You can put this solution on YOUR website! cosec 45 = 1/sin 45 sin 45 = 1/ cosec 45 = 1/1/ cosec 45 =

tan 45 degrees _____ cot 45 degrees _____ This question is from textbook Answer by Nate(3500) ( Show Source ): You can put this solution on YOUR website!

For the 45 degree angle, think of the diagonal of a square. If the side lengths of the square are 1, then the diagonal (by the Pythagorean Theorem) is sqrt(2). Then sin(45) = cos(45) = tan(45) = cot(45) = sec(45) = csc(45) = For the 30 and 60 degree angles, think of an equilateral triangle cut in half; that forms two 30-60-90 right triangles.

csc(45) = sqrt(2) sec(45) = sqrt(2) the functions for 225 degrees are the same as the functions for 45 degrees except that, since the angle is in quadrant 3, the rules for the signs of the functions in quadrant 3 apply and you get:

Question 1194318: Evaluate sin45°+cos 45°−tan 45° cot 45°−sec 45°+csc 45° ...

Algebra -> Trigonometry-basics-> SOLUTION: Csc 520 is equal to ?ATan 45 BCos 20 CSin 20 DCsc 20 Log On

csc 45 degrees = sec 45 cos -30 degrees = cos 30 cos - 30 degrees = sin 60 cot 75 degrees = tan 15 ...

Question 440978: how do i rewrite the following trigonometric functions using angles between 0 and 90 degrees?

Question 655670: if csc of theta equals root 2, how many degrees is that? Answer by Alan3354(69443) ( Show Source ): You can put this solution on YOUR website!

You can put this solution on YOUR website! Signs Quadrant I II III IV ----- Sine + + - - Cosine + - - + Tangent + - + - Cotangent + - + - Secant + - - + Cosecant + + - - ----- The Secant and the Cosecant are both POSITIVE in quadrant I The Secant and the Cosecant are both NEGATIVE in quadrant III So the answer is quadrants I and III since to be equal they must have the same sign.