Given:

It is given in the question that the equation is 4x−3y−9=0 .

Concept Used:

In this we have to keep some concept in mind:

(i) The graph of y=mx+b is a straight line ,in which the slope is m and the y − intercept is (0,b) .

(ii)Slope intercept form : y=mx+b

(iii) m=risesun

  (a)If m>0 ,the line rises from left to right.

  (b)If m=0 ,the line is horizontal.

  (c)If m<0 ,the line falls from left to right.

  (d)If m is undefined, the line is vertical.

Calculation: The given equation is, 4x−3y−9=0 .

  4x−3y−9=0  (solve for y)−3y=−4x+9y=−4x+9−3y=−43x−93y=−43x−3

Here,it has seen that , m=−43 and the y − intersept is (0,−3) .

The graph passes through the point (0,−3) ,and it is the straight line that is upward.

Conclusion:

The slope is m=−43 and the y − intersept is (0,−3) .