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%I A023397 #18 Jan 27 2022 22:48:04
%S A023397 2,3,2,3,2,2,2,3,2,3,2,3,3,2,3,3,3,3,3,3,2,3,2,2,2,3,3,3,3,3,3,3,3,2,
%T A023397 3,3,2,3,3,3,3,3,2,2,2,2,3,3,2,3,2,2,3,2,2,3,2,2,3,2,2,2,2,3,2,2,3,2,
%U A023397 3,3,3,2,2,3,3,3,2,3,3,3,2,2,2,2,2,3,2,2,3,3,3,2,3,2,3,3,2,3,2,3,3,2,2,2,2,2,3,2
%N A023397 In base 10, if any power of 2 ends with k 2's and 3's, they must be the first k terms of this sequence in reverse order.
%H A023397 Ray Chandler, <a href="/A023397/b023397.txt">Table of n, a(n) for n = 1..10000</a>
%e A023397 No power of 2 ends with 3, so the first term is 2.
%e A023397 No power of 2 is == 22 (mod 100), since 4 does not divide 22, so the next term is 3 (and 4 does divide 32).
%e A023397 No power of 2 is == 332 (mod 1000), since 8 does not divide 332, so the next term is 2 (and 8 does divide 232). And so on.
%Y A023397 Cf. A023410, A053316.
%K A023397 nonn,base
%O A023397 1,1
%A A023397 _David W. Wilson_

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