(The Rectangle class) Following the example of the Circle class in Section 9.2, design a class named Rectangle to represent a rectangle. The class contains: Two double data fields named width and height that specify the width and height of the rectangle. The default values are 1 for both width and height. A no-arg constructor that creates a default rectangle. A constructor that creates a rectangle with the specified width and height. A method named getArea() that returns the area of this rectangle. A method named getPerimeter() that returns the perimeter. Draw the UML diagram for the class then implement the class. Write a test program that creates two Rectangle objects- one with width 4 and height 40, and the other with width 3. 5 and height 35. 9. Display the width, height, area, and perimeter of each rectangle in this order.

Question

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Answer 1

Textbook Question

Chapter 9, Problem 9.1PE

(The Rectangle class) Following the example of the Circle class in Section 9.2, design a class named Rectangle to represent a rectangle. The class contains:

Two double data fields named width and height that specify the width and height of the rectangle. The default values are 1 for both width and height.
A no-arg constructor that creates a default rectangle.
A constructor that creates a rectangle with the specified width and height.
A method named getArea() that returns the area of this rectangle.
A method named getPerimeter() that returns the perimeter.

Draw the UML diagram for the class then implement the class. Write a test program that creates two Rectangle objects- one with width 4 and height 40, and the other with width 3. 5 and height 35. 9. Display the width, height, area, and perimeter of each rectangle in this order.

Expert Solution & Answer

Program Plan Intro

Rectangle

Program plan:

Import required packages.
Declare the main class named “Main”.
- Give the main method “public static void main ()”.
  - Create an object “myRectangle” and pass the arguments.
  - Print the area of the first rectangle along with width and height by calling the function “getArea()”
  - Print the perimeter of the first rectangle by calling the function “getPerimeter()”
  - Create another object “yourRectangle” and also pass the arguments.
  - Print the area of the second rectangle along with width and height by calling the function “getArea()”
  - Print the perimeter of the second rectangle by calling the function “getPerimeter()”
Define class named “MyRectangle”
- Declare the data members and default constructor.
- Declare a parameterized constructor.
  - Define a method “getArea()” to calculate the area of the rectangle.
  - Return the result.
  - Define a method “getPerimeter()” to calculate the perimeter of the rectangle.
  - Return the result.

Program Description Answer

The below program is used to display the area and perimeter of the two rectangles along with the width and height of the rectangles.

Explanation of Solution

Program:

// Class definition

public class One {

// Define main function

public static void main(String[] args) {

/*Create object for the class and pass the arguments */

MyRectangle myRectangle = new MyRectangle(4, 40);

// Print the area of the first rectangle

System.out.println("The area of a rectangle with width " + myRectangle.width + " and height "

+ myRectangle.height + " is " + myRectangle.getArea());

// Print the perimeter of the first rectangle

System.out.println("The perimeter of a rectangle is " + myRectangle.getPerimeter());

/* Create object for the class and pass the arguments */

MyRectangle yourRectangle = new MyRectangle(3.5, 35.9);

// Print the area of the second rectangle

System.out.println("The area of a rectangle with width " + yourRectangle.width + " and height "

+ yourRectangle.height + " is " + yourRectangle.getArea());

// Print the perimeter of the second rectangle

System.out.println("The perimeter of a rectangle is " + yourRectangle.getPerimeter());

}

// Class definition

class MyRectangle {

// Data members

double width = 1;

double height = 1;

// Default Constructor

public MyRectangle() {

}

// Parameterized Constructor

public MyRectangle(double newWidth, double newHeight) {

width = newWidth;

height = newHeight;

}

// Method to get the area of rectangle

public double getArea() {

/* Return the area value by multiplying width and height */

return width * height;

}

// Method to get the perimeter of rectangle

public double getPerimeter() {

/*Return the perimeter value by multiplying 2 with width and height */

return 2 * (width + height);

