In Exercises 69 and 70, determine whether you can use a normal distribution to approximate the binomial distribution. If you can, use the normal distribution to approximate the indicated probabilities and sketch their graphs. If you cannot, explain why and use a binomial distribution to find the indicated probabilities. 69. A survey of U.S. adults found that 32% have an online account with their healthcare provider. You randomly select 70 U.S. adults and ask them whether they have an online account with their healthcare provider. Find the probability that the number who have an online account with their healthcare provider is (a) at most 15, (b) exactly 25, and (c) greater than 30. Identify any unusual events. Explain. (Source: Pew Research Center)
In Exercises 69 and 70, determine whether you can use a normal distribution to approximate the binomial distribution. If you can, use the normal distribution to approximate the indicated probabilities and sketch their graphs. If you cannot, explain why and use a binomial distribution to find the indicated probabilities. 69. A survey of U.S. adults found that 32% have an online account with their healthcare provider. You randomly select 70 U.S. adults and ask them whether they have an online account with their healthcare provider. Find the probability that the number who have an online account with their healthcare provider is (a) at most 15, (b) exactly 25, and (c) greater than 30. Identify any unusual events. Explain. (Source: Pew Research Center)
Solution Summary: The author illustrates how the normal distribution can be used to approximate the binomial distribution.
In Exercises 69 and 70, determine whether you can use a normal distribution to approximate the binomial distribution. If you can, use the normal distribution to approximate the indicated probabilities and sketch their graphs. If you cannot, explain why and use a binomial distribution to find the indicated probabilities.
69. A survey of U.S. adults found that 32% have an online account with their healthcare provider. You randomly select 70 U.S. adults and ask them whether they have an online account with their healthcare provider. Find the probability that the number who have an online account with their healthcare provider is (a) at most 15, (b) exactly 25, and (c) greater than 30. Identify any unusual events. Explain. (Source: Pew Research Center)
Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.
Fred needs to choose a password for a certain website. Assume that he will choose an
8-character password, and that the legal characters are the lowercase letters a, b, c, ...,
z, the uppercase letters A, B, C, ..., Z, and the numbers 0, 1, . . ., 9.
(a) How many possibilities are there if he is required to have at least one lowercase letter
in his password?
(b) How many possibilities are there if he is required to have at least one lowercase
letter and at least one uppercase letter in his password?
(c) How many possibilities are there if he is required to have at least one lowercase
letter, at least one uppercase letter, and at least one number in his password?
a =1500, b=1700 what is percentage of a is b
A 12-inch bar that is clamped at both ends is to be subjected to an increasing amount of stress until it snaps. Let Y = the distance from the left end at which the break occurs. Suppose Y has the following pdf.
f(y) =
{
(a) Compute the cdf of Y.
F(y) =
0
0
y
-옴)
0 ≤ y ≤ 12
1-
12
y 12
Graph the cdf of Y.
F(y)
1.0
0.8
0.6
0.4
0.2
y
2
6
8
10
12
F(y)
F(y)
F(y)
1.01
1.0ㅏ
1.0
0.8
0.6
0.4
0.2
0.8
0.8
0.6
0.4
ཨཱུ སྦེ
0.6
0.4
0.2
2
4
6
8
10
12
(b) Compute P(Y ≤ 5), P(Y > 6), and P(5 ≤ y ≤ 6). (Round your answers to three decimal places.)
P(Y ≤ 5) =
P(Y > 6) =
P(5 ≤ y ≤ 6) =
(c) Compute E(Y), E(y²), and V(Y).
E(Y) =
in
E(Y2)
v(x) =
in 2
2
2
4
6
8
10
12
y
2
4
6
8
10
12
Chapter 5 Solutions
Elementary Statistics: Picturing the World (7th Edition)
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