(a) Calculate the angular velocity of the ring when collar passes through 90 0 ? Collar is free to slide on a ring and ring is attached to a vertical shaft. Which rotates in a fixed bearing. Initially, collar is at top of the ring θ = 0 at 35 rad/sec of angular velocity. Refer figure.

Question

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Answer 1

Question

Chapter 17.2, Problem 17.91P

To determine

(a)

Calculate the angular velocity of the ring when collar passes through 900 ? Collar is free to slide on a ring and ring is attached to a vertical shaft. Which rotates in a fixed bearing. Initially, collar is at top of the ring θ=0 at 35 rad/sec of angular velocity. Refer figure.

Expert Solution

Answer to Problem 17.91P

The angular velocity of the ring when coller is at 900 from the top is 15 rad/sec.

Explanation of Solution

Given:

The weight of collar = ωc=4lb=1.814kg

Mass of ring = ωr=6lb=2.721kg

The radius of the ring,

Rr=10in=0.254mθ=0vc=0

The angular velocity (ωc) of the collar = 35 rad/sec.

Concept used:

Conservation of angular momentum.

Conservation of energy.

Calculation:

Vector Mechanics for Engineers: Dynamics, Chapter 17.2, Problem 17.91P , additional homework tip 2

Position (1): θ=0vc=0

Position (2): θ=900(vc)4=vy=Rω2

By conservation of angular momentum,

IRω1=IRω2+mcvyRmRR2ω1=(mR+2mc)R2ω2ω2=mRω1(mR+2mc)

Potential energy at position 1 and position 2

v1=mcgRv2=0

The kinetic energy of position 1 and position 2

T1=IRω122=12mRR2ω12T2=IRω122+12mc(vx2+vY2)=mRR2ω224+mcR2ω222+mcvy22

Applying conservation of energy principle,

T1+v1=T2+v2mRR2ω124+mcgR=mRR2ω224+mcR2ω222+mcvy22

But,

Mass of collar, mc=wcg=0.1849kg

Mass of ring, mR=wRg=0.277kg

ω2=mRω1(mR+2mc)=0.277×35(0.277+2×0.1849)=14.98ω2=15rad/sec

Conclusion:

Using conservation of angular momentum we are able to find, the angular velocity of the ring for θ=900 is 15 a rad/sec.

To determine

(b)

What will be the velocity of collar with respect to ring? Collar is free to slide on a ring and ring is attached to a vertical shaft. Which rotates in a fixed bearing. Initially, collar is at top of the ring θ=0 at 35 rad/sec of angular velocity. Refer figure.

Expert Solution

Answer to Problem 17.91P

The corresponding velocity of collar relative to ring is 6.242 m/s.

Explanation of Solution

Given:

The weight of color = ωc=4lb=1.814kg

Mass of ring = ωr=6lb=2.721kg

The radius of the ring,

Rr=10in=0.254mθ=0vc=0

The angular velocity (ωc) of the collar = 35 rad/sec.

Concept used:

Conservation of angular momentum.

Conservation of energy.

Calculation:

Potential energy at position 1 and position 2

v1=mcgRv2=0

The kinetic energy of position 1 and position 2

T1=IRω122=12mRR2ω12T2=IRω122+12mc(vx2+vY2)=mRR2ω224+mcR2ω222+mcvy22

Applying conservation of energy principle,

T1+v1=T2+v2mRR2ω124+mcgR=mRR2ω224+mcR2ω222+mcvy22

mRR2ω124+mcgR=(mR4+mc2)R2ω22+mcvy225.472+0.4607=2.347+0.092vy2vy=6.242m/s.

Conclusion:

Using conservation of energy principle we are able to find the velocity of collar relative to ring at θ=900 is 6.242m/s

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Answer 2

Question

Chapter 17.2, Problem 17.91P

To determine

(a)

Calculate the angular velocity of the ring when collar passes through 900 ? Collar is free to slide on a ring and ring is attached to a vertical shaft. Which rotates in a fixed bearing. Initially, collar is at top of the ring θ=0 at 35 rad/sec of angular velocity. Refer figure.