}

Sample Output

The area of a rectangle with width 4.0 and height 40.0 is 160.0

The perimeter of a rectangle is 88.0

The area of a rectangle with width 3.5 and height 35.9 is 125.64999999999999

The perimeter of a rectangle is 78.8

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03:28

Students have asked these similar questions

9. Consider the diagram on the right. Using this diagram and the four following terms: (a) lonization Energy, (b) Electron Affinity, (c) Mulliken Electronegativity, and (d) Polarizability, label each arrow with the correct term (you can label the arrows with the corresponding letter for space purposes). Please provide labels for both species X and Y. lonization Limit b) Indicate why. Energy- Species X Species Y Which species (X or Y) has the highest electronegativity? Which has the largest polarizability? c)( 2) Consider BH3 (boron trihydride) and TIH3 (thallium trihydride). Which one is more polarizable and why? Which one would have stronger intermolecular forces and why?

b) 12. Consider XeO a) Draw the correct Lewis structure for this molecule. Calculate the steric number for XeO3 and based on your answer, what would be the molecular geometry it adopts? d) c) (1mark) According to VB theory, what is the hybridization for this molecule? Use the space below to explicitly show how you have arrived to your answer in part c. Clearly Sketch how hybridization occurs using electron orbital box diagrams and link central and terminal atoms.

Consider CIFs and draw it's Lewis structure. What molecular geometry would you expect it 10. to have, and why? Comment on the distortion of the bond angles, if any is expected.

Answer 2

Textbook Question

Chapter 9, Problem 9.1PE

(The Rectangle class) Following the example of the Circle class in Section 9.2, design a class named Rectangle to represent a rectangle. The class contains:

Two double data fields named width and height that specify the width and height of the rectangle. The default values are 1 for both width and height.
A no-arg constructor that creates a default rectangle.
A constructor that creates a rectangle with the specified width and height.
A method named getArea() that returns the area of this rectangle.
A method named getPerimeter() that returns the perimeter.

Draw the UML diagram for the class then implement the class. Write a test program that creates two Rectangle objects- one with width 4 and height 40, and the other with width 3. 5 and height 35. 9. Display the width, height, area, and perimeter of each rectangle in this order.

Expert Solution & Answer

Program Plan Intro

Rectangle

Program plan:

Import required packages.
Declare the main class named “Main”.
- Give the main method “public static void main ()”.
  - Create an object “myRectangle” and pass the arguments.
  - Print the area of the first rectangle along with width and height by calling the function “getArea()”
  - Print the perimeter of the first rectangle by calling the function “getPerimeter()”
  - Create another object “yourRectangle” and also pass the arguments.
  - Print the area of the second rectangle along with width and height by calling the function “getArea()”
  - Print the perimeter of the second rectangle by calling the function “getPerimeter()”
Define class named “MyRectangle”
- Declare the data members and default constructor.
- Declare a parameterized constructor.
  - Define a method “getArea()” to calculate the area of the rectangle.
  - Return the result.
  - Define a method “getPerimeter()” to calculate the perimeter of the rectangle.
  - Return the result.

Program Description Answer

The below program is used to display the area and perimeter of the two rectangles along with the width and height of the rectangles.

Explanation of Solution

Program:

// Class definition

public class One {

// Define main function

public static void main(String[] args) {

/*Create object for the class and pass the arguments */

MyRectangle myRectangle = new MyRectangle(4, 40);

// Print the area of the first rectangle

System.out.println("The area of a rectangle with width " + myRectangle.width + " and height "

+ myRectangle.height + " is " + myRectangle.getArea());

// Print the perimeter of the first rectangle

System.out.println("The perimeter of a rectangle is " + myRectangle.getPerimeter());

/* Create object for the class and pass the arguments */

MyRectangle yourRectangle = new MyRectangle(3.5, 35.9);

// Print the area of the second rectangle

System.out.println("The area of a rectangle with width " + yourRectangle.width + " and height "

+ yourRectangle.height + " is " + yourRectangle.getArea());

// Print the perimeter of the second rectangle

System.out.println("The perimeter of a rectangle is " + yourRectangle.getPerimeter());

}

// Class definition

class MyRectangle {

// Data members

double width = 1;

double height = 1;

// Default Constructor

public MyRectangle() {

}

// Parameterized Constructor

public MyRectangle(double newWidth, double newHeight) {

width = newWidth;

height = newHeight;

