| 1 | import re
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| 2 | import sys
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| 3 |
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| 4 | # Reason last stmt is continued (or C_NONE if it's not).
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| 5 | (C_NONE, C_BACKSLASH, C_STRING_FIRST_LINE,
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| 6 | C_STRING_NEXT_LINES, C_BRACKET) = range(5)
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| 7 |
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| 8 | if 0: # for throwaway debugging output
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| 9 | def dump(*stuff):
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| 10 | sys.__stdout__.write(" ".join(map(str, stuff)) + "\n")
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| 11 |
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| 12 | # Find what looks like the start of a popular stmt.
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| 13 |
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| 14 | _synchre = re.compile(r"""
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| 15 | ^
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| 16 | [ \t]*
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| 17 | (?: while
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| 18 | | else
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| 19 | | def
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| 20 | | return
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| 21 | | assert
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| 22 | | break
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| 23 | | class
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| 24 | | continue
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| 25 | | elif
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| 26 | | try
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| 27 | | except
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| 28 | | raise
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| 29 | | import
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| 30 | | yield
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| 31 | )
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| 32 | \b
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| 33 | """, re.VERBOSE | re.MULTILINE).search
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| 34 |
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| 35 | # Match blank line or non-indenting comment line.
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| 36 |
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| 37 | _junkre = re.compile(r"""
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| 38 | [ \t]*
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| 39 | (?: \# \S .* )?
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| 40 | \n
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| 41 | """, re.VERBOSE).match
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| 42 |
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| 43 | # Match any flavor of string; the terminating quote is optional
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| 44 | # so that we're robust in the face of incomplete program text.
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| 45 |
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| 46 | _match_stringre = re.compile(r"""
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| 47 | \""" [^"\\]* (?:
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| 48 | (?: \\. | "(?!"") )
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| 49 | [^"\\]*
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| 50 | )*
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| 51 | (?: \""" )?
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| 52 |
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| 53 | | " [^"\\\n]* (?: \\. [^"\\\n]* )* "?
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| 54 |
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| 55 | | ''' [^'\\]* (?:
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| 56 | (?: \\. | '(?!'') )
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| 57 | [^'\\]*
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| 58 | )*
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| 59 | (?: ''' )?
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| 60 |
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| 61 | | ' [^'\\\n]* (?: \\. [^'\\\n]* )* '?
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| 62 | """, re.VERBOSE | re.DOTALL).match
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| 63 |
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| 64 | # Match a line that starts with something interesting;
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| 65 | # used to find the first item of a bracket structure.
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| 66 |
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| 67 | _itemre = re.compile(r"""
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| 68 | [ \t]*
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| 69 | [^\s#\\] # if we match, m.end()-1 is the interesting char
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| 70 | """, re.VERBOSE).match
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| 71 |
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| 72 | # Match start of stmts that should be followed by a dedent.
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| 73 |
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| 74 | _closere = re.compile(r"""
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| 75 | \s*
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| 76 | (?: return
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| 77 | | break
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| 78 | | continue
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| 79 | | raise
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| 80 | | pass
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| 81 | )
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| 82 | \b
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| 83 | """, re.VERBOSE).match
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| 84 |
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| 85 | # Chew up non-special chars as quickly as possible. If match is
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| 86 | # successful, m.end() less 1 is the index of the last boring char
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| 87 | # matched. If match is unsuccessful, the string starts with an
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| 88 | # interesting char.
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| 89 |
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| 90 | _chew_ordinaryre = re.compile(r"""
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| 91 | [^[\](){}#'"\\]+
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| 92 | """, re.VERBOSE).match
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| 93 |
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| 94 | # Build translation table to map uninteresting chars to "x", open
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| 95 | # brackets to "(", and close brackets to ")".