Expert Solution

Answer to Problem 17.91P

The angular velocity of the ring when coller is at 900 from the top is 15 rad/sec.

Explanation of Solution

Given:

The weight of collar = ωc=4lb=1.814kg

Mass of ring = ωr=6lb=2.721kg

The radius of the ring,

Rr=10in=0.254mθ=0vc=0

The angular velocity (ωc) of the collar = 35 rad/sec.

Concept used:

Conservation of angular momentum.

Conservation of energy.

Calculation:

Vector Mechanics for Engineers: Dynamics, Chapter 17.2, Problem 17.91P , additional homework tip 2

Position (1): θ=0vc=0

Position (2): θ=900(vc)4=vy=Rω2

By conservation of angular momentum,

IRω1=IRω2+mcvyRmRR2ω1=(mR+2mc)R2ω2ω2=mRω1(mR+2mc)

Potential energy at position 1 and position 2

v1=mcgRv2=0

The kinetic energy of position 1 and position 2

T1=IRω122=12mRR2ω12T2=IRω122+12mc(vx2+vY2)=mRR2ω224+mcR2ω222+mcvy22

Applying conservation of energy principle,

T1+v1=T2+v2mRR2ω124+mcgR=mRR2ω224+mcR2ω222+mcvy22

But,

Mass of collar, mc=wcg=0.1849kg

Mass of ring, mR=wRg=0.277kg

ω2=mRω1(mR+2mc)=0.277×35(0.277+2×0.1849)=14.98ω2=15rad/sec

Conclusion:

Using conservation of angular momentum we are able to find, the angular velocity of the ring for θ=900 is 15 a rad/sec.

To determine

(b)

What will be the velocity of collar with respect to ring? Collar is free to slide on a ring and ring is attached to a vertical shaft. Which rotates in a fixed bearing. Initially, collar is at top of the ring θ=0 at 35 rad/sec of angular velocity. Refer figure.

Expert Solution

Answer to Problem 17.91P

The corresponding velocity of collar relative to ring is 6.242 m/s.

Explanation of Solution

Given:

The weight of color = ωc=4lb=1.814kg

Mass of ring = ωr=6lb=2.721kg

The radius of the ring,

Rr=10in=0.254mθ=0vc=0

The angular velocity (ωc) of the collar = 35 rad/sec.

Concept used:

Conservation of angular momentum.

Conservation of energy.

Calculation:

Potential energy at position 1 and position 2

v1=mcgRv2=0

The kinetic energy of position 1 and position 2

T1=IRω122=12mRR2ω12T2=IRω122+12mc(vx2+vY2)=mRR2ω224+mcR2ω222+mcvy22

Applying conservation of energy principle,

T1+v1=T2+v2mRR2ω124+mcgR=mRR2ω224+mcR2ω222+mcvy22

mRR2ω124+mcgR=(mR4+mc2)R2ω22+mcvy225.472+0.4607=2.347+0.092vy2vy=6.242m/s.

Conclusion:

Using conservation of energy principle we are able to find the velocity of collar relative to ring at θ=900 is 6.242m/s

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Answer 3

Question

Chapter 17.2, Problem 17.91P

To determine

(a)

Calculate the angular velocity of the ring when collar passes through 900 ? Collar is free to slide on a ring and ring is attached to a vertical shaft. Which rotates in a fixed bearing. Initially, collar is at top of the ring θ=0 at 35 rad/sec of angular velocity. Refer figure.

Expert Solution

Answer to Problem 17.91P

The angular velocity of the ring when coller is at 900 from the top is 15 rad/sec.

Explanation of Solution

Given:

The weight of collar = ωc=4lb=1.814kg

Mass of ring = ωr=6lb=2.721kg

The radius of the ring,

Rr=10in=0.254mθ=0vc=0

The angular velocity (ωc) of the collar = 35 rad/sec.

