The given expressions are,

3==5+2

'b'<'a'+1

10>5+2

(10>5)+2

'c'=='d'-1&&2<4

'c'=='d'-1||2>4

xor('c'=='d'-1, 2>4)

xor('c'=='d'-1, 2<4)

10>5>2

There are only two possibilities that can be concluded from the expression. If the expression is true, then it will have the logical value 1. If the expression is false, then it will have the logical value 0. The given expression “3==5+2” is false. Hence, the output will be 0.

Consider the value of a is 0 and the value of b is 1. The output will be,

b<a+11<0+1

The obtained output is false. Hence, it will have the logical value 0.

The given expression “10>5+2” is false. Hence, the output will be 1.

In the expression “(10>5)+2”, first “(10>5)” will be evaluated. This expression is true. Hence, it will have the logical value 1. Add “2” to this logical value. The final output is 3.

Consider the value of c is 0 and the value of d is 1 in the expression “'c'=='d'-1&&2<4”. The expression becomes,

c==d−1&&2<40==1−1&&2<4

In this expression, the order of preference is “−, <, ==, &&”. Hence,

0==(1−1)&&2<40==0&&(2<4)     (0==0)&&1     1&&1     1

Consider the value of c is 0 and the value of d is 1 in the expression “'c'=='d'-1||2>4”. The expression becomes,

c==d−1||2>40==1−1||2>4

In this expression, the order of preference is “−, <, ==, ||”. Hence,

                  0==(1−1)||2>4                  0==0||(2>4)(0==0)||0                     1||0                        1

Consider the value of c is 0 and the value of d is 1 in the expression “xor('c'=='d'-1, 2>4)”. The expression becomes,

xor(c==d−1,2>4)xor(0==1−1,2>4)

In this expression, the order of preference is “−, <, ==, xor”. Hence,

xor(0==(1−1),2>4)xor(0==0,(2>4))xor((0==0),0)xor(1,0)1

Consider the value of c is 0 and the value of d is 1 in the expression “xor('c'=='d'-1&&2<4)”. The expression becomes,

xor(c==d−1,2<4)xor(0==1−1,2<4)

In this expression, the order of preference is “−, <, ==, xor”. Hence,

xor(0==(1−1),2<4)xor(0==0,(2<4))xor((0==0),1)xor(1,1)0

In the expression “10>5>2”, first “(10>5)” will be evaluated. This expression is true. Hence, it will have the logical value 1. Now “(1>2)” is false. Hence, it will have the logical value 0.

MATLAB Code:

3==5+2

'b'<'a'+1

10>5+2

(10>5)+2

'c'=='d'-1&&2<4

'c'=='d'-1||2>4

xor('c'=='d'-1, 2>4)

xor('c'=='d'-1, 2<4)

10>5>2

Save the MATLAB script with name, chapter1_54793_1_3P.m in the current folder. Execute the script by typing the script name at the command window to generate output.

Result:

Therefore, the required variable is created.