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| 96 |
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| 97 | _tran = ['x'] * 256
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| 98 | for ch in "({[":
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| 99 | _tran[ord(ch)] = '('
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| 100 | for ch in ")}]":
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| 101 | _tran[ord(ch)] = ')'
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| 102 | for ch in "\"'\\\n#":
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| 103 | _tran[ord(ch)] = ch
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| 104 | _tran = ''.join(_tran)
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| 105 | del ch
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| 106 |
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| 107 | try:
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| 108 | UnicodeType = type(unicode(""))
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| 109 | except NameError:
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| 110 | UnicodeType = None
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| 111 |
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| 112 | class Parser:
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| 113 |
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| 114 | def __init__(self, indentwidth, tabwidth):
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| 115 | self.indentwidth = indentwidth
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| 116 | self.tabwidth = tabwidth
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| 117 |
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| 118 | def set_str(self, str):
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| 119 | assert len(str) == 0 or str[-1] == '\n'
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| 120 | if type(str) is UnicodeType:
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| 121 | # The parse functions have no idea what to do with Unicode, so
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| 122 | # replace all Unicode characters with "x". This is "safe"
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| 123 | # so long as the only characters germane to parsing the structure
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| 124 | # of Python are 7-bit ASCII. It's *necessary* because Unicode
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| 125 | # strings don't have a .translate() method that supports
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| 126 | # deletechars.
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| 127 | uniphooey = str
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| 128 | str = []
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| 129 | push = str.append
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| 130 | for raw in map(ord, uniphooey):
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| 131 | push(raw < 127 and chr(raw) or "x")
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| 132 | str = "".join(str)
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| 133 | self.str = str
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| 134 | self.study_level = 0
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| 135 |
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| 136 | # Return index of a good place to begin parsing, as close to the
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| 137 | # end of the string as possible. This will be the start of some
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| 138 | # popular stmt like "if" or "def". Return None if none found:
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| 139 | # the caller should pass more prior context then, if possible, or
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| 140 | # if not (the entire program text up until the point of interest
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| 141 | # has already been tried) pass 0 to set_lo.
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| 142 | #
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| 143 | # This will be reliable iff given a reliable is_char_in_string
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| 144 | # function, meaning that when it says "no", it's absolutely
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| 145 | # guaranteed that the char is not in a string.
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| 146 |
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| 147 | def find_good_parse_start(self, is_char_in_string=None,
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| 148 | _synchre=_synchre):
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| 149 | str, pos = self.str, None
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| 150 |
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| 151 | if not is_char_in_string:
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| 152 | # no clue -- make the caller pass everything
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| 153 | return None
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| 154 |
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| 155 | # Peek back from the end for a good place to start,
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| 156 | # but don't try too often; pos will be left None, or
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| 157 | # bumped to a legitimate synch point.
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| 158 | limit = len(str)
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| 159 | for tries in range(5):
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| 160 | i = str.rfind(":\n", 0, limit)
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| 161 | if i < 0:
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| 162 | break
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| 163 | i = str.rfind('\n', 0, i) + 1 # start of colon line
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| 164 | m = _synchre(str, i, limit)
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| 165 | if m and not is_char_in_string(m.start()):
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| 166 | pos = m.start()
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| 167 | break
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| 168 | limit = i
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| 169 | if pos is None:
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| 170 | # Nothing looks like a block-opener, or stuff does
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| 171 | # but is_char_in_string keeps returning true; most likely
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| 172 | # we're in or near a giant string, the colorizer hasn't
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| 173 | # caught up enough to be helpful, or there simply *aren't*
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| 174 | # any interesting stmts. In any of these cases we're
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| 175 | # going to have to parse the whole thing to be sure, so
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| 176 | # give it one last try from the start, but stop wasting
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| 177 | # time here regardless of the outcome.
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| 178 | m = _synchre(str)
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| 179 | if m and not is_char_in_string(m.start()):
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| 180 | pos = m.start()
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| 181 | return pos
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| 182 |
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| 183 | # Peeking back worked; look forward until _synchre no longer
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| 184 | # matches.
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| 185 | i = pos + 1
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| 186 | while 1:
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| 187 | m = _synchre(str, i)
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| 188 | if m:
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| 189 | s, i = m.span()
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| 190 | if not is_char_in_string(s):
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| 191 | pos = s
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| 192 | else:
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| 193 | break
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| 194 | return pos
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| 195 |
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| 196 | # Throw away the start of the string. Intended to be called with
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| 197 | # find_good_parse_start's result.
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| 198 |
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| 199 | def set_lo(self, lo):
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| 200 | assert lo == 0 or self.str[lo-1] == '\n'
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| 201 | if lo > 0:
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| 202 | self.str = self.str[lo:]
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| 203 |
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| 204 | # As quickly as humanly possible <wink>, find the line numbers (0-
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| 205 | # based) of the non-continuation lines.
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| 206 | # Creates self.{goodlines, continuation}.