}

// Method to get the area of rectangle

public double getArea() {

/* Return the area value by multiplying width and height */

return width * height;

}

// Method to get the perimeter of rectangle

public double getPerimeter() {

/*Return the perimeter value by multiplying 2 with width and height */

return 2 * (width + height);

}

Sample Output

The area of a rectangle with width 4.0 and height 40.0 is 160.0

The perimeter of a rectangle is 88.0

The area of a rectangle with width 3.5 and height 35.9 is 125.64999999999999

The perimeter of a rectangle is 78.8

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03:28

Answer 3

Textbook Question

Chapter 9, Problem 9.1PE

(The Rectangle class) Following the example of the Circle class in Section 9.2, design a class named Rectangle to represent a rectangle. The class contains:

Two double data fields named width and height that specify the width and height of the rectangle. The default values are 1 for both width and height.
A no-arg constructor that creates a default rectangle.
A constructor that creates a rectangle with the specified width and height.
A method named getArea() that returns the area of this rectangle.
A method named getPerimeter() that returns the perimeter.

Draw the UML diagram for the class then implement the class. Write a test program that creates two Rectangle objects- one with width 4 and height 40, and the other with width 3. 5 and height 35. 9. Display the width, height, area, and perimeter of each rectangle in this order.

Expert Solution & Answer

Program Plan Intro

Rectangle

Program plan:

Import required packages.
Declare the main class named “Main”.
- Give the main method “public static void main ()”.
  - Create an object “myRectangle” and pass the arguments.
  - Print the area of the first rectangle along with width and height by calling the function “getArea()”
  - Print the perimeter of the first rectangle by calling the function “getPerimeter()”
  - Create another object “yourRectangle” and also pass the arguments.
  - Print the area of the second rectangle along with width and height by calling the function “getArea()”
  - Print the perimeter of the second rectangle by calling the function “getPerimeter()”
Define class named “MyRectangle”
- Declare the data members and default constructor.
- Declare a parameterized constructor.
  - Define a method “getArea()” to calculate the area of the rectangle.
  - Return the result.
  - Define a method “getPerimeter()” to calculate the perimeter of the rectangle.
  - Return the result.

Program Description Answer

The below program is used to display the area and perimeter of the two rectangles along with the width and height of the rectangles.

Explanation of Solution

Program:

// Class definition

public class One {

// Define main function

public static void main(String[] args) {

/*Create object for the class and pass the arguments */

MyRectangle myRectangle = new MyRectangle(4, 40);

// Print the area of the first rectangle

System.out.println("The area of a rectangle with width " + myRectangle.width + " and height "

+ myRectangle.height + " is " + myRectangle.getArea());

// Print the perimeter of the first rectangle

System.out.println("The perimeter of a rectangle is " + myRectangle.getPerimeter());

/* Create object for the class and pass the arguments */

MyRectangle yourRectangle = new MyRectangle(3.5, 35.9);

// Print the area of the second rectangle

System.out.println("The area of a rectangle with width " + yourRectangle.width + " and height "

+ yourRectangle.height + " is " + yourRectangle.getArea());

// Print the perimeter of the second rectangle

System.out.println("The perimeter of a rectangle is " + yourRectangle.getPerimeter());

}

// Class definition

class MyRectangle {

// Data members

double width = 1;

double height = 1;

// Default Constructor

public MyRectangle() {

}

// Parameterized Constructor

public MyRectangle(double newWidth, double newHeight) {

width = newWidth;

height = newHeight;

}

// Method to get the area of rectangle

public double getArea() {

/* Return the area value by multiplying width and height */

return width * height;

}

// Method to get the perimeter of rectangle

public double getPerimeter() {

/*Return the perimeter value by multiplying 2 with width and height */

return 2 * (width + height);

}

Sample Output

The area of a rectangle with width 4.0 and height 40.0 is 160.0

The perimeter of a rectangle is 88.0

The area of a rectangle with width 3.5 and height 35.9 is 125.64999999999999

The perimeter of a rectangle is 78.8

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03:28

Answer 4

Textbook Question

Chapter 9, Problem 9.1PE

(The Rectangle class) Following the example of the Circle class in Section 9.2, design a class named Rectangle to represent a rectangle. The class contains:

Two double data fields named width and height that specify the width and height of the rectangle. The default values are 1 for both width and height.
A no-arg constructor that creates a default rectangle.
A constructor that creates a rectangle with the specified width and height.
A method named getArea() that returns the area of this rectangle.
A method named getPerimeter() that returns the perimeter.

