The distance d from a point P (x_p,y_p,z_p) to the line that passes through the two points A (x_A,y_A,z_A) and B (x_B,y_B,z_B) can be calculated by d=2S/r where r is the distance between the points A and B, given by r = ( x B − x A ) 2 + ( y B − y A ) 2 + ( z B − z A ) 2 and S is the area of the triangle defined by the three points calculated by where s = s 1 2 + s 2 2 + s 3 3 where

s 1 = x P y A + x A y B + x B y P − ( y P x A + y A x B + y B x P ) s 2 = y P z A + y A z B + y B z P − ( z P y A + z A y B + z B y P ) s 3 = x P z A + x A z B + x B z P − ( z P x A + z A x B + z B x P ) . Determine the distance of point P(2,6,-1) from the line that passes through point A(-2, -1.5,-3) and point B(-2.5,6,4). First define the variables x_P,y_P,z_P, x_A, y_A, z_A, x_B,y_B, and z_B,and then use the variable tocalculate s₁, s₂, s₃. and r. Finally calculate S and d.