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| 207 |
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| 208 | def _study1(self):
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| 209 | if self.study_level >= 1:
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| 210 | return
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| 211 | self.study_level = 1
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| 212 |
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| 213 | # Map all uninteresting characters to "x", all open brackets
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| 214 | # to "(", all close brackets to ")", then collapse runs of
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| 215 | # uninteresting characters. This can cut the number of chars
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| 216 | # by a factor of 10-40, and so greatly speed the following loop.
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| 217 | str = self.str
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| 218 | str = str.translate(_tran)
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| 219 | str = str.replace('xxxxxxxx', 'x')
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| 220 | str = str.replace('xxxx', 'x')
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| 221 | str = str.replace('xx', 'x')
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| 222 | str = str.replace('xx', 'x')
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| 223 | str = str.replace('\nx', '\n')
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| 224 | # note that replacing x\n with \n would be incorrect, because
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| 225 | # x may be preceded by a backslash
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| 226 |
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| 227 | # March over the squashed version of the program, accumulating
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| 228 | # the line numbers of non-continued stmts, and determining
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| 229 | # whether & why the last stmt is a continuation.
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| 230 | continuation = C_NONE
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| 231 | level = lno = 0 # level is nesting level; lno is line number
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| 232 | self.goodlines = goodlines = [0]
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| 233 | push_good = goodlines.append
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| 234 | i, n = 0, len(str)
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| 235 | while i < n:
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| 236 | ch = str[i]
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| 237 | i = i+1
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| 238 |
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| 239 | # cases are checked in decreasing order of frequency
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| 240 | if ch == 'x':
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| 241 | continue
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| 242 |
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| 243 | if ch == '\n':
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| 244 | lno = lno + 1
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| 245 | if level == 0:
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| 246 | push_good(lno)
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| 247 | # else we're in an unclosed bracket structure
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| 248 | continue
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| 249 |
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| 250 | if ch == '(':
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| 251 | level = level + 1
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| 252 | continue
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| 253 |
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| 254 | if ch == ')':
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| 255 | if level:
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| 256 | level = level - 1
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| 257 | # else the program is invalid, but we can't complain
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| 258 | continue
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| 259 |
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| 260 | if ch == '"' or ch == "'":
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| 261 | # consume the string
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| 262 | quote = ch
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| 263 | if str[i-1:i+2] == quote * 3:
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| 264 | quote = quote * 3
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| 265 | firstlno = lno
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| 266 | w = len(quote) - 1
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| 267 | i = i+w
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| 268 | while i < n:
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| 269 | ch = str[i]
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| 270 | i = i+1
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| 271 |
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| 272 | if ch == 'x':
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| 273 | continue
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| 274 |
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| 275 | if str[i-1:i+w] == quote:
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| 276 | i = i+w
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| 277 | break
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| 278 |
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| 279 | if ch == '\n':
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| 280 | lno = lno + 1
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| 281 | if w == 0:
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| 282 | # unterminated single-quoted string
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| 283 | if level == 0:
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| 284 | push_good(lno)
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| 285 | break
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| 286 | continue
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| 287 |
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| 288 | if ch == '\\':
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| 289 | assert i < n
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| 290 | if str[i] == '\n':
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| 291 | lno = lno + 1
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| 292 | i = i+1
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| 293 | continue
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| 294 |
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| 295 | # else comment char or paren inside string
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| 296 |
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| 297 | else:
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| 298 | # didn't break out of the loop, so we're still
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| 299 | # inside a string
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| 300 | if (lno - 1) == firstlno:
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| 301 | # before the previous \n in str, we were in the first
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| 302 | # line of the string
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| 303 | continuation = C_STRING_FIRST_LINE
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| 304 | else:
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| 305 | continuation = C_STRING_NEXT_LINES
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| 306 | continue # with outer loop
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| 307 |
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| 308 | if ch == '#':
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| 309 | # consume the comment
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| 310 | i = str.find('\n', i)
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| 311 | assert i >= 0
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| 312 | continue
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| 313 |
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| 314 | assert ch == '\\'
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| 315 | assert i < n
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| 316 | if str[i] == '\n':
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| 317 | lno = lno + 1
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| 318 | if i+1 == n:
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| 319 | continuation = C_BACKSLASH
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| 320 | i = i+1
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| 321 |
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| 322 | # The last stmt may be continued for all 3 reasons.
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| 323 | # String continuation takes precedence over bracket
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| 324 | # continuation, which beats backslash continuation.