Draw the UML diagram for the class then implement the class. Write a test program that creates two Rectangle objects- one with width 4 and height 40, and the other with width 3. 5 and height 35. 9. Display the width, height, area, and perimeter of each rectangle in this order.

Expert Solution & Answer

Program Plan Intro

Rectangle

Program plan:

Import required packages.
Declare the main class named “Main”.
- Give the main method “public static void main ()”.
  - Create an object “myRectangle” and pass the arguments.
  - Print the area of the first rectangle along with width and height by calling the function “getArea()”
  - Print the perimeter of the first rectangle by calling the function “getPerimeter()”
  - Create another object “yourRectangle” and also pass the arguments.
  - Print the area of the second rectangle along with width and height by calling the function “getArea()”
  - Print the perimeter of the second rectangle by calling the function “getPerimeter()”
Define class named “MyRectangle”
- Declare the data members and default constructor.
- Declare a parameterized constructor.
  - Define a method “getArea()” to calculate the area of the rectangle.
  - Return the result.
  - Define a method “getPerimeter()” to calculate the perimeter of the rectangle.
  - Return the result.

Program Description Answer

The below program is used to display the area and perimeter of the two rectangles along with the width and height of the rectangles.

Explanation of Solution

Program:

// Class definition

public class One {

// Define main function

public static void main(String[] args) {

/*Create object for the class and pass the arguments */

MyRectangle myRectangle = new MyRectangle(4, 40);

// Print the area of the first rectangle

System.out.println("The area of a rectangle with width " + myRectangle.width + " and height "

+ myRectangle.height + " is " + myRectangle.getArea());

// Print the perimeter of the first rectangle

System.out.println("The perimeter of a rectangle is " + myRectangle.getPerimeter());

/* Create object for the class and pass the arguments */

MyRectangle yourRectangle = new MyRectangle(3.5, 35.9);

// Print the area of the second rectangle

System.out.println("The area of a rectangle with width " + yourRectangle.width + " and height "

+ yourRectangle.height + " is " + yourRectangle.getArea());

// Print the perimeter of the second rectangle

System.out.println("The perimeter of a rectangle is " + yourRectangle.getPerimeter());

}

// Class definition

class MyRectangle {

// Data members

double width = 1;

double height = 1;

// Default Constructor

public MyRectangle() {

}

// Parameterized Constructor

public MyRectangle(double newWidth, double newHeight) {

width = newWidth;

height = newHeight;

}

// Method to get the area of rectangle

public double getArea() {

/* Return the area value by multiplying width and height */

return width * height;

}

// Method to get the perimeter of rectangle

public double getPerimeter() {

/*Return the perimeter value by multiplying 2 with width and height */

return 2 * (width + height);

}

Sample Output

The area of a rectangle with width 4.0 and height 40.0 is 160.0

The perimeter of a rectangle is 88.0

The area of a rectangle with width 3.5 and height 35.9 is 125.64999999999999

The perimeter of a rectangle is 78.8

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03:28

Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

Expert Solution & Answer

Program Plan Intro

Rectangle

Program plan:

Import required packages.
Declare the main class named “Main”.
- Give the main method “public static void main ()”.
  - Create an object “myRectangle” and pass the arguments.
  - Print the area of the first rectangle along with width and height by calling the function “getArea()”
  - Print the perimeter of the first rectangle by calling the function “getPerimeter()”
  - Create another object “yourRectangle” and also pass the arguments.
  - Print the area of the second rectangle along with width and height by calling the function “getArea()”
  - Print the perimeter of the second rectangle by calling the function “getPerimeter()”
Define class named “MyRectangle”
- Declare the data members and default constructor.
- Declare a parameterized constructor.
  - Define a method “getArea()” to calculate the area of the rectangle.
  - Return the result.
  - Define a method “getPerimeter()” to calculate the perimeter of the rectangle.
  - Return the result.