Concept used:

Conservation of angular momentum.

Conservation of energy.

Calculation:

Vector Mechanics for Engineers: Dynamics, Chapter 17.2, Problem 17.91P , additional homework tip 2

Position (1): θ=0vc=0

Position (2): θ=900(vc)4=vy=Rω2

By conservation of angular momentum,

IRω1=IRω2+mcvyRmRR2ω1=(mR+2mc)R2ω2ω2=mRω1(mR+2mc)

Potential energy at position 1 and position 2

v1=mcgRv2=0

The kinetic energy of position 1 and position 2

T1=IRω122=12mRR2ω12T2=IRω122+12mc(vx2+vY2)=mRR2ω224+mcR2ω222+mcvy22

Applying conservation of energy principle,

T1+v1=T2+v2mRR2ω124+mcgR=mRR2ω224+mcR2ω222+mcvy22

But,

Mass of collar, mc=wcg=0.1849kg

Mass of ring, mR=wRg=0.277kg

ω2=mRω1(mR+2mc)=0.277×35(0.277+2×0.1849)=14.98ω2=15rad/sec

Conclusion:

Using conservation of angular momentum we are able to find, the angular velocity of the ring for θ=900 is 15 a rad/sec.

To determine

(b)

What will be the velocity of collar with respect to ring? Collar is free to slide on a ring and ring is attached to a vertical shaft. Which rotates in a fixed bearing. Initially, collar is at top of the ring θ=0 at 35 rad/sec of angular velocity. Refer figure.

Expert Solution

Answer to Problem 17.91P

The corresponding velocity of collar relative to ring is 6.242 m/s.

Explanation of Solution

Given:

The weight of color = ωc=4lb=1.814kg

Mass of ring = ωr=6lb=2.721kg

The radius of the ring,

Rr=10in=0.254mθ=0vc=0

The angular velocity (ωc) of the collar = 35 rad/sec.

Concept used:

Conservation of angular momentum.

Conservation of energy.

Calculation:

Potential energy at position 1 and position 2

v1=mcgRv2=0

The kinetic energy of position 1 and position 2

T1=IRω122=12mRR2ω12T2=IRω122+12mc(vx2+vY2)=mRR2ω224+mcR2ω222+mcvy22

Applying conservation of energy principle,

T1+v1=T2+v2mRR2ω124+mcgR=mRR2ω224+mcR2ω222+mcvy22

mRR2ω124+mcgR=(mR4+mc2)R2ω22+mcvy225.472+0.4607=2.347+0.092vy2vy=6.242m/s.

Conclusion:

Using conservation of energy principle we are able to find the velocity of collar relative to ring at θ=900 is 6.242m/s

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Answer 4

Question

Chapter 17.2, Problem 17.91P

To determine

(a)

Calculate the angular velocity of the ring when collar passes through 900 ? Collar is free to slide on a ring and ring is attached to a vertical shaft. Which rotates in a fixed bearing. Initially, collar is at top of the ring θ=0 at 35 rad/sec of angular velocity. Refer figure.

Expert Solution

Answer to Problem 17.91P

The angular velocity of the ring when coller is at 900 from the top is 15 rad/sec.

Explanation of Solution

Given:

The weight of collar = ωc=4lb=1.814kg

Mass of ring = ωr=6lb=2.721kg

The radius of the ring,

Rr=10in=0.254mθ=0vc=0

The angular velocity (ωc) of the collar = 35 rad/sec.

Concept used:

Conservation of angular momentum.

Conservation of energy.

