%I #6 May 18 2014 11:41:54

%S 1,0,0,0,0,3,14,78,497,3628,29990,277200,2834328,31770514,387459072,

%T 5108103000,72397196844,1097800704000,17735107218083,304112751022080,

%U 5516784599040000,105559797875432727,2124765080865042873,44881973505008640000,992717442773183102976

%N floor(n! / n^3).

%F a(n) = A000142(n-1) / A000290(n).

%o (Python)

%o import math

%o for i in range(1,32): print str(math.factorial(i)/(i**3))+',',

%Y Cf. A000142, A000578, A072230, A242427.

%Y Cf. A226198 (floor(n!/n^2)).

%K nonn

%O 1,6

%A _Alex Ratushnyak_, May 14 2014