Program Description Answer

The below program is used to display the area and perimeter of the two rectangles along with the width and height of the rectangles.

Explanation of Solution

Program:

// Class definition

public class One {

// Define main function

public static void main(String[] args) {

/*Create object for the class and pass the arguments */

MyRectangle myRectangle = new MyRectangle(4, 40);

// Print the area of the first rectangle

System.out.println("The area of a rectangle with width " + myRectangle.width + " and height "

+ myRectangle.height + " is " + myRectangle.getArea());

// Print the perimeter of the first rectangle

System.out.println("The perimeter of a rectangle is " + myRectangle.getPerimeter());

/* Create object for the class and pass the arguments */

MyRectangle yourRectangle = new MyRectangle(3.5, 35.9);

// Print the area of the second rectangle

System.out.println("The area of a rectangle with width " + yourRectangle.width + " and height "

+ yourRectangle.height + " is " + yourRectangle.getArea());

// Print the perimeter of the second rectangle

System.out.println("The perimeter of a rectangle is " + yourRectangle.getPerimeter());

}

// Class definition

class MyRectangle {

// Data members

double width = 1;

double height = 1;

// Default Constructor

public MyRectangle() {

}

// Parameterized Constructor

public MyRectangle(double newWidth, double newHeight) {

width = newWidth;

height = newHeight;

}

// Method to get the area of rectangle

public double getArea() {

/* Return the area value by multiplying width and height */

return width * height;

}

// Method to get the perimeter of rectangle

public double getPerimeter() {

/*Return the perimeter value by multiplying 2 with width and height */

return 2 * (width + height);

}

Sample Output

The area of a rectangle with width 4.0 and height 40.0 is 160.0

The perimeter of a rectangle is 88.0

The area of a rectangle with width 3.5 and height 35.9 is 125.64999999999999

The perimeter of a rectangle is 78.8

Answer 8

Expert Solution & Answer

Program Plan Intro

Rectangle

Program plan:

Import required packages.
Declare the main class named “Main”.
- Give the main method “public static void main ()”.
  - Create an object “myRectangle” and pass the arguments.
  - Print the area of the first rectangle along with width and height by calling the function “getArea()”
  - Print the perimeter of the first rectangle by calling the function “getPerimeter()”
  - Create another object “yourRectangle” and also pass the arguments.
  - Print the area of the second rectangle along with width and height by calling the function “getArea()”
  - Print the perimeter of the second rectangle by calling the function “getPerimeter()”
Define class named “MyRectangle”
- Declare the data members and default constructor.
- Declare a parameterized constructor.
  - Define a method “getArea()” to calculate the area of the rectangle.
  - Return the result.
  - Define a method “getPerimeter()” to calculate the perimeter of the rectangle.
  - Return the result.

Program Description Answer

The below program is used to display the area and perimeter of the two rectangles along with the width and height of the rectangles.

Explanation of Solution

Program:

// Class definition

public class One {

// Define main function

public static void main(String[] args) {

/*Create object for the class and pass the arguments */

MyRectangle myRectangle = new MyRectangle(4, 40);

// Print the area of the first rectangle

System.out.println("The area of a rectangle with width " + myRectangle.width + " and height "

+ myRectangle.height + " is " + myRectangle.getArea());

// Print the perimeter of the first rectangle

System.out.println("The perimeter of a rectangle is " + myRectangle.getPerimeter());

/* Create object for the class and pass the arguments */

MyRectangle yourRectangle = new MyRectangle(3.5, 35.9);

// Print the area of the second rectangle

System.out.println("The area of a rectangle with width " + yourRectangle.width + " and height "

+ yourRectangle.height + " is " + yourRectangle.getArea());

// Print the perimeter of the second rectangle

System.out.println("The perimeter of a rectangle is " + yourRectangle.getPerimeter());

