The Analysis of Biological Data
The Analysis of Biological Data
2nd Edition
ISBN: 9781936221486
Author: Michael C. Whitlock, Dolph Schluter
Publisher: W. H. Freeman
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Chapter 3, Problem 1PP

(a)

To determine

To find: The sample size.

(a)

Expert Solution
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Explanation of Solution

Given:

The data set is:

    112
    128
    108
    129
    125
    153
    155
    132
    137

The provided data represents that there are total 9 observations. Thus, the sample size is 9.

(b)

To determine

To find: The sum of the provided observations.

(b)

Expert Solution
Check Mark

Answer to Problem 1PP

The sum is 1179.

Explanation of Solution

The sum of the provided observations can be calculated as:

  Sum of observations=112+128+....+137=1179

Thus, the required sum is 1179.

(c)

To determine

To fin: The mean of the provided observation and apply the units after calculation.

(c)

Expert Solution
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Answer to Problem 1PP

The mean is 131 mm Hg

Explanation of Solution

The mean for the provided data set can be computed as:

  Mean=Sum of observationsNumber of observations=11799=131

Thus, the mean is 131 mm Hg.

(d)

To determine

To find: The sum of square.

(d)

Expert Solution
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Answer to Problem 1PP

The value of the sum of square is 2036.

Explanation of Solution

The sum of square is computed as:

    x(xx¯)(xx¯)2
    112-19361
    128-39
    108-23529
    129-24
    125-636
    15322484
    15524576
    13211
    137636

      ( x x ¯ )2=2036

Thus, the sum of square is 2036.

(e)

To determine

To find: The variance for the provided data set.

(e)

Expert Solution
Check Mark

Answer to Problem 1PP

The variance is 254.2

Explanation of Solution

Variance for the provided data set is computed as:

  s2= ( x x ¯ ) 2 =2036n1=203691=254.5

(f)

To determine

To find: The standard deviation for the provided data set.

(f)

Expert Solution
Check Mark

Answer to Problem 1PP

The standard deviation is 15.950

Explanation of Solution

Standard deviation for the provided data set is computed as:

  Standard deviation=Variance=254.5=15.950

Thus, the standard deviation is 15.950.

(g)

To determine

To find: The coefficient of variation.

(g)

Expert Solution
Check Mark

Answer to Problem 1PP

The coefficient of variation is 12.176%

Explanation of Solution

The coefficient of variation can be computed as:

  CV=sx¯×100=15.950131×100=12.176

The coefficient of variation is 12.176%.

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