the value of part AB. Also, the arc cut off by the chord is divided in two equal parts.

AC⌢=CB⌢=ACB⌢2

AC⌢=CB⌢= ACB⌢2ACB⌢=7.308"CB⌢=7.308"2CB⌢=3.654"

The value of AB is AB=6.034" and the value of arc is CB⌢=3.654"

Conclusion:

Thus, the value of AB is AB=6.034" and the value of arc is CB⌢=3.654".

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Answer 4

Textbook Question

Chapter 55, Problem 20A

Solve the following exercises based on Principles 11-14, although an exercise may require the application of two or more of any of the principles. Round the answers to 3 decimal places where necessary unless otherwise stated.
a. If A B = 5.378 " and A C = 3.782 " , find (1) DB (2) A C B . ⌢

b If D B = 3.017 " and A C B ⌢ = 7.308 " , find (1) AB (2) C B . ⌢

Chapter 55, Problem 20A, Solve the following exercises based on Principles 11-14, although an exercise may require the

Expert Solution

To determine

(a)

The value of DB and arc ACB⌢.

Answer to Problem 20A

The value of DB is DB=2.689.

Explanation of Solution

Given information:

AB = 5.378"

AC⌢=3.782"

Mathematics For Machine Technology, Chapter 55, Problem 20A , additional homework tip 1

If the radius of the circle is perpendicular to the chord, it always divides the chord in two equal parts.

In the figure given above, the radius is perpendicular to the chord; hence, the parts AD will be equal to DB. Each portion AD and DB is half the value of part AB.

AD=DB=AB2

DB=AB2=5.3782=2.689DB=2.689

The value of DB is DB=2.689

If the radius of the circle is perpendicular to the chord, it always divides the chord and the arc cut off by the chord in two equal parts.

In the figure given above, the radius is perpendicular to the chord; hence, the parts AD will be equal to DB. Each portion AD and DB is half the value of part AB. Also, the arc cut off by the chord is divided in two equal parts.

AC⌢=CB⌢=ACB⌢2

AC⌢=CB⌢= ACB⌢2AC⌢=3.782"ACB⌢=2×3.782"=7.564"ACB⌢=7.564"

The value of DB is DB=2.689 and the value of arc is ACB⌢=7.564".

Conclusion:

Thus, the value of DB is DB=2.689 and the value of arc is ACB⌢=7.564".

Expert Solution

To determine

(b)

The value of AB and arc CB⌢.

Answer to Problem 20A

The value of AB is AB=6.034" and the value of arc is CB⌢=3.654".

Explanation of Solution

Given information:

AB = 3.017"

ACB⌢=7.308"

Mathematics For Machine Technology, Chapter 55, Problem 20A , additional homework tip 2

If the radius of the circle is perpendicular to the chord, it always divides the chord in two equal parts.

In the figure given above, the radius is perpendicular to the chord; hence, the parts AD will be equal to DB. Each portion AD and DB is half the value of part AB.

AD=DB=AB2

AB=2×DBAB=2×3.017"AB=6.034"

The value of AB is AB=6.034"

If the radius of the circle is perpendicular to the chord, it always divides the chord and the arc cut off by the chord in two equal parts.

In the figure given above, the radius is perpendicular to the chord; hence, the parts AD will be equal to DB. Each portion AD and DB is half the value of part AB. Also, the arc cut off by the chord is divided in two equal parts.

AC⌢=CB⌢=ACB⌢2

AC⌢=CB⌢= ACB⌢2ACB⌢=7.308"CB⌢=7.308"2CB⌢=3.654"

The value of AB is AB=6.034" and the value of arc is CB⌢=3.654"

Conclusion:

Thus, the value of AB is AB=6.034" and the value of arc is CB⌢=3.654".

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

Expert Solution

To determine

(a)

The value of DB and arc ACB⌢.

Answer to Problem 20A

The value of DB is DB=2.689.