Calculation:

Vector Mechanics for Engineers: Dynamics, Chapter 17.2, Problem 17.91P , additional homework tip 2

Position (1): θ=0vc=0

Position (2): θ=900(vc)4=vy=Rω2

By conservation of angular momentum,

IRω1=IRω2+mcvyRmRR2ω1=(mR+2mc)R2ω2ω2=mRω1(mR+2mc)

Potential energy at position 1 and position 2

v1=mcgRv2=0

The kinetic energy of position 1 and position 2

T1=IRω122=12mRR2ω12T2=IRω122+12mc(vx2+vY2)=mRR2ω224+mcR2ω222+mcvy22

Applying conservation of energy principle,

T1+v1=T2+v2mRR2ω124+mcgR=mRR2ω224+mcR2ω222+mcvy22

But,

Mass of collar, mc=wcg=0.1849kg

Mass of ring, mR=wRg=0.277kg

ω2=mRω1(mR+2mc)=0.277×35(0.277+2×0.1849)=14.98ω2=15rad/sec

Conclusion:

Using conservation of angular momentum we are able to find, the angular velocity of the ring for θ=900 is 15 a rad/sec.

To determine

(b)

What will be the velocity of collar with respect to ring? Collar is free to slide on a ring and ring is attached to a vertical shaft. Which rotates in a fixed bearing. Initially, collar is at top of the ring θ=0 at 35 rad/sec of angular velocity. Refer figure.

Expert Solution

Answer to Problem 17.91P

The corresponding velocity of collar relative to ring is 6.242 m/s.

Explanation of Solution

Given:

The weight of color = ωc=4lb=1.814kg

Mass of ring = ωr=6lb=2.721kg

The radius of the ring,

Rr=10in=0.254mθ=0vc=0

The angular velocity (ωc) of the collar = 35 rad/sec.

Concept used:

Conservation of angular momentum.

Conservation of energy.

Calculation:

Potential energy at position 1 and position 2

v1=mcgRv2=0

The kinetic energy of position 1 and position 2

T1=IRω122=12mRR2ω12T2=IRω122+12mc(vx2+vY2)=mRR2ω224+mcR2ω222+mcvy22

Applying conservation of energy principle,

T1+v1=T2+v2mRR2ω124+mcgR=mRR2ω224+mcR2ω222+mcvy22

mRR2ω124+mcgR=(mR4+mc2)R2ω22+mcvy225.472+0.4607=2.347+0.092vy2vy=6.242m/s.

Conclusion:

Using conservation of energy principle we are able to find the velocity of collar relative to ring at θ=900 is 6.242m/s

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 17.2, Problem 17.91P

To determine

(a)

Calculate the angular velocity of the ring when collar passes through 900 ? Collar is free to slide on a ring and ring is attached to a vertical shaft. Which rotates in a fixed bearing. Initially, collar is at top of the ring θ=0 at 35 rad/sec of angular velocity. Refer figure.

Expert Solution

Answer to Problem 17.91P

The angular velocity of the ring when coller is at 900 from the top is 15 rad/sec.

Explanation of Solution

Given:

The weight of collar = ωc=4lb=1.814kg

Mass of ring = ωr=6lb=2.721kg

The radius of the ring,

Rr=10in=0.254mθ=0vc=0

The angular velocity (ωc) of the collar = 35 rad/sec.

Concept used:

Conservation of angular momentum.

Conservation of energy.

Calculation:

Vector Mechanics for Engineers: Dynamics, Chapter 17.2, Problem 17.91P , additional homework tip 2

Position (1): θ=0vc=0

Position (2): θ=900(vc)4=vy=Rω2

By conservation of angular momentum,

IRω1=IRω2+mcvyRmRR2ω1=(mR+2mc)R2ω2ω2=mRω1(mR+2mc)

Potential energy at position 1 and position 2

v1=mcgRv2=0

The kinetic energy of position 1 and position 2

T1=IRω122=12mRR2ω12T2=IRω122+12mc(vx2+vY2)=mRR2ω224+mcR2ω222+mcvy22

Applying conservation of energy principle,

T1+v1=T2+v2mRR2ω124+mcgR=mRR2ω224+mcR2ω222+mcvy22

But,

Mass of collar, mc=wcg=0.1849kg

Mass of ring, mR=wRg=0.277kg

ω2=mRω1(mR+2mc)=0.277×35(0.277+2×0.1849)=14.98ω2=15rad/sec

Conclusion:

Using conservation of angular momentum we are able to find, the angular velocity of the ring for θ=900 is 15 a rad/sec.

