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A185456
Payphone packing sequence.
0
1, 3, 5, 8, 9, 14, 15, 16, 17, 26, 27, 28, 29, 30, 31, 32, 33, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 98, 99, 100, 101, 102, 103, 104, 105, 106, 107, 108, 109, 110, 111, 112, 113, 114, 115, 116, 117, 118, 119, 120, 121, 122, 123, 124
OFFSET
1,2
COMMENTS
Assume that the first person to use a bank of payphones selects one at the end, and all subsequent users select the phone which puts them farthest from the current phone users. U(n) is the smallest number of phones such that n may be used without any two adjacent phones being used.
FORMULA
a(n) is the index of the n-th record in A166079, which is given by the recurrence y(n) = y(m) + y(n-m+1) - 1, with y(1) = y(2) = 1 and y(3) = 2, where m = ceiling(n/2). - John W. Layman, Feb 05 2011
From Nathaniel Johnston, Apr 12 2011: (Start)
a(n) = a(n-1) + n - 1 if n = 2^k + 2 for some natural number k, a(n) = a(n-1) + 1 otherwise, for n >= 3.
a(n) = n + 2^(1+floor(log_2(n-2))) for n >= 3. (End)
EXAMPLE
For 4 phones, only the outer two will be used. For a fifth phone, however, a third person may come along and use the middle phone without any two being adjacent; thus U(3)=5. A seventh phone will not lead to a fourth being used without adjacent people, but an eighth will, hence U(4)=8.
CROSSREFS
Sequence in context: A050094 A137319 A138808 * A308405 A331314 A018804
KEYWORD
easy,nonn
AUTHOR
Craig B. Daniel, Feb 04 2011
EXTENSIONS
Terms 26,27,...,114 added by John W. Layman, Feb 05 2011
Edited by N. J. A. Sloane, Feb 07 2011
a(51) - a(60) from Nathaniel Johnston, Apr 12 2011
STATUS
approved