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| 325 | if (continuation != C_STRING_FIRST_LINE
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| 326 | and continuation != C_STRING_NEXT_LINES and level > 0):
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| 327 | continuation = C_BRACKET
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| 328 | self.continuation = continuation
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| 329 |
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| 330 | # Push the final line number as a sentinel value, regardless of
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| 331 | # whether it's continued.
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| 332 | assert (continuation == C_NONE) == (goodlines[-1] == lno)
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| 333 | if goodlines[-1] != lno:
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| 334 | push_good(lno)
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| 335 |
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| 336 | def get_continuation_type(self):
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| 337 | self._study1()
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| 338 | return self.continuation
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| 339 |
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| 340 | # study1 was sufficient to determine the continuation status,
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| 341 | # but doing more requires looking at every character. study2
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| 342 | # does this for the last interesting statement in the block.
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| 343 | # Creates:
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| 344 | # self.stmt_start, stmt_end
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| 345 | # slice indices of last interesting stmt
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| 346 | # self.stmt_bracketing
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| 347 | # the bracketing structure of the last interesting stmt;
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| 348 | # for example, for the statement "say(boo) or die", stmt_bracketing
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| 349 | # will be [(0, 0), (3, 1), (8, 0)]. Strings and comments are
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| 350 | # treated as brackets, for the matter.
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| 351 | # self.lastch
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| 352 | # last non-whitespace character before optional trailing
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| 353 | # comment
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| 354 | # self.lastopenbracketpos
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| 355 | # if continuation is C_BRACKET, index of last open bracket
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| 356 |
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| 357 | def _study2(self):
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| 358 | if self.study_level >= 2:
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| 359 | return
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| 360 | self._study1()
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| 361 | self.study_level = 2
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| 362 |
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| 363 | # Set p and q to slice indices of last interesting stmt.
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| 364 | str, goodlines = self.str, self.goodlines
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| 365 | i = len(goodlines) - 1
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| 366 | p = len(str) # index of newest line
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| 367 | while i:
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| 368 | assert p
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| 369 | # p is the index of the stmt at line number goodlines[i].
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| 370 | # Move p back to the stmt at line number goodlines[i-1].
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| 371 | q = p
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| 372 | for nothing in range(goodlines[i-1], goodlines[i]):
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| 373 | # tricky: sets p to 0 if no preceding newline
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| 374 | p = str.rfind('\n', 0, p-1) + 1
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| 375 | # The stmt str[p:q] isn't a continuation, but may be blank
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| 376 | # or a non-indenting comment line.
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| 377 | if _junkre(str, p):
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| 378 | i = i-1
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| 379 | else:
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| 380 | break
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| 381 | if i == 0:
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| 382 | # nothing but junk!
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| 383 | assert p == 0
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| 384 | q = p
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| 385 | self.stmt_start, self.stmt_end = p, q
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| 386 |
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| 387 | # Analyze this stmt, to find the last open bracket (if any)
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| 388 | # and last interesting character (if any).
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| 389 | lastch = ""
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| 390 | stack = [] # stack of open bracket indices
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| 391 | push_stack = stack.append
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| 392 | bracketing = [(p, 0)]
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| 393 | while p < q:
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| 394 | # suck up all except ()[]{}'"#\\
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| 395 | m = _chew_ordinaryre(str, p, q)
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| 396 | if m:
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| 397 | # we skipped at least one boring char
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| 398 | newp = m.end()
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| 399 | # back up over totally boring whitespace
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| 400 | i = newp - 1 # index of last boring char
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| 401 | while i >= p and str[i] in " \t\n":
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| 402 | i = i-1
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| 403 | if i >= p:
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| 404 | lastch = str[i]
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| 405 | p = newp
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| 406 | if p >= q:
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| 407 | break
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| 408 |
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| 409 | ch = str[p]
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| 410 |
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| 411 | if ch in "([{":
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| 412 | push_stack(p)
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| 413 | bracketing.append((p, len(stack)))
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| 414 | lastch = ch
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| 415 | p = p+1
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| 416 | continue
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| 417 |
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| 418 | if ch in ")]}":
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| 419 | if stack:
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| 420 | del stack[-1]
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| 421 | lastch = ch
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| 422 | p = p+1
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| 423 | bracketing.append((p, len(stack)))
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| 424 | continue
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| 425 |
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| 426 | if ch == '"' or ch == "'":
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| 427 | # consume string
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| 428 | # Note that study1 did this with a Python loop, but
|
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| 429 | # we use a regexp here; the reason is speed in both
|
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| 430 | # cases; the string may be huge, but study1 pre-squashed
|
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| 431 | # strings to a couple of characters per line. study1
|
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| 432 | # also needed to keep track of newlines, and we don't
|
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| 433 | # have to.
