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1. Consider the systems whose transfer functions are given as below. Determine (i) BIBO stability, (ii) strict internal stability, and (iii) marginally internal stability for each of the systems. You should be able to answer these just simply finding the poles and checking sign of real part of the poles. a) H(s) = (s-3) (s+1) (s+3)² 2 (s-5) b) H(s) = c) H(s) = (s-5)(s+1) $2 ((s+3)²+4)2 d) H(s) = e) H(s) = S (s-3)²+4 (S-4) (s²-4s)(s+1)² f) H(s) = S+1 (s²+9)2

1. Consider the systems whose transfer functions are given as below. Determine (i) BIBO stability, (ii) strict internal stability, and (iii) marginally internal stability for each of the systems. You should be able to answer these just simply finding the poles and checking sign of real part of the poles. a) H(s) = (s-3) (s+1) (s+3)² 2 (s-5) b) H(s) = c) H(s) = (s-5)(s+1) $2 ((s+3)²+4)2 d) H(s) = e) H(s) = S (s-3)²+4 (S-4) (s²-4s)(s+1)² f) H(s) = S+1 (s²+9)2

Power System Analysis and Design (MindTap Course List)
Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter6: Power Flows
Section: Chapter Questions
Problem 6.16P
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1. Consider the systems whose transfer functions are given as below. Determine (i) BIBO stability, (ii) strict internal stability, and (iii) marginally internal stability for each of the systems. You should be able to answer these just simply finding the poles and checking sign of real part of the poles. a) H(s) = (s-3) (s+1) (s+3)² 2 (s-5) b) H(s) = c) H(s) = (s-5)(s+1) $2 ((s+3)²+4)2 d) H(s) = e) H(s) = S (s-3)²+4 (S-4) (s²-4s)(s+1)² f) H(s) = S+1 (s²+9)2
Transcribed Image Text:1. Consider the systems whose transfer functions are given as below. Determine (i) BIBO stability, (ii) strict internal stability, and (iii) marginally internal stability for each of the systems. You should be able to answer these just simply finding the poles and checking sign of real part of the poles. a) H(s) = (s-3) (s+1) (s+3)² 2 (s-5) b) H(s) = c) H(s) = (s-5)(s+1) $2 ((s+3)²+4)2 d) H(s) = e) H(s) = S (s-3)²+4 (S-4) (s²-4s)(s+1)² f) H(s) = S+1 (s²+9)2
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