Introduction to Java Programming and Data Structures, Comprehensive Version, Student Value Edition (11th Edition)
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Chapter 3.10, Problem 3.10.1CP

Explanation of Solution

Given statements:

(true) && (3>4)

  • 1st part: The first part is given as “true”.
  • 2nd part: In the second part, the value “3” is not greater than “4”. Hence the second part is “false”.
  • The AND (&&) operation becomes “true” if both the parts are “true”. Otherwise, it is “false”.
  • Here, one part is “true” and the other part is “false”.

Therefore, (true) && (3>4) returns “false

!(x>0) && (x>0)

  • Apply “1” in the place of “x”. Then the statement becomes “!(1>0) && (1>0)”
  • 1st part: In the first part, “1” is greater than “0”. But NOT operator makes this as “false”.
  • 2nd part: In the second part, the value “1” is greater than “0”. Hence the second part is “true”.
  • The AND (&&) operation becomes “true” if both the parts are “true”. Otherwise, it is “false”.
  • Here, one part is “false” and the other part is “true”.

Therefore, !(x>0) && (x>0)returns “false

(x>0) || (x<0)

  • Apply “1” in the place of “x”. Then the statement becomes “(1>0) || (1<0)”
  • 1st part: In the first part, “1” is greater than “0”. Hence, it returns “true”.
  • 2nd part: In the second part, the value “1” is not less than “0”. Hence the second part is “false”.
  • The OR (||) operation becomes “true” if any one of the parts is “true”. Otherwise, it is “false”.
  • Here, one part is “true” and the other part is “false”.

Therefore, (x>0) || (x<0) returns “true”...

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Chapter 3 Solutions

Introduction to Java Programming and Data Structures, Comprehensive Version, Student Value Edition (11th Edition)

Chapter 3.5, Problem 3.5.3CPChapter 3.6, Problem 3.6.1CPChapter 3.6, Problem 3.6.2CPChapter 3.6, Problem 3.6.3CPChapter 3.6, Problem 3.6.4CPChapter 3.7, Problem 3.7.1CPChapter 3.7, Problem 3.7.2CPChapter 3.9, Problem 3.9.1CPChapter 3.10, Problem 3.10.1CPChapter 3.10, Problem 3.10.2CPChapter 3.10, Problem 3.10.3CPChapter 3.10, Problem 3.10.4CPChapter 3.10, Problem 3.10.5CPChapter 3.10, Problem 3.10.6CPChapter 3.10, Problem 3.10.7CPChapter 3.10, Problem 3.10.8CPChapter 3.10, Problem 3.10.9CPChapter 3.10, Problem 3.10.10CPChapter 3.10, Problem 3.10.11CPChapter 3.11, Problem 3.11.1CPChapter 3.12, Problem 3.12.1CPChapter 3.13, Problem 3.13.1CPChapter 3.13, Problem 3.13.2CPChapter 3.13, Problem 3.13.3CPChapter 3.13, Problem 3.13.4CPChapter 3.13, Problem 3.13.5CPChapter 3.14, Problem 3.14.1CPChapter 3.14, Problem 3.14.2CPChapter 3.14, Problem 3.14.3CPChapter 3.14, Problem 3.14.4CPChapter 3.15, Problem 3.15.1CPChapter 3.15, Problem 3.15.2CPChapter 3.15, Problem 3.15.3CPChapter 3.15, Problem 3.15.4CPChapter 3, Problem 3.1PEChapter 3, Problem 3.2PEChapter 3, Problem 3.3PEChapter 3, Problem 3.4PEChapter 3, Problem 3.5PEChapter 3, Problem 3.6PEChapter 3, Problem 3.7PEChapter 3, Problem 3.8PEChapter 3, Problem 3.9PEChapter 3, Problem 3.10PEChapter 3, Problem 3.11PEChapter 3, Problem 3.12PEChapter 3, Problem 3.13PEChapter 3, Problem 3.14PEChapter 3, Problem 3.15PEChapter 3, Problem 3.16PEChapter 3, Problem 3.17PEChapter 3, Problem 3.18PEChapter 3, Problem 3.19PEChapter 3, Problem 3.20PEChapter 3, Problem 3.21PEChapter 3, Problem 3.22PEChapter 3, Problem 3.23PEChapter 3, Problem 3.24PEChapter 3, Problem 3.25PEChapter 3, Problem 3.26PEChapter 3, Problem 3.27PEChapter 3, Problem 3.28PEChapter 3, Problem 3.29PEChapter 3, Problem 3.30PEChapter 3, Problem 3.31PEChapter 3, Problem 3.32PEChapter 3, Problem 3.33PEChapter 3, Problem 3.34PE
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