|
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| 434 | bracketing.append((p, len(stack)+1))
|
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| 435 | lastch = ch
|
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| 436 | p = _match_stringre(str, p, q).end()
|
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| 437 | bracketing.append((p, len(stack)))
|
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| 438 | continue
|
|---|
| 439 |
|
|---|
| 440 | if ch == '#':
|
|---|
| 441 | # consume comment and trailing newline
|
|---|
| 442 | bracketing.append((p, len(stack)+1))
|
|---|
| 443 | p = str.find('\n', p, q) + 1
|
|---|
| 444 | assert p > 0
|
|---|
| 445 | bracketing.append((p, len(stack)))
|
|---|
| 446 | continue
|
|---|
| 447 |
|
|---|
| 448 | assert ch == '\\'
|
|---|
| 449 | p = p+1 # beyond backslash
|
|---|
| 450 | assert p < q
|
|---|
| 451 | if str[p] != '\n':
|
|---|
| 452 | # the program is invalid, but can't complain
|
|---|
| 453 | lastch = ch + str[p]
|
|---|
| 454 | p = p+1 # beyond escaped char
|
|---|
| 455 |
|
|---|
| 456 | # end while p < q:
|
|---|
| 457 |
|
|---|
| 458 | self.lastch = lastch
|
|---|
| 459 | if stack:
|
|---|
| 460 | self.lastopenbracketpos = stack[-1]
|
|---|
| 461 | self.stmt_bracketing = tuple(bracketing)
|
|---|
| 462 |
|
|---|
| 463 | # Assuming continuation is C_BRACKET, return the number
|
|---|
| 464 | # of spaces the next line should be indented.
|
|---|
| 465 |
|
|---|
| 466 | def compute_bracket_indent(self):
|
|---|
| 467 | self._study2()
|
|---|
| 468 | assert self.continuation == C_BRACKET
|
|---|
| 469 | j = self.lastopenbracketpos
|
|---|
| 470 | str = self.str
|
|---|
| 471 | n = len(str)
|
|---|
| 472 | origi = i = str.rfind('\n', 0, j) + 1
|
|---|
| 473 | j = j+1 # one beyond open bracket
|
|---|
| 474 | # find first list item; set i to start of its line
|
|---|
| 475 | while j < n:
|
|---|
| 476 | m = _itemre(str, j)
|
|---|
| 477 | if m:
|
|---|
| 478 | j = m.end() - 1 # index of first interesting char
|
|---|
| 479 | extra = 0
|
|---|
| 480 | break
|
|---|
| 481 | else:
|
|---|
| 482 | # this line is junk; advance to next line
|
|---|
| 483 | i = j = str.find('\n', j) + 1
|
|---|
| 484 | else:
|
|---|
| 485 | # nothing interesting follows the bracket;
|
|---|
| 486 | # reproduce the bracket line's indentation + a level
|
|---|
| 487 | j = i = origi
|
|---|
| 488 | while str[j] in " \t":
|
|---|
| 489 | j = j+1
|
|---|
| 490 | extra = self.indentwidth
|
|---|
| 491 | return len(str[i:j].expandtabs(self.tabwidth)) + extra
|
|---|
| 492 |
|
|---|
| 493 | # Return number of physical lines in last stmt (whether or not
|
|---|
| 494 | # it's an interesting stmt! this is intended to be called when
|
|---|
| 495 | # continuation is C_BACKSLASH).
|
|---|
| 496 |
|
|---|
| 497 | def get_num_lines_in_stmt(self):
|
|---|
| 498 | self._study1()
|
|---|
| 499 | goodlines = self.goodlines
|
|---|
| 500 | return goodlines[-1] - goodlines[-2]
|
|---|
| 501 |
|
|---|
| 502 | # Assuming continuation is C_BACKSLASH, return the number of spaces
|
|---|
| 503 | # the next line should be indented. Also assuming the new line is
|
|---|
| 504 | # the first one following the initial line of the stmt.
