A modification in a vector “vec = [11 -5 33 2 8 -4 25]” instead of deleting the negative elements, retain only the positive ones.

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Chapter 2, Problem 2.4P

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A modification in a vector “vec = [11 -5 33 2 8 -4 25]” instead of deleting the negative elements, retain only the positive ones.

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Ho: μ = 22 - H₁:22 x = 25.1, n = 59, σ = 8.45, α = .01 a. Use the data given to test the following hypotheses. (Round your answer to 2 decimal places, e.g. 15.25.) The value of the test statistic is and we b. Use the p-value to reach a statistical conclusion. (Round your answer to 4 decimal places, e.g. 0.1254.) Since the p-value of is than a/2 = .005, the decision is to: Appendix A Statistical Tables c. Using the critical value method, what are the critical sample mean values? (Round your answer to 3 decimal places, e.g. 15.254.) Critical mean values: Upper value: Lower value:

- Ho=25 H:25 x = 28.1, n = = 55, σ = 8.47, α = .01 a. Use the data given to test the following hypotheses. (Round your answer to 2 decimal places, e.g. 15.25.) The value of the test statistic is and we b. Use the p-value to reach a statistical conclusion. (Round your answer to 4 decimal places, e.g. 0.1254.) Since the p-value of is than a/2 = .005, the decision is to: Appendix A Statistical Tables c. Using the critical value method, what are the critical sample mean values? (Round your answer to 3 decimal places, e.g. 15.254.) Critical mean values: Upper value: Lower value:

Answer 2

Question

Chapter 2, Problem 2.4P

To determine

To find:

A modification in a vector “vec = [11 -5 33 2 8 -4 25]” instead of deleting the negative elements, retain only the positive ones.

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Answer 3

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Chapter 2, Problem 2.4P

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To find:

A modification in a vector “vec = [11 -5 33 2 8 -4 25]” instead of deleting the negative elements, retain only the positive ones.

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Answer 4

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Chapter 2, Problem 2.4P

To determine

To find:

A modification in a vector “vec = [11 -5 33 2 8 -4 25]” instead of deleting the negative elements, retain only the positive ones.

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Answer 5

Chapter 2, Problem 2.4P

To determine

To find:

A modification in a vector “vec = [11 -5 33 2 8 -4 25]” instead of deleting the negative elements, retain only the positive ones.

Answer 6

Chapter 2, Problem 2.4P

To determine

To find:

A modification in a vector “vec = [11 -5 33 2 8 -4 25]” instead of deleting the negative elements, retain only the positive ones.

Answer 7

Chapter 2, Problem 2.4P

To determine

To find:

A modification in a vector “vec = [11 -5 33 2 8 -4 25]” instead of deleting the negative elements, retain only the positive ones.

Answer 8

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Answer 11

Ch. 2 - Prob. 2.1P Ch. 2 - Prob. 2.2P Ch. 2 - Prob. 2.3P Ch. 2 - Prob. 2.4P Ch. 2 - Prob. 2.5P Ch. 2 - Prob. 1E Ch. 2 - Prob. 2E Ch. 2 - Prob. 3E Ch. 2 - Prob. 4E Ch. 2 - Prob. 5E

A modification in a vector “vec = [11 -5 33 2 8 -4 25]” instead of deleting the negative elements, retain only the positive ones.

Solution Summary: The author explains how the MATLAB script is used to find the sum of the first n terms of a harmonic series.

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A modification in a vector “vec = [11 -5 33 2 8 -4 25]” instead of deleting the negative elements, retain only the positive ones.

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Chapter 2 Solutions

A modification in a vector “vec = [11 -5 33 2 8 -4 25]” instead of deleting the negative elements, retain only the positive ones.

Solution Summary: The author explains how the MATLAB script is used to find the sum of the first n terms of a harmonic series.

Concept explainers

Videos

To find: A modification in a vector “vec = [11 -5 33 2 8 -4 25]” instead of deleting the negative elements, retain only the positive ones.

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Chapter 2 Solutions

To find:

A modification in a vector “vec = [11 -5 33 2 8 -4 25]” instead of deleting the negative elements, retain only the positive ones.