To determine

(b)

What will be the velocity of collar with respect to ring? Collar is free to slide on a ring and ring is attached to a vertical shaft. Which rotates in a fixed bearing. Initially, collar is at top of the ring θ=0 at 35 rad/sec of angular velocity. Refer figure.

Expert Solution

Answer to Problem 17.91P

The corresponding velocity of collar relative to ring is 6.242 m/s.

Explanation of Solution

Given:

The weight of color = ωc=4lb=1.814kg

Mass of ring = ωr=6lb=2.721kg

The radius of the ring,

Rr=10in=0.254mθ=0vc=0

The angular velocity (ωc) of the collar = 35 rad/sec.

Concept used:

Conservation of angular momentum.

Conservation of energy.

Calculation:

Potential energy at position 1 and position 2

v1=mcgRv2=0

The kinetic energy of position 1 and position 2

T1=IRω122=12mRR2ω12T2=IRω122+12mc(vx2+vY2)=mRR2ω224+mcR2ω222+mcvy22

Applying conservation of energy principle,

T1+v1=T2+v2mRR2ω124+mcgR=mRR2ω224+mcR2ω222+mcvy22

mRR2ω124+mcgR=(mR4+mc2)R2ω22+mcvy225.472+0.4607=2.347+0.092vy2vy=6.242m/s.

Conclusion:

Using conservation of energy principle we are able to find the velocity of collar relative to ring at θ=900 is 6.242m/s

Answer 6

Chapter 17.2, Problem 17.91P

To determine

(a)

Calculate the angular velocity of the ring when collar passes through 900 ? Collar is free to slide on a ring and ring is attached to a vertical shaft. Which rotates in a fixed bearing. Initially, collar is at top of the ring θ=0 at 35 rad/sec of angular velocity. Refer figure.

Expert Solution

Answer to Problem 17.91P

The angular velocity of the ring when coller is at 900 from the top is 15 rad/sec.

Explanation of Solution

Given:

The weight of collar = ωc=4lb=1.814kg

Mass of ring = ωr=6lb=2.721kg

The radius of the ring,

Rr=10in=0.254mθ=0vc=0

The angular velocity (ωc) of the collar = 35 rad/sec.

Concept used:

Conservation of angular momentum.

Conservation of energy.

Calculation:

Vector Mechanics for Engineers: Dynamics, Chapter 17.2, Problem 17.91P , additional homework tip 2

Position (1): θ=0vc=0

Position (2): θ=900(vc)4=vy=Rω2

By conservation of angular momentum,

IRω1=IRω2+mcvyRmRR2ω1=(mR+2mc)R2ω2ω2=mRω1(mR+2mc)

Potential energy at position 1 and position 2

v1=mcgRv2=0

The kinetic energy of position 1 and position 2

T1=IRω122=12mRR2ω12T2=IRω122+12mc(vx2+vY2)=mRR2ω224+mcR2ω222+mcvy22

Applying conservation of energy principle,

T1+v1=T2+v2mRR2ω124+mcgR=mRR2ω224+mcR2ω222+mcvy22

But,

Mass of collar, mc=wcg=0.1849kg

Mass of ring, mR=wRg=0.277kg

ω2=mRω1(mR+2mc)=0.277×35(0.277+2×0.1849)=14.98ω2=15rad/sec

Conclusion:

Using conservation of angular momentum we are able to find, the angular velocity of the ring for θ=900 is 15 a rad/sec.

Answer 7

Chapter 17.2, Problem 17.91P

To determine

(a)

Calculate the angular velocity of the ring when collar passes through 900 ? Collar is free to slide on a ring and ring is attached to a vertical shaft. Which rotates in a fixed bearing. Initially, collar is at top of the ring θ=0 at 35 rad/sec of angular velocity. Refer figure.

