Serialize to Xml
Imports System
Imports System.IO
Imports System.Xml
Imports System.Xml.Serialization
Public Class MainClass
Public Shared Sub Main()
Dim roster = New EmployeeCollection(DateTime.Now)
Dim employees = New Employee() _
{New Employee With {.Id = 1, .Name = "A", _
.Title = "Coder", _
.HireDate = DateTime.Now, _
.HourlyRate = 100.0}, _
New Employee With {.Id = 4, .Name = "B", _
.Title = "Coder", _
.HireDate = DateTime.Now, _
.HourlyRate = 100.75}}
roster.Employees = employees
Dim serializer As New XmlSerializer(GetType(EmployeeCollection))
Dim fs As New FileStream("EmployeeCollection.xml", FileMode.Create)
serializer.Serialize(fs, roster)
fs.Close()
roster = Nothing
fs = New FileStream("EmployeeCollection.xml", FileMode.Open)
roster = DirectCast(serializer.Deserialize(fs), EmployeeCollection)
serializer.Serialize(Console.Out, roster)
End Sub
End Class
<XmlRoot("EmployeeCollection")> _
Public Class EmployeeCollection
<XmlElement(ElementName:="LastUpdated", datatype:="date")> _
Public LastUpdated As DateTime
<XmlArray("Employees"), XmlArrayItem("Employee")> _
Public Employees As Employee()
Public Sub New()
End Sub
Public Sub New(ByVal update As DateTime)
Me.LastUpdated = update
End Sub
End Class
Public Class Employee
<XmlElement("Name")> _
Public Name As String = String.Empty
<XmlElement("Title")> _
Public Title As String = String.Empty
<XmlElement(ElementName:="HireDate", datatype:="date")> _
Public HireDate As DateTime = Date.MinValue
<XmlElement("HourlyRate")> _
Public HourlyRate As Decimal = 0
<XmlAttribute(AttributeName:="id", DataType:="integer")> _
Public Id As String = String.Empty
Public Sub New()
End Sub
Public Sub New(ByVal employeName As String, ByVal employeeTitle As String, ByVal employeeHireDate As DateTime, ByVal employeeHourlyRate As Decimal)
Me.Name = employeName
Me.Title = employeeTitle
Me.HireDate = employeeHireDate
Me.HourlyRate = employeeHourlyRate
End Sub
End Class