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Chapter 5.3, Problem 28STQ

Explanation of Solution

Reasons for causing an error message:

  • • From the given code, the variables “s1” and “s2” are names of objects of “Species” type; however this program does not create any objects for two names “s1” and “s2” which are just names not objects.
    • ○ Hence, it displays an error message.
  • • Object declaration for “Species” class will be as follows:

  Species s1 = new Species();

  Species s2 = new Species();

Correction code:

//Define class "SpeciesEqualsDemo"

public class SpeciesEqualsDemo

{

    //Define main function

    public static void main(String[] args)

    {

        //Create "s1" object for "Species" class

        Species s1 = new Species();

     ...

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Given a relation schema R = (A, B, C, D, E,G) with a set of functional dependencies F {ABCD BC → DE B→ D D→ A}. (a) Show that R is not in BCNF using the functional dependency A → BCD. (b) Show that AG is a superkey for R (c) Compute a canonical cover Fc for the set of functional dependencies F. Show your work. (d) Give a 3NF decomposition of R based on the canonical cover found in (c). Show your work. (e) Give a BCNF decomposition of R using F. Show your work.

Chapter 5 Solutions

Java: An Introduction to Problem Solving and Programming plus MyProgrammingLab with Pearson eText -- Access Card Package (7th Edition)

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