Answer 8

Expert Solution

Answer to Problem 17.91P

The angular velocity of the ring when coller is at 900 from the top is 15 rad/sec.

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

Given:

The weight of collar = ωc=4lb=1.814kg

Mass of ring = ωr=6lb=2.721kg

The radius of the ring,

Rr=10in=0.254mθ=0vc=0

The angular velocity (ωc) of the collar = 35 rad/sec.

Concept used:

Conservation of angular momentum.

Conservation of energy.

Calculation:

Vector Mechanics for Engineers: Dynamics, Chapter 17.2, Problem 17.91P , additional homework tip 2

Position (1): θ=0vc=0

Position (2): θ=900(vc)4=vy=Rω2

By conservation of angular momentum,

IRω1=IRω2+mcvyRmRR2ω1=(mR+2mc)R2ω2ω2=mRω1(mR+2mc)

Potential energy at position 1 and position 2

v1=mcgRv2=0

The kinetic energy of position 1 and position 2

T1=IRω122=12mRR2ω12T2=IRω122+12mc(vx2+vY2)=mRR2ω224+mcR2ω222+mcvy22

Applying conservation of energy principle,

T1+v1=T2+v2mRR2ω124+mcgR=mRR2ω224+mcR2ω222+mcvy22

But,

Mass of collar, mc=wcg=0.1849kg

Mass of ring, mR=wRg=0.277kg

ω2=mRω1(mR+2mc)=0.277×35(0.277+2×0.1849)=14.98ω2=15rad/sec

Conclusion:

Using conservation of angular momentum we are able to find, the angular velocity of the ring for θ=900 is 15 a rad/sec.

Answer 13

To determine

(b)

What will be the velocity of collar with respect to ring? Collar is free to slide on a ring and ring is attached to a vertical shaft. Which rotates in a fixed bearing. Initially, collar is at top of the ring θ=0 at 35 rad/sec of angular velocity. Refer figure.

Expert Solution

Answer to Problem 17.91P

The corresponding velocity of collar relative to ring is 6.242 m/s.

Explanation of Solution

Given:

The weight of color = ωc=4lb=1.814kg

Mass of ring = ωr=6lb=2.721kg

The radius of the ring,

Rr=10in=0.254mθ=0vc=0

The angular velocity (ωc) of the collar = 35 rad/sec.

Concept used:

Conservation of angular momentum.

Conservation of energy.

Calculation:

Potential energy at position 1 and position 2

v1=mcgRv2=0

The kinetic energy of position 1 and position 2

T1=IRω122=12mRR2ω12T2=IRω122+12mc(vx2+vY2)=mRR2ω224+mcR2ω222+mcvy22

Applying conservation of energy principle,

T1+v1=T2+v2mRR2ω124+mcgR=mRR2ω224+mcR2ω222+mcvy22

mRR2ω124+mcgR=(mR4+mc2)R2ω22+mcvy225.472+0.4607=2.347+0.092vy2vy=6.242m/s.

Conclusion:

Using conservation of energy principle we are able to find the velocity of collar relative to ring at θ=900 is 6.242m/s

Answer 14

To determine

(b)

What will be the velocity of collar with respect to ring? Collar is free to slide on a ring and ring is attached to a vertical shaft. Which rotates in a fixed bearing. Initially, collar is at top of the ring θ=0 at 35 rad/sec of angular velocity. Refer figure.

Answer 15

Expert Solution

Answer to Problem 17.91P

The corresponding velocity of collar relative to ring is 6.242 m/s.

Answer 16

Expert Solution

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

Given:

The weight of color = ωc=4lb=1.814kg

Mass of ring = ωr=6lb=2.721kg

The radius of the ring,

Rr=10in=0.254mθ=0vc=0

The angular velocity (ωc) of the collar = 35 rad/sec.

