The number of years does one electron takes to travel the full length of the cable.

Question

Want to see more full solutions like this?

Answer 1

Question

Chapter 26, Problem 1P

To determine

The number of years does one electron takes to travel the full length of the cable.

Expert Solution & Answer

Answer to Problem 1P

The number of years that takes one electron to travel the full length of the cable is 27.0 yr .

Explanation of Solution

Given information: Length of the high voltage transmission line is 200 km , diameter of the transmission line is 2.00 cm , steady current is 1000 A , the number of electrons per unit volume is 8.50×1028 electrons/m3 .

Write the expression for the area of cross section of a conductor.

A=π4d2

Here,

A is the area of cross section of a conductor.

d is the diameter of the transmission line.

Substitute 2.00 cm for d in equation (1) to find A ,

A=π4(2.00 cm×1 m100 cm)2=3.14×10−4 m2

Thus, the area of cross section of a conductor is 3.14×10−4 m2 .

Formula to calculate the drift velocity of a conductor.

I=neAVdVd=IneA (2)

Here,

Vd is the drift velocity of a conductor.

n is the number of electrons per unit volume.

I is the steady current.

e is the charge of one electron.

The value of charge of one electron is 1.6×10−19 C .

Substitute 1000 A for I , 8.50×1028 electrons/m3 for n , 1.6×10−19 C for e , 3.14×10−4 m2 for A in equation (2) to find Vd ,

Vd=1000 A(8.50×1028 electrons/m3)×(1.6×10−19 C)×(3.14×10−4 m2)=2.34×10−4 m/s

Thus, the drift velocity of a conductor is 2.34×10−4 m/s .

Formula to calculate the number of years that takes one electron to travel the full length of the cable.

T=DVd (3)

Here,

T is the number of years that takes one electron to travel the full length of the cable.

D is the length of the high voltage transmission line.

Substitute 200 km for D , 2.34×10−4 m/s for Vd in equation (3) to find T ,

T=200 km×1000 m1 km2.34×10−4 m/s=8.54×108 s×1 yr(365×24×60×60) s=27.0 yr

Thus, the number of years that takes one electron to travel the full length of the cable is 27.0 yr .

Conclusion:

Therefore, the number of years that takes one electron to travel the full length of the cable is 27.0 yr .

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

04:53

Students have asked these similar questions

Please help

15 cm Two lenses lie 70 cm apart. The focal lengths are f₁ = 20 cm for lens 1 (converging), and f₂ = -51 cm for lens 2 (diverging). A 15 cm tall object sits 45 cm in front of lens 1. Note: the 50 and 100 cm markings on the line are not the positions of the lenses! a) First, draw the positions of the two lenses. Then draw a ray diagram with all the primary rays. Include the location of image 1 formed by lens 1 and the final image formed by lens 2. (4 points) 0 cm 50 cm 100 cm 150 cm b) For each of image 1 and the final image: are they real or virtual, upright or inverted (relative to the original object)? (1 point) c) Calculate the distance of the final image from the object. (2 points) d) Find the magnification and size in cm of the final image. (2 points) e) Do your calculations in parts c) and d) match your ray diagrams in part a)? (1 point)

A simple series circuit consists of a 150 Ω resistor, a 27.0 V battery, a switch, and a 2.00 pF parallel-plate capacitor (initially uncharged) with plates 5.0 mm apart. The switch is closed at t =0s . Part A Part complete Part B Part complete Part C Find the electric flux at t =0.50ns. Express your answer in volt-meters. View Available Hint(s)for Part C Activate to select the appropriates template from the following choices. Operate up and down arrow for selection and press enter to choose the input value typeActivate to select the appropriates symbol from the following choices. Operate up and down arrow for selection and press enter to choose the input value type nothing V⋅m Part D Find the displacement current at t =0.50ns.

Answer 2

Question

Chapter 26, Problem 1P

To determine

The number of years does one electron takes to travel the full length of the cable.

Expert Solution & Answer

Answer to Problem 1P

The number of years that takes one electron to travel the full length of the cable is 27.0 yr .

Explanation of Solution

Given information: Length of the high voltage transmission line is 200 km , diameter of the transmission line is 2.00 cm , steady current is 1000 A , the number of electrons per unit volume is 8.50×1028 electrons/m3 .

Write the expression for the area of cross section of a conductor.

A=π4d2

Here,

A is the area of cross section of a conductor.

d is the diameter of the transmission line.

Substitute 2.00 cm for d in equation (1) to find A ,

A=π4(2.00 cm×1 m100 cm)2=3.14×10−4 m2

Thus, the area of cross section of a conductor is 3.14×10−4 m2 .

Formula to calculate the drift velocity of a conductor.

I=neAVdVd=IneA (2)

Here,

Vd is the drift velocity of a conductor.

n is the number of electrons per unit volume.

I is the steady current.

e is the charge of one electron.

The value of charge of one electron is 1.6×10−19 C .

