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Solution: Challenge: Light activated switch

Solution: Challenge: Light activated switch

Uit de cursus: Electronics Foundations: Basic Circuits

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Solution: Challenge: Light activated switch

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- [Instructor] This is how I worked my way to a solution for the light-activated switch. I started by thinking of the Wheatstone bridge as two parallel voltage dividers. Since I'll be taking a differential measurement for the Wheatstone bridge output, the output voltage from the voltage divider on side A will serve as a reference that's compared against the output of the voltage divider on side B. I'm measuring the voltage across this gap, with the left half representing the positive side and the right half being the negative side. For simplicity, I decided to make the left two resistors on side A constant and equal. I chose to use 10-kiloohm resistors, since I had a bunch of them handy. Since they are equal, the output of the left voltage divider, which I've labeled as VA, will be equal to one-half of the input voltage of the Wheatstone bridge. For this challenge, it doesn't really matter what that input voltage is,…

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