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Search: a056894 -id:a056894
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a(n) = smallest number m such that m^2+n is prime.
+10
7
1, 0, 0, 1, 0, 1, 0, 3, 2, 1, 0, 1, 0, 3, 2, 1, 0, 1, 0, 3, 4, 1, 0, 7, 2, 9, 2, 1, 0, 1, 0, 3, 2, 3, 6, 1, 0, 3, 2, 1, 0, 1, 0, 3, 4, 1, 0, 5, 2, 3, 4, 1, 0, 5, 2, 9, 2, 1, 0, 1, 0, 3, 2, 3, 6, 1, 0, 9, 2, 1, 0, 1, 0, 3, 2, 5, 6, 1, 0, 3, 4, 1, 0, 5, 2, 9, 4, 1, 0, 7, 4, 3, 2, 3, 6, 1, 0, 3, 2
OFFSET
1,8
LINKS
FORMULA
a(n) = sqrt(A056896(n)-n) = sqrt(A056897(n)).
For p a prime: a(p) = 0 (and a(p-1) = 1 if p<>3).
EXAMPLE
a(8) = 3 since 3^2+8 = 17 which is prime.
PROG
(PARI) A056898(n) = { my(m=0); while(!isprime((m*m)+n), m++); (m); }; \\ Antti Karttunen, Mar 04 2018
KEYWORD
nonn
AUTHOR
Henry Bottomley, Jul 05 2000
STATUS
approved
Smallest prime with square excess of n.
+10
5
2, 3, 7, 13, 41, 31, 23, 89, 73, 59, 47, 61, 113, 239, 79, 97, 593, 139, 163, 461, 277, 191, 167, 193, 281, 251, 223, 317, 353, 991, 431, 761, 433, 563, 359, 397, 521, 479, 439, 569, 617, 571, 619, 773, 829, 887, 947, 673, 1493, 1571, 727, 1013, 953, 1279
OFFSET
1,1
FORMULA
a(n) =n+A056894(n).
a(n) = min{p in A000040: A053186(p) = n}. - R. J. Mathar, Jul 28 2013
EXAMPLE
a(4)=13 since 13=3^2+4, while 2, 3, 5, 7 and 11 have square excesses of 1, 2, 1, 3 and 3 respectively.
MAPLE
A056893 := proc(n)
local p ;
p :=2 ;
while A053186(p) <> n do
p := nextprime(p) ;
end do:
return p ;
end proc: # R. J. Mathar, Jul 28 2013
PROG
(PARI) A056893(n)={
local(p=2) ;
while( A053186(p)!=n,
p=nextprime(p+1)
) ;
return(p)
} /* R. J. Mathar, Jul 28 2013 */
KEYWORD
nonn
AUTHOR
Henry Bottomley, Jul 05 2000
STATUS
approved
If the smallest prime with a square excess of n is p then a(n)^2 = p - n.
+10
3
1, 1, 2, 3, 6, 5, 4, 9, 8, 7, 6, 7, 10, 15, 8, 9, 24, 11, 12, 21, 16, 13, 12, 13, 16, 15, 14, 17, 18, 31, 20, 27, 20, 23, 18, 19, 22, 21, 20, 23, 24, 23, 24, 27, 28, 29, 30, 25, 38, 39, 26, 31, 30, 35, 28, 45, 34, 31, 42, 31, 34, 33, 32, 33, 36, 35, 34, 75, 40, 37, 36, 41, 48, 45
OFFSET
1,3
LINKS
FORMULA
a(n) = sqrt(A056893(n)-n) = A000196(A056893(n)) = sqrt(A056894(n)).
EXAMPLE
a(4)=3 because the smallest prime with a square excess of 4 is 13 and 13 - 4 = 3^2.
MATHEMATICA
a = {}; Do[p = 2; While[n != p - (r = Floor@Sqrt[p])^2, p = NextPrime[p]]; AppendTo[a, r], {n, 74}]; a (* Ivan Neretin, May 02 2019 *)
PROG
(PARI) a(n) = {my(p=2); while(n != p-sqrtint(p)^2, p = nextprime(p+1)); sqrtint(p - n); } \\ Michel Marcus, May 05 2019
KEYWORD
nonn
AUTHOR
Henry Bottomley, Jul 05 2000
STATUS
approved

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