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A259935
Infinite sequence of positive integers such that a(n) = A000005(a(1) + a(2) + ... + a(n)) for all n >= 1.
9
2, 4, 6, 6, 4, 8, 4, 8, 4, 8, 4, 4, 8, 8, 12, 4, 8, 4, 8, 4, 3, 4, 4, 15, 8, 10, 4, 8, 8, 8, 4, 16, 4, 8, 8, 6, 6, 8, 4, 16, 4, 8, 12, 4, 4, 8, 4, 16, 12, 4, 8, 4, 8, 8, 16, 4, 8, 8, 8, 8, 8, 8, 4, 16, 4, 8, 12, 8, 16, 12, 8, 16, 12, 4, 4, 8, 8, 8, 8, 8, 24, 8, 12, 8, 4, 8, 8, 8, 16, 8, 6, 6, 8, 4, 8, 4, 8, 8, 12, 8, 18, 8, 32, 24, 18, 4, 8, 16, 4, 16, 4, 8, 12, 8, 8, 8, 8, 8, 8, 12
OFFSET
1,1
COMMENTS
V. S. Guba (2015) proved that such an infinite sequence exists. Numerical evidence suggests that it may also be unique (cf. A259934).
If there are infinitely many n with a(n) = a(n+1), then A175304 is infinite (see comment in A259934). - Vladimir Shevelev, Jul 21 2015
LINKS
N. J. A. Sloane, Table of n, a(n) for n = 1..64800 (Based on Robert Israel's b-file for A259934.)
V. S. Guba et al., Sequence and divisors, 2015. (in Russian)
FORMULA
a(n) = A000005(A259934(n)) = A259934(n) - A259934(n-1).
gcd(a(n), A259934(n)) = A286540(n) = A009191(A259934(n)). - Antti Karttunen, Nov 26 2017
CROSSREFS
First differences of A259934.
Sequence in context: A248844 A257821 A238365 * A054584 A049041 A092337
KEYWORD
nonn,nice
AUTHOR
Max Alekseyev, Jul 09 2015
STATUS
approved