|
|---|
| 505 |
|
|---|
| 506 | def compute_backslash_indent(self):
|
|---|
| 507 | self._study2()
|
|---|
| 508 | assert self.continuation == C_BACKSLASH
|
|---|
| 509 | str = self.str
|
|---|
| 510 | i = self.stmt_start
|
|---|
| 511 | while str[i] in " \t":
|
|---|
| 512 | i = i+1
|
|---|
| 513 | startpos = i
|
|---|
| 514 |
|
|---|
| 515 | # See whether the initial line starts an assignment stmt; i.e.,
|
|---|
| 516 | # look for an = operator
|
|---|
| 517 | endpos = str.find('\n', startpos) + 1
|
|---|
| 518 | found = level = 0
|
|---|
| 519 | while i < endpos:
|
|---|
| 520 | ch = str[i]
|
|---|
| 521 | if ch in "([{":
|
|---|
| 522 | level = level + 1
|
|---|
| 523 | i = i+1
|
|---|
| 524 | elif ch in ")]}":
|
|---|
| 525 | if level:
|
|---|
| 526 | level = level - 1
|
|---|
| 527 | i = i+1
|
|---|
| 528 | elif ch == '"' or ch == "'":
|
|---|
| 529 | i = _match_stringre(str, i, endpos).end()
|
|---|
| 530 | elif ch == '#':
|
|---|
| 531 | break
|
|---|
| 532 | elif level == 0 and ch == '=' and \
|
|---|
| 533 | (i == 0 or str[i-1] not in "=<>!") and \
|
|---|
| 534 | str[i+1] != '=':
|
|---|
| 535 | found = 1
|
|---|
| 536 | break
|
|---|
| 537 | else:
|
|---|
| 538 | i = i+1
|
|---|
| 539 |
|
|---|
| 540 | if found:
|
|---|
| 541 | # found a legit =, but it may be the last interesting
|
|---|
| 542 | # thing on the line
|
|---|
| 543 | i = i+1 # move beyond the =
|
|---|
| 544 | found = re.match(r"\s*\\", str[i:endpos]) is None
|
|---|
| 545 |
|
|---|
| 546 | if not found:
|
|---|
| 547 | # oh well ... settle for moving beyond the first chunk
|
|---|
| 548 | # of non-whitespace chars
|
|---|
| 549 | i = startpos
|
|---|
| 550 | while str[i] not in " \t\n":
|
|---|
| 551 | i = i+1
|
|---|
| 552 |
|
|---|
| 553 | return len(str[self.stmt_start:i].expandtabs(\
|
|---|
| 554 | self.tabwidth)) + 1
|
|---|
| 555 |
|
|---|
| 556 | # Return the leading whitespace on the initial line of the last
|
|---|
| 557 | # interesting stmt.
|
|---|
| 558 |
|
|---|
| 559 | def get_base_indent_string(self):
|
|---|
| 560 | self._study2()
|
|---|
| 561 | i, n = self.stmt_start, self.stmt_end
|
|---|
| 562 | j = i
|
|---|
| 563 | str = self.str
|
|---|
| 564 | while j < n and str[j] in " \t":
|
|---|
| 565 | j = j + 1
|
|---|
| 566 | return str[i:j]
|
|---|
| 567 |
|
|---|
| 568 | # Did the last interesting stmt open a block?
|
|---|
| 569 |
|
|---|
| 570 | def is_block_opener(self):
|
|---|
| 571 | self._study2()
|
|---|
| 572 | return self.lastch == ':'
|
|---|
| 573 |
|
|---|
| 574 | # Did the last interesting stmt close a block?
|
|---|
| 575 |
|
|---|
| 576 | def is_block_closer(self):
|
|---|
| 577 | self._study2()
|
|---|
| 578 | return _closere(self.str, self.stmt_start) is not None
|
|---|
| 579 |
|
|---|
| 580 | # index of last open bracket ({[, or None if none
|
|---|
| 581 | lastopenbracketpos = None
|
|---|
| 582 |
|
|---|
| 583 | def get_last_open_bracket_pos(self):
|
|---|
| 584 | self._study2()
|
|---|
| 585 | return self.lastopenbracketpos
|
|---|
| 586 |
|
|---|
| 587 | # the structure of the bracketing of the last interesting statement,
|
|---|
| 588 | # in the format defined in _study2, or None if the text didn't contain
|
|---|
| 589 | # anything
|
|---|
| 590 | stmt_bracketing = None
|
|---|
| 591 |
|
|---|
| 592 | def get_last_stmt_bracketing(self):
|
|---|
| 593 | self._study2()
|
|---|
| 594 | return self.stmt_bracketing
|
|---|