Concept used:

Conservation of angular momentum.

Conservation of energy.

Calculation:

Potential energy at position 1 and position 2

v1=mcgRv2=0

The kinetic energy of position 1 and position 2

T1=IRω122=12mRR2ω12T2=IRω122+12mc(vx2+vY2)=mRR2ω224+mcR2ω222+mcvy22

Applying conservation of energy principle,

T1+v1=T2+v2mRR2ω124+mcgR=mRR2ω224+mcR2ω222+mcvy22

mRR2ω124+mcgR=(mR4+mc2)R2ω22+mcvy225.472+0.4607=2.347+0.092vy2vy=6.242m/s.

Conclusion:

Using conservation of energy principle we are able to find the velocity of collar relative to ring at θ=900 is 6.242m/s

Answer 20

Ch. 17.1 - A round object of mass m and radius r is released...Ch. 17.1 - Prob. 17.CQ2P Ch. 17.1 - Prob. 17.CQ3P Ch. 17.1 - Prob. 17.CQ4P Ch. 17.1 - Slender bar A is rigidly connected to a massless...Ch. 17.1 - A 200-kg flywheel is at rest when a constant 300 N...Ch. 17.1 - The rotor of an electric motor has an angular...Ch. 17.1 - Two uniform disks of the same material are...Ch. 17.1 - Two disks of the same material are attached to a...Ch. 17.1 - Prob. 17.5P

(a) Calculate the angular velocity of the ring when collar passes through 90 0 ? Collar is free to slide on a ring and ring is attached to a vertical shaft. Which rotates in a fixed bearing. Initially, collar is at top of the ring θ = 0 at 35 rad/sec of angular velocity. Refer figure.

Videos

(a)

Calculate the angular velocity of the ring when collar passes through 900 ? Collar is free to slide on a ring and ring is attached to a vertical shaft. Which rotates in a fixed bearing. Initially, collar is at top of the ring θ=0 at 35 rad/sec of angular velocity. Refer figure.

Answer to Problem 17.91P

Explanation of Solution

(b)

What will be the velocity of collar with respect to ring? Collar is free to slide on a ring and ring is attached to a vertical shaft. Which rotates in a fixed bearing. Initially, collar is at top of the ring θ=0 at 35 rad/sec of angular velocity. Refer figure.

Answer to Problem 17.91P

Explanation of Solution

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Chapter 17 Solutions

(a) Calculate the angular velocity of the ring when collar passes through 90 0 ? Collar is free to slide on a ring and ring is attached to a vertical shaft. Which rotates in a fixed bearing. Initially, collar is at top of the ring θ = 0 at 35 rad/sec of angular velocity. Refer figure.

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(a) Calculate the angular velocity of the ring when collar passes through 900 ? Collar is free to slide on a ring and ring is attached to a vertical shaft. Which rotates in a fixed bearing. Initially, collar is at top of the ring θ=0 at 35 rad/sec of angular velocity. Refer figure.

Answer to Problem 17.91P

Explanation of Solution

(b) What will be the velocity of collar with respect to ring? Collar is free to slide on a ring and ring is attached to a vertical shaft. Which rotates in a fixed bearing. Initially, collar is at top of the ring θ=0 at 35 rad/sec of angular velocity. Refer figure.

Answer to Problem 17.91P

Explanation of Solution

Want to see more full solutions like this?

Chapter 17 Solutions

(a)

Calculate the angular velocity of the ring when collar passes through 900 ? Collar is free to slide on a ring and ring is attached to a vertical shaft. Which rotates in a fixed bearing. Initially, collar is at top of the ring θ=0 at 35 rad/sec of angular velocity. Refer figure.

(b)

What will be the velocity of collar with respect to ring? Collar is free to slide on a ring and ring is attached to a vertical shaft. Which rotates in a fixed bearing. Initially, collar is at top of the ring θ=0 at 35 rad/sec of angular velocity. Refer figure.