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Permutation of nonnegative integers: a(n) = A264978(A263272(n)).
3

%I #7 Dec 13 2023 08:37:55

%S 0,1,2,3,8,5,6,17,4,9,10,7,24,26,14,15,44,16,18,19,20,51,53,11,12,35,

%T 13,27,28,29,30,89,23,21,62,22,72,71,25,78,80,41,42,125,43,45,46,47,

%U 132,134,50,48,143,49,54,55,56,57,170,59,60,179,58,153,152,52,159,161,32,33,98,31,36,37,34,105,107,38,39,116,40,81

%N Permutation of nonnegative integers: a(n) = A264978(A263272(n)).

%C Composition of A263272 with the permutation obtained from its quadrisection. Equally: composition of permutations that are obtained from the bisection and octisection of A263273.

%H Antti Karttunen, <a href="/A265343/b265343.txt">Table of n, a(n) for n = 0..6561</a>

%H <a href="/index/Per#IntegerPermutation">Index entries for sequences that are permutations of the natural numbers</a>

%F a(n) = A264978(A263272(n)).

%F Other identities. For all n >= 0:

%F a(3*n) = 3*a(n).

%o (Scheme) (define (A265343 n) (A264978 (A263272 n)))

%Y Inverse: A265344.

%Y Cf. A263272, A263273, A264978.

%Y Cf. also A265363.

%K nonn,base

%O 0,3

%A _Antti Karttunen_, Dec 07 2015