Explanation of Solution

Given information:

AB = 5.378"

AC⌢=3.782"

Mathematics For Machine Technology, Chapter 55, Problem 20A , additional homework tip 1

If the radius of the circle is perpendicular to the chord, it always divides the chord in two equal parts.

In the figure given above, the radius is perpendicular to the chord; hence, the parts AD will be equal to DB. Each portion AD and DB is half the value of part AB.

AD=DB=AB2

DB=AB2=5.3782=2.689DB=2.689

The value of DB is DB=2.689

If the radius of the circle is perpendicular to the chord, it always divides the chord and the arc cut off by the chord in two equal parts.

In the figure given above, the radius is perpendicular to the chord; hence, the parts AD will be equal to DB. Each portion AD and DB is half the value of part AB. Also, the arc cut off by the chord is divided in two equal parts.

AC⌢=CB⌢=ACB⌢2

AC⌢=CB⌢= ACB⌢2AC⌢=3.782"ACB⌢=2×3.782"=7.564"ACB⌢=7.564"

The value of DB is DB=2.689 and the value of arc is ACB⌢=7.564".

Conclusion:

Thus, the value of DB is DB=2.689 and the value of arc is ACB⌢=7.564".

Expert Solution

To determine

(b)

The value of AB and arc CB⌢.

Answer to Problem 20A

The value of AB is AB=6.034" and the value of arc is CB⌢=3.654".

Explanation of Solution

Given information:

AB = 3.017"

ACB⌢=7.308"

Mathematics For Machine Technology, Chapter 55, Problem 20A , additional homework tip 2

If the radius of the circle is perpendicular to the chord, it always divides the chord in two equal parts.

In the figure given above, the radius is perpendicular to the chord; hence, the parts AD will be equal to DB. Each portion AD and DB is half the value of part AB.

AD=DB=AB2

AB=2×DBAB=2×3.017"AB=6.034"

The value of AB is AB=6.034"

If the radius of the circle is perpendicular to the chord, it always divides the chord and the arc cut off by the chord in two equal parts.

In the figure given above, the radius is perpendicular to the chord; hence, the parts AD will be equal to DB. Each portion AD and DB is half the value of part AB. Also, the arc cut off by the chord is divided in two equal parts.

AC⌢=CB⌢=ACB⌢2

AC⌢=CB⌢= ACB⌢2ACB⌢=7.308"CB⌢=7.308"2CB⌢=3.654"

The value of AB is AB=6.034" and the value of arc is CB⌢=3.654"

Conclusion:

Thus, the value of AB is AB=6.034" and the value of arc is CB⌢=3.654".

Answer 8

Expert Solution

To determine

(a)

The value of DB and arc ACB⌢.

Answer to Problem 20A

The value of DB is DB=2.689.

Explanation of Solution

Given information:

AB = 5.378"

AC⌢=3.782"

Mathematics For Machine Technology, Chapter 55, Problem 20A , additional homework tip 1

If the radius of the circle is perpendicular to the chord, it always divides the chord in two equal parts.

In the figure given above, the radius is perpendicular to the chord; hence, the parts AD will be equal to DB. Each portion AD and DB is half the value of part AB.

AD=DB=AB2

DB=AB2=5.3782=2.689DB=2.689

The value of DB is DB=2.689

If the radius of the circle is perpendicular to the chord, it always divides the chord and the arc cut off by the chord in two equal parts.

In the figure given above, the radius is perpendicular to the chord; hence, the parts AD will be equal to DB. Each portion AD and DB is half the value of part AB. Also, the arc cut off by the chord is divided in two equal parts.

AC⌢=CB⌢=ACB⌢2

AC⌢=CB⌢= ACB⌢2AC⌢=3.782"ACB⌢=2×3.782"=7.564"ACB⌢=7.564"

The value of DB is DB=2.689 and the value of arc is ACB⌢=7.564".

Conclusion:

Thus, the value of DB is DB=2.689 and the value of arc is ACB⌢=7.564".

