OFFSET
1,1
REFERENCES
Mohammad K. Azarian, Sylvester's Sequence and the Infinite Egyptian Fraction Decomposition of 1, Problem 958, College Mathematics Journal, Vol. 42, No. 4, September 2011, p. 330. Solution published in Vol. 43, No. 4, September 2012, pp. 340-342
FORMULA
a(n) = round((3.08435104906918990233569320020272148875011089837398848476442237096569...)^(2 ^n)) = round(A144807^(2^n)). [corrected by Joerg Arndt, Jan 15 2021]
a(n+1) = a(n)^2 - a(n) + 1, with a(1) = 10.
MATHEMATICA
a = {}; r = 10; Do[AppendTo[a, r]; r = r^2 - r + 1, {n, 1, 10}]; a (* or *)
Table[Round[3.0843510490691899023356932002027214887501108983739884847644223709656918819573478313933749294227854951850767 2786196650938869338548385641623^(2^n)], {n, 1, 8}] (* Artur Jasinski *)
NestList[#^2-#+1&, 10, 8] (* Harvey P. Dale, May 07 2017 *)
CROSSREFS
KEYWORD
nonn
AUTHOR
Artur Jasinski, Sep 21 2008
STATUS
approved