Substitute 1000 A for I , 8.50×1028 electrons/m3 for n , 1.6×10−19 C for e , 3.14×10−4 m2 for A in equation (2) to find Vd ,

Vd=1000 A(8.50×1028 electrons/m3)×(1.6×10−19 C)×(3.14×10−4 m2)=2.34×10−4 m/s

Thus, the drift velocity of a conductor is 2.34×10−4 m/s .

Formula to calculate the number of years that takes one electron to travel the full length of the cable.

T=DVd (3)

Here,

T is the number of years that takes one electron to travel the full length of the cable.

D is the length of the high voltage transmission line.

Substitute 200 km for D , 2.34×10−4 m/s for Vd in equation (3) to find T ,

T=200 km×1000 m1 km2.34×10−4 m/s=8.54×108 s×1 yr(365×24×60×60) s=27.0 yr

Thus, the number of years that takes one electron to travel the full length of the cable is 27.0 yr .

Conclusion:

Therefore, the number of years that takes one electron to travel the full length of the cable is 27.0 yr .

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

04:53

Answer 3

Question

Chapter 26, Problem 1P

To determine

The number of years does one electron takes to travel the full length of the cable.

Expert Solution & Answer

Answer to Problem 1P

The number of years that takes one electron to travel the full length of the cable is 27.0 yr .

Explanation of Solution

Given information: Length of the high voltage transmission line is 200 km , diameter of the transmission line is 2.00 cm , steady current is 1000 A , the number of electrons per unit volume is 8.50×1028 electrons/m3 .

Write the expression for the area of cross section of a conductor.

A=π4d2

Here,

A is the area of cross section of a conductor.

d is the diameter of the transmission line.

Substitute 2.00 cm for d in equation (1) to find A ,

A=π4(2.00 cm×1 m100 cm)2=3.14×10−4 m2

Thus, the area of cross section of a conductor is 3.14×10−4 m2 .

Formula to calculate the drift velocity of a conductor.

I=neAVdVd=IneA (2)

Here,

Vd is the drift velocity of a conductor.

n is the number of electrons per unit volume.

I is the steady current.

e is the charge of one electron.

The value of charge of one electron is 1.6×10−19 C .

Substitute 1000 A for I , 8.50×1028 electrons/m3 for n , 1.6×10−19 C for e , 3.14×10−4 m2 for A in equation (2) to find Vd ,

Vd=1000 A(8.50×1028 electrons/m3)×(1.6×10−19 C)×(3.14×10−4 m2)=2.34×10−4 m/s

Thus, the drift velocity of a conductor is 2.34×10−4 m/s .

Formula to calculate the number of years that takes one electron to travel the full length of the cable.

T=DVd (3)

Here,

T is the number of years that takes one electron to travel the full length of the cable.

D is the length of the high voltage transmission line.

Substitute 200 km for D , 2.34×10−4 m/s for Vd in equation (3) to find T ,

T=200 km×1000 m1 km2.34×10−4 m/s=8.54×108 s×1 yr(365×24×60×60) s=27.0 yr

Thus, the number of years that takes one electron to travel the full length of the cable is 27.0 yr .

Conclusion:

Therefore, the number of years that takes one electron to travel the full length of the cable is 27.0 yr .

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

04:53

Answer 4

Question

Chapter 26, Problem 1P

To determine

The number of years does one electron takes to travel the full length of the cable.

Expert Solution & Answer

Answer to Problem 1P

The number of years that takes one electron to travel the full length of the cable is 27.0 yr .

Explanation of Solution

Given information: Length of the high voltage transmission line is 200 km , diameter of the transmission line is 2.00 cm , steady current is 1000 A , the number of electrons per unit volume is 8.50×1028 electrons/m3 .

Write the expression for the area of cross section of a conductor.

A=π4d2

Here,

A is the area of cross section of a conductor.

d is the diameter of the transmission line.

Substitute 2.00 cm for d in equation (1) to find A ,

A=π4(2.00 cm×1 m100 cm)2=3.14×10−4 m2

Thus, the area of cross section of a conductor is 3.14×10−4 m2 .

Formula to calculate the drift velocity of a conductor.

I=neAVdVd=IneA (2)

Here,

Vd is the drift velocity of a conductor.

n is the number of electrons per unit volume.

I is the steady current.

e is the charge of one electron.

The value of charge of one electron is 1.6×10−19 C .

Substitute 1000 A for I , 8.50×1028 electrons/m3 for n , 1.6×10−19 C for e , 3.14×10−4 m2 for A in equation (2) to find Vd ,

Vd=1000 A(8.50×1028 electrons/m3)×(1.6×10−19 C)×(3.14×10−4 m2)=2.34×10−4 m/s

Thus, the drift velocity of a conductor is 2.34×10−4 m/s .

Formula to calculate the number of years that takes one electron to travel the full length of the cable.

T=DVd (3)

Here,

T is the number of years that takes one electron to travel the full length of the cable.

D is the length of the high voltage transmission line.

Substitute 200 km for D , 2.34×10−4 m/s for Vd in equation (3) to find T ,

T=200 km×1000 m1 km2.34×10−4 m/s=8.54×108 s×1 yr(365×24×60×60) s=27.0 yr

Thus, the number of years that takes one electron to travel the full length of the cable is 27.0 yr .