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

To determine

(a)

The value of DB and arc ACB⌢.

Answer 13

Answer to Problem 20A

The value of DB is DB=2.689.

Answer 14

Explanation of Solution

Given information:

AB = 5.378"

AC⌢=3.782"

Mathematics For Machine Technology, Chapter 55, Problem 20A , additional homework tip 1

If the radius of the circle is perpendicular to the chord, it always divides the chord in two equal parts.

In the figure given above, the radius is perpendicular to the chord; hence, the parts AD will be equal to DB. Each portion AD and DB is half the value of part AB.

AD=DB=AB2

DB=AB2=5.3782=2.689DB=2.689

The value of DB is DB=2.689

If the radius of the circle is perpendicular to the chord, it always divides the chord and the arc cut off by the chord in two equal parts.

In the figure given above, the radius is perpendicular to the chord; hence, the parts AD will be equal to DB. Each portion AD and DB is half the value of part AB. Also, the arc cut off by the chord is divided in two equal parts.

AC⌢=CB⌢=ACB⌢2

AC⌢=CB⌢= ACB⌢2AC⌢=3.782"ACB⌢=2×3.782"=7.564"ACB⌢=7.564"

The value of DB is DB=2.689 and the value of arc is ACB⌢=7.564".

Conclusion:

Thus, the value of DB is DB=2.689 and the value of arc is ACB⌢=7.564".

Answer 15

Expert Solution

To determine

(b)

The value of AB and arc CB⌢.

Answer to Problem 20A

The value of AB is AB=6.034" and the value of arc is CB⌢=3.654".

Explanation of Solution

Given information:

AB = 3.017"

ACB⌢=7.308"

Mathematics For Machine Technology, Chapter 55, Problem 20A , additional homework tip 2

If the radius of the circle is perpendicular to the chord, it always divides the chord in two equal parts.

In the figure given above, the radius is perpendicular to the chord; hence, the parts AD will be equal to DB. Each portion AD and DB is half the value of part AB.

AD=DB=AB2

AB=2×DBAB=2×3.017"AB=6.034"

The value of AB is AB=6.034"

If the radius of the circle is perpendicular to the chord, it always divides the chord and the arc cut off by the chord in two equal parts.

In the figure given above, the radius is perpendicular to the chord; hence, the parts AD will be equal to DB. Each portion AD and DB is half the value of part AB. Also, the arc cut off by the chord is divided in two equal parts.

AC⌢=CB⌢=ACB⌢2

AC⌢=CB⌢= ACB⌢2ACB⌢=7.308"CB⌢=7.308"2CB⌢=3.654"

The value of AB is AB=6.034" and the value of arc is CB⌢=3.654"

Conclusion:

Thus, the value of AB is AB=6.034" and the value of arc is CB⌢=3.654".

Answer 16

Expert Solution

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

To determine

(b)

The value of AB and arc CB⌢.

Answer 20

Answer to Problem 20A

The value of AB is AB=6.034" and the value of arc is CB⌢=3.654".

Answer 21

Explanation of Solution

Given information:

AB = 3.017"

ACB⌢=7.308"

Mathematics For Machine Technology, Chapter 55, Problem 20A , additional homework tip 2

If the radius of the circle is perpendicular to the chord, it always divides the chord in two equal parts.

In the figure given above, the radius is perpendicular to the chord; hence, the parts AD will be equal to DB. Each portion AD and DB is half the value of part AB.

AD=DB=AB2

AB=2×DBAB=2×3.017"AB=6.034"

The value of AB is AB=6.034"

If the radius of the circle is perpendicular to the chord, it always divides the chord and the arc cut off by the chord in two equal parts.

In the figure given above, the radius is perpendicular to the chord; hence, the parts AD will be equal to DB. Each portion AD and DB is half the value of part AB. Also, the arc cut off by the chord is divided in two equal parts.

AC⌢=CB⌢=ACB⌢2