Chapter 3, Problem 9CP

Question

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Answer 1

Expert Solution & Answer

Chapter 3, Problem 9CP

(a)

Explanation of Solution

Given: The value of x is 3, of y is 2, and the following expression:

if (x > 2)

{

if (y > 2)

{

int z = x + y;

cout << "z is " << z << endl;

}

}

else

cout << "x is " << x << endl;

To find: The output of the code and the flowchart of the code.

Solution:

The output of the code will be nothing. The first â€˜ifâ€™ statement will be executed as 3 > 2 will be true...

(b)

Explanation of Solution

Given: The value of x is 3, of y is 4, and the following expression:

if (x > 2)

{

if (y > 2)

{

int z = x + y;

cout << "z is " << z << endl;

}

}

else

cout << "x is " << x << endl;

To find: The output of the code and the flowchart for the code.

Solution:

The output of the code will be â€œz is 7â€�. The first â€˜ifâ€™ statement will be true because 3 > 2, and the first â€˜ifâ€™ statement will be executed...

(c)

Explanation of Solution

Given: The value of x is 2, of y is 2, and the following expression:

if (x > 2)

{

if (y > 2)

{

int z = x + y;

cout << "z is " << z << endl;

}

}

else

cout << "x is " << x << endl;

To find: The output of the code and the flowchart for the code.

Solution:

The output of the code will be â€œx is 2â€�. The first â€˜ifâ€™ statement will be false because 2 is not greater than 2, the first â€˜ifâ€™ statement will not be executed...

Expert Solution & Answer

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Check out a sample textbook solution

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Answer 2

Expert Solution & Answer

Chapter 3, Problem 9CP

(a)

Explanation of Solution

Given: The value of x is 3, of y is 2, and the following expression:

if (x > 2)

{

if (y > 2)

{

int z = x + y;

cout << "z is " << z << endl;

}

}

else

cout << "x is " << x << endl;

To find: The output of the code and the flowchart of the code.

Solution:

The output of the code will be nothing. The first â€˜ifâ€™ statement will be executed as 3 > 2 will be true...

(b)

Explanation of Solution

Given: The value of x is 3, of y is 4, and the following expression:

if (x > 2)

{

if (y > 2)

{

int z = x + y;

cout << "z is " << z << endl;

}

}

else

cout << "x is " << x << endl;

To find: The output of the code and the flowchart for the code.

Solution:

The output of the code will be â€œz is 7â€�. The first â€˜ifâ€™ statement will be true because 3 > 2, and the first â€˜ifâ€™ statement will be executed...

(c)

Explanation of Solution

Given: The value of x is 2, of y is 2, and the following expression:

if (x > 2)

{

if (y > 2)

{

int z = x + y;

cout << "z is " << z << endl;

}

}

else

cout << "x is " << x << endl;

To find: The output of the code and the flowchart for the code.

Solution:

The output of the code will be â€œx is 2â€�. The first â€˜ifâ€™ statement will be false because 2 is not greater than 2, the first â€˜ifâ€™ statement will not be executed...

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 3

Expert Solution & Answer

Chapter 3, Problem 9CP

(a)

Explanation of Solution

Given: The value of x is 3, of y is 2, and the following expression:

if (x > 2)

{

if (y > 2)

{

int z = x + y;

cout << "z is " << z << endl;

}

}

else

cout << "x is " << x << endl;

To find: The output of the code and the flowchart of the code.

Solution:

The output of the code will be nothing. The first â€˜ifâ€™ statement will be executed as 3 > 2 will be true...

(b)

Explanation of Solution

Given: The value of x is 3, of y is 4, and the following expression:

if (x > 2)

{

if (y > 2)

{

int z = x + y;

cout << "z is " << z << endl;

}

}

else

cout << "x is " << x << endl;

To find: The output of the code and the flowchart for the code.

Solution:

The output of the code will be â€œz is 7â€�. The first â€˜ifâ€™ statement will be true because 3 > 2, and the first â€˜ifâ€™ statement will be executed...

(c)

Explanation of Solution

Given: The value of x is 2, of y is 2, and the following expression:

if (x > 2)

{

if (y > 2)

{

int z = x + y;

cout << "z is " << z << endl;

}

}

else

cout << "x is " << x << endl;

To find: The output of the code and the flowchart for the code.

Solution:

The output of the code will be â€œx is 2â€�. The first â€˜ifâ€™ statement will be false because 2 is not greater than 2, the first â€˜ifâ€™ statement will not be executed...

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Expert Solution & Answer

Chapter 3, Problem 9CP

(a)

Explanation of Solution

Given: The value of x is 3, of y is 2, and the following expression:

if (x > 2)

{

if (y > 2)

{

int z = x + y;

cout << "z is " << z << endl;

}

}

else

cout << "x is " << x << endl;

To find: The output of the code and the flowchart of the code.

Solution:

The output of the code will be nothing. The first â€˜ifâ€™ statement will be executed as 3 > 2 will be true...

(b)

Explanation of Solution

Given: The value of x is 3, of y is 4, and the following expression:

if (x > 2)

{

if (y > 2)

{

int z = x + y;

cout << "z is " << z << endl;

}

}

else

cout << "x is " << x << endl;

To find: The output of the code and the flowchart for the code.

Solution:

The output of the code will be â€œz is 7â€�. The first â€˜ifâ€™ statement will be true because 3 > 2, and the first â€˜ifâ€™ statement will be executed...