}

// Class definition

class MyRectangle {

// Data members

double width = 1;

double height = 1;

// Default Constructor

public MyRectangle() {

}

// Parameterized Constructor

public MyRectangle(double newWidth, double newHeight) {

width = newWidth;

height = newHeight;

}

// Method to get the area of rectangle

public double getArea() {

/* Return the area value by multiplying width and height */

return width * height;

}

// Method to get the perimeter of rectangle

public double getPerimeter() {

/*Return the perimeter value by multiplying 2 with width and height */

return 2 * (width + height);

}

Sample Output

The area of a rectangle with width 4.0 and height 40.0 is 160.0

The perimeter of a rectangle is 88.0

The area of a rectangle with width 3.5 and height 35.9 is 125.64999999999999

The perimeter of a rectangle is 78.8

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Program Plan Intro

Rectangle

Program plan:

Import required packages.
Declare the main class named “Main”.
- Give the main method “public static void main ()”.
  - Create an object “myRectangle” and pass the arguments.
  - Print the area of the first rectangle along with width and height by calling the function “getArea()”
  - Print the perimeter of the first rectangle by calling the function “getPerimeter()”
  - Create another object “yourRectangle” and also pass the arguments.
  - Print the area of the second rectangle along with width and height by calling the function “getArea()”
  - Print the perimeter of the second rectangle by calling the function “getPerimeter()”
Define class named “MyRectangle”
- Declare the data members and default constructor.
- Declare a parameterized constructor.
  - Define a method “getArea()” to calculate the area of the rectangle.
  - Return the result.
  - Define a method “getPerimeter()” to calculate the perimeter of the rectangle.
  - Return the result.

Answer 12

Program Description Answer

The below program is used to display the area and perimeter of the two rectangles along with the width and height of the rectangles.

Answer 13

Explanation of Solution

Program:

// Class definition

public class One {

// Define main function

public static void main(String[] args) {

/*Create object for the class and pass the arguments */

MyRectangle myRectangle = new MyRectangle(4, 40);

// Print the area of the first rectangle

System.out.println("The area of a rectangle with width " + myRectangle.width + " and height "

+ myRectangle.height + " is " + myRectangle.getArea());

// Print the perimeter of the first rectangle

System.out.println("The perimeter of a rectangle is " + myRectangle.getPerimeter());

/* Create object for the class and pass the arguments */

MyRectangle yourRectangle = new MyRectangle(3.5, 35.9);

// Print the area of the second rectangle

System.out.println("The area of a rectangle with width " + yourRectangle.width + " and height "

+ yourRectangle.height + " is " + yourRectangle.getArea());

// Print the perimeter of the second rectangle

System.out.println("The perimeter of a rectangle is " + yourRectangle.getPerimeter());

}

// Class definition

class MyRectangle {

// Data members

double width = 1;

double height = 1;

// Default Constructor

public MyRectangle() {

}

// Parameterized Constructor

public MyRectangle(double newWidth, double newHeight) {

width = newWidth;

height = newHeight;

}

// Method to get the area of rectangle

public double getArea() {

/* Return the area value by multiplying width and height */

return width * height;

}

// Method to get the perimeter of rectangle

public double getPerimeter() {

/*Return the perimeter value by multiplying 2 with width and height */

return 2 * (width + height);

}

Answer 14

Sample Output

The area of a rectangle with width 4.0 and height 40.0 is 160.0

The perimeter of a rectangle is 88.0

The area of a rectangle with width 3.5 and height 35.9 is 125.64999999999999

The perimeter of a rectangle is 78.8

Answer 15

Ch. 9.3 - Prob. 9.3.1CP Ch. 9.3 - How do you define a class?Ch. 9.3 - How do you declare an objects reference variable?Ch. 9.3 - How do you create an object?Ch. 9.4 - Prob. 9.4.5CP Ch. 9.4 - When will a class have a default constructor?Ch. 9.5 - Which operator is used to access a data field or...Ch. 9.5 - What is an anonymous object?Ch. 9.5 - Prob. 9.5.3CP Ch. 9.5 - Is an array an object or a primitive-type value?...

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