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Numbers k such that k^3 divides 16^(k^2) + 1.
9

%I #7 Jun 06 2021 06:32:07

%S 1,17,707489,5030929,6029713,209372172193,250938565921,1413292053713,

%T 1784415176081,24025953593297,48948914347889,1423524187400657,

%U 5817190224008753,49446116858851553,74262006382962977

%N Numbers k such that k^3 divides 16^(k^2) + 1.

%C 17 divides a(n) for n > 1.

%Y Cf. A127263 k^3 divides 2^(k^2) + 1).

%Y Cf. A128678, A128679, A128680, A128681, A128682, A128683, A128684, A128685.

%Y Cf. A177813, A177814, A177816, A177817, A177818, A177819, A177820.

%Y Cf. A128677 (least k > p such that (k*p)^3 divides (p-1)^(k*p)^2+1, where p = prime(n) > 2).

%K nonn

%O 1,2

%A _Alexander Adamchuk_, May 14 2010

%E Terms a(6) onward from _Max Alekseyev_, May 16 2010