(c)

Explanation of Solution

Given: The value of x is 2, of y is 2, and the following expression:

if (x > 2)

{

if (y > 2)

{

int z = x + y;

cout << "z is " << z << endl;

}

}

else

cout << "x is " << x << endl;

To find: The output of the code and the flowchart for the code.

Solution:

The output of the code will be â€œx is 2â€�. The first â€˜ifâ€™ statement will be false because 2 is not greater than 2, the first â€˜ifâ€™ statement will not be executed...

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 5

Expert Solution & Answer

Answer 6

Expert Solution & Answer

Answer 7

Chapter 3, Problem 9CP

(a)

Explanation of Solution

Given: The value of x is 3, of y is 2, and the following expression:

if (x > 2)

{

if (y > 2)

{

int z = x + y;

cout << "z is " << z << endl;

}

}

else

cout << "x is " << x << endl;

To find: The output of the code and the flowchart of the code.

Solution:

The output of the code will be nothing. The first â€˜ifâ€™ statement will be executed as 3 > 2 will be true...

(b)

Explanation of Solution

Given: The value of x is 3, of y is 4, and the following expression:

if (x > 2)

{

if (y > 2)

{

int z = x + y;

cout << "z is " << z << endl;

}

}

else

cout << "x is " << x << endl;

To find: The output of the code and the flowchart for the code.

Solution:

The output of the code will be â€œz is 7â€�. The first â€˜ifâ€™ statement will be true because 3 > 2, and the first â€˜ifâ€™ statement will be executed...

(c)

Explanation of Solution

Given: The value of x is 2, of y is 2, and the following expression:

if (x > 2)

{

if (y > 2)

{

int z = x + y;

cout << "z is " << z << endl;

}

}

else

cout << "x is " << x << endl;

To find: The output of the code and the flowchart for the code.

Solution:

The output of the code will be â€œx is 2â€�. The first â€˜ifâ€™ statement will be false because 2 is not greater than 2, the first â€˜ifâ€™ statement will not be executed...

Answer 8

Chapter 3, Problem 9CP

(a)

Explanation of Solution

Given: The value of x is 3, of y is 2, and the following expression:

if (x > 2)

{

if (y > 2)

{

int z = x + y;

cout << "z is " << z << endl;

}

}

else

cout << "x is " << x << endl;

To find: The output of the code and the flowchart of the code.

Solution:

The output of the code will be nothing. The first â€˜ifâ€™ statement will be executed as 3 > 2 will be true...

Answer 9

Chapter 3, Problem 9CP

(a)

Explanation of Solution

Given: The value of x is 3, of y is 2, and the following expression:

if (x > 2)

{

if (y > 2)

{

int z = x + y;

cout << "z is " << z << endl;

}

}

else

cout << "x is " << x << endl;

To find: The output of the code and the flowchart of the code.

Solution:

The output of the code will be nothing. The first â€˜ifâ€™ statement will be executed as 3 > 2 will be true...

Answer 10

(b)

Explanation of Solution

Given: The value of x is 3, of y is 4, and the following expression:

if (x > 2)

{

if (y > 2)

{

int z = x + y;

cout << "z is " << z << endl;

}

}

else

cout << "x is " << x << endl;

To find: The output of the code and the flowchart for the code.

Solution:

The output of the code will be â€œz is 7â€�. The first â€˜ifâ€™ statement will be true because 3 > 2, and the first â€˜ifâ€™ statement will be executed...

Answer 11

(b)

Explanation of Solution

Given: The value of x is 3, of y is 4, and the following expression:

if (x > 2)

{

if (y > 2)

{

int z = x + y;

cout << "z is " << z << endl;

}

}

else

cout << "x is " << x << endl;

To find: The output of the code and the flowchart for the code.

Solution:

The output of the code will be â€œz is 7â€�. The first â€˜ifâ€™ statement will be true because 3 > 2, and the first â€˜ifâ€™ statement will be executed...

Answer 12

(c)

Explanation of Solution

Given: The value of x is 2, of y is 2, and the following expression:

if (x > 2)

{

if (y > 2)

{

int z = x + y;

cout << "z is " << z << endl;

}

}

else

cout << "x is " << x << endl;

To find: The output of the code and the flowchart for the code.

Solution:

The output of the code will be â€œx is 2â€�. The first â€˜ifâ€™ statement will be false because 2 is not greater than 2, the first â€˜ifâ€™ statement will not be executed...

Answer 13

(c)

Explanation of Solution

Given: The value of x is 2, of y is 2, and the following expression:

if (x > 2)

{

if (y > 2)

{

int z = x + y;

cout << "z is " << z << endl;

}

}

else

cout << "x is " << x << endl;

To find: The output of the code and the flowchart for the code.

Solution:

The output of the code will be â€œx is 2â€�. The first â€˜ifâ€™ statement will be false because 2 is not greater than 2, the first â€˜ifâ€™ statement will not be executed...

Answer 14

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Answer 15

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Answer 16

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Answer 17

Chapter 3, Problem 1CP Chapter 3, Problem 2CP Chapter 3, Problem 3CP Chapter 3, Problem 4CP Chapter 3, Problem 5CP Chapter 3, Problem 6CP Chapter 3, Problem 7CP Chapter 3, Problem 8CP Chapter 3, Problem 9CP Chapter 3, Problem 10CP

Chapter 3, Problem 9CP

Solution Summary: The author explains that the output of the code and the flowchart will be nothing.

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