Conclusion:

Therefore, the number of years that takes one electron to travel the full length of the cable is 27.0 yr .

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

04:53

Answer 5

Chapter 26, Problem 1P

To determine

The number of years does one electron takes to travel the full length of the cable.

Expert Solution & Answer

Answer to Problem 1P

The number of years that takes one electron to travel the full length of the cable is 27.0 yr .

Explanation of Solution

Given information: Length of the high voltage transmission line is 200 km , diameter of the transmission line is 2.00 cm , steady current is 1000 A , the number of electrons per unit volume is 8.50×1028 electrons/m3 .

Write the expression for the area of cross section of a conductor.

A=π4d2

Here,

A is the area of cross section of a conductor.

d is the diameter of the transmission line.

Substitute 2.00 cm for d in equation (1) to find A ,

A=π4(2.00 cm×1 m100 cm)2=3.14×10−4 m2

Thus, the area of cross section of a conductor is 3.14×10−4 m2 .

Formula to calculate the drift velocity of a conductor.

I=neAVdVd=IneA (2)

Here,

Vd is the drift velocity of a conductor.

n is the number of electrons per unit volume.

I is the steady current.

e is the charge of one electron.

The value of charge of one electron is 1.6×10−19 C .

Substitute 1000 A for I , 8.50×1028 electrons/m3 for n , 1.6×10−19 C for e , 3.14×10−4 m2 for A in equation (2) to find Vd ,

Vd=1000 A(8.50×1028 electrons/m3)×(1.6×10−19 C)×(3.14×10−4 m2)=2.34×10−4 m/s

Thus, the drift velocity of a conductor is 2.34×10−4 m/s .

Formula to calculate the number of years that takes one electron to travel the full length of the cable.

T=DVd (3)

Here,

T is the number of years that takes one electron to travel the full length of the cable.

D is the length of the high voltage transmission line.

Substitute 200 km for D , 2.34×10−4 m/s for Vd in equation (3) to find T ,

T=200 km×1000 m1 km2.34×10−4 m/s=8.54×108 s×1 yr(365×24×60×60) s=27.0 yr

Thus, the number of years that takes one electron to travel the full length of the cable is 27.0 yr .

Conclusion:

Therefore, the number of years that takes one electron to travel the full length of the cable is 27.0 yr .

Answer 6

Chapter 26, Problem 1P

To determine

The number of years does one electron takes to travel the full length of the cable.

Expert Solution & Answer

Answer to Problem 1P

The number of years that takes one electron to travel the full length of the cable is 27.0 yr .

Explanation of Solution

Given information: Length of the high voltage transmission line is 200 km , diameter of the transmission line is 2.00 cm , steady current is 1000 A , the number of electrons per unit volume is 8.50×1028 electrons/m3 .

Write the expression for the area of cross section of a conductor.

A=π4d2

Here,

A is the area of cross section of a conductor.

d is the diameter of the transmission line.

Substitute 2.00 cm for d in equation (1) to find A ,

A=π4(2.00 cm×1 m100 cm)2=3.14×10−4 m2

Thus, the area of cross section of a conductor is 3.14×10−4 m2 .

Formula to calculate the drift velocity of a conductor.

I=neAVdVd=IneA (2)

Here,

Vd is the drift velocity of a conductor.

n is the number of electrons per unit volume.

I is the steady current.

e is the charge of one electron.

The value of charge of one electron is 1.6×10−19 C .

Substitute 1000 A for I , 8.50×1028 electrons/m3 for n , 1.6×10−19 C for e , 3.14×10−4 m2 for A in equation (2) to find Vd ,

Vd=1000 A(8.50×1028 electrons/m3)×(1.6×10−19 C)×(3.14×10−4 m2)=2.34×10−4 m/s

Thus, the drift velocity of a conductor is 2.34×10−4 m/s .

Formula to calculate the number of years that takes one electron to travel the full length of the cable.

T=DVd (3)

Here,

T is the number of years that takes one electron to travel the full length of the cable.

D is the length of the high voltage transmission line.

Substitute 200 km for D , 2.34×10−4 m/s for Vd in equation (3) to find T ,

T=200 km×1000 m1 km2.34×10−4 m/s=8.54×108 s×1 yr(365×24×60×60) s=27.0 yr

Thus, the number of years that takes one electron to travel the full length of the cable is 27.0 yr .

Conclusion:

Therefore, the number of years that takes one electron to travel the full length of the cable is 27.0 yr .

Answer 7

Chapter 26, Problem 1P

To determine

The number of years does one electron takes to travel the full length of the cable.

Answer 8

Expert Solution & Answer

Answer to Problem 1P

The number of years that takes one electron to travel the full length of the cable is 27.0 yr .

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

Given information: Length of the high voltage transmission line is 200 km , diameter of the transmission line is 2.00 cm , steady current is 1000 A , the number of electrons per unit volume is 8.50×1028 electrons/m3 .