(Probability) The probability that a phone call will last less than t minutes can be pproximated by the exponential probability function: Probability that a call lasts less than t m i n u t e s = 1 − e − t / a a i s t h e a v e r a g e c a l l l e n g t h . e i s E u l e r ’ s n u m b e r ( 2.71828 ) . For example, assuming the average call length is 2 minutes, the probability that a call will last less than 1 minute is calculated as 1 − e − 1 / 2 = 0.3297. Using this probability equation, write a C++ program that calculates and displays a list of probabilities of a call lasting less than 1 minute to less than 10 minutes, in 1-minute increments.

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Answer 1

Textbook Question

Chapter 5, Problem 1PP

(Probability) The probability that a phone call will last less than t minutes can be pproximated by the exponential probability function:

Probability that a call lasts less than t m i n u t e s = 1 − e − t / a

a i s t h e a v e r a g e c a l l l e n g t h . e i s E u l e r ’ s n u m b e r ( 2.71828 ) .

For example, assuming the average call length is 2 minutes, the probability that a call will last

less than 1 minute is calculated as 1 − e − 1 / 2 = 0.3297. Using this probability equation, write a

C++ program that calculates and displays a list of probabilities of a call lasting less than 1 minute to less than 10 minutes, in 1-minute increments.

Expert Solution & Answer

Program Plan Intro

Program plan:

Include the header files and using the namespace for standard I/O.
Define the main function.
Declare the variables x and z of integer type and y of double data type.
Declare the essential variables.
Use the loop to iterate.
Calculate the probability that the call last less than t minutes.
Display the list of probabilities in tabular format

Program description:

The main purpose of the program is to calculate theprobability of that a call will last less than one minute. This is calculated by the below formula: -

p=1−e−ta ∀ e is the Euler's number (2.71828) a is the average call length t is the minutes

Explanation of Solution

Program:

//Importing the essential headers
#include <iostream>
#include <iomanip>
#include <math.h>
//Using the namespace for standard I/O
usingnamespacestd;
//Defining the main function
intmain()
{
//Declaring the essential variables 
double p;//to store the Probability
double e =2.71828;//to store the Euler’s number
int a=2;//to store the average call length
cout<<"Call Time\tProbability\n";
//Using the loop to iterate 
for(int t =1; t <10; t++)
{
//Calculating the probability that the call last less than t minutes
        p =1-pow(e,(-1*t)/(a));
//Displaying the list of probabilities in tabular format 
cout<<setprecision(0)<< fixed << t <<"\t\t"<<setprecision(4)<< p <<endl;
}
}

Sample output:

C++ for Engineers and Scientists, Chapter 5, Problem 1PP

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(Dynamic Programming.) Recall the problem presented in Assign- ment 3 where given a list L of n ordered integers you're tasked with removing m of them such that the distance between the closest two remaining integers is maxi- mized. See Assignment 1 for further clarification and examples. As it turns out there is no (known) greedy algorithm to solve this problem. However, there is a dynamic programming solution. Devise a dynamic programming solution which determines the maximum distance between the closest two points after removing m numbers. Note, it doesn't need to return the resulting list itself. Hint 1: Your sub-problems should be of the form S(i, j), where S(i, j) returns the maximum distance of the closest two numbers when only considering removing j of the first i numbers in L. As an example if L [3, 4, 6, 8, 9, 12, 13, 15], then S(4, 1) = 2, since the closest two values of L' = [3,4,6,8] are 6 and 8 after removing 4 (note, 8-6 = = 2). = Hint 2: For the sub-problem S(i, j),…

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Answer 2

Textbook Question

Chapter 5, Problem 1PP

(Probability) The probability that a phone call will last less than t minutes can be pproximated by the exponential probability function:

Probability that a call lasts less than t m i n u t e s = 1 − e − t / a

a i s t h e a v e r a g e c a l l l e n g t h . e i s E u l e r ’ s n u m b e r ( 2.71828 ) .

For example, assuming the average call length is 2 minutes, the probability that a call will last

less than 1 minute is calculated as 1 − e − 1 / 2 = 0.3297. Using this probability equation, write a

C++ program that calculates and displays a list of probabilities of a call lasting less than 1 minute to less than 10 minutes, in 1-minute increments.

Expert Solution & Answer

Program Plan Intro

Program plan:

Include the header files and using the namespace for standard I/O.
Define the main function.
Declare the variables x and z of integer type and y of double data type.
Declare the essential variables.
Use the loop to iterate.
Calculate the probability that the call last less than t minutes.
Display the list of probabilities in tabular format

Program description:

The main purpose of the program is to calculate theprobability of that a call will last less than one minute. This is calculated by the below formula: -

p=1−e−ta ∀ e is the Euler's number (2.71828) a is the average call length t is the minutes

Explanation of Solution

Program:

//Importing the essential headers
#include <iostream>
#include <iomanip>
#include <math.h>
//Using the namespace for standard I/O
usingnamespacestd;
//Defining the main function
intmain()
{
//Declaring the essential variables 
double p;//to store the Probability
double e =2.71828;//to store the Euler’s number
int a=2;//to store the average call length
cout<<"Call Time\tProbability\n";
//Using the loop to iterate 
for(int t =1; t <10; t++)
{
//Calculating the probability that the call last less than t minutes
        p =1-pow(e,(-1*t)/(a));
//Displaying the list of probabilities in tabular format 
cout<<setprecision(0)<< fixed << t <<"\t\t"<<setprecision(4)<< p <<endl;
}
}

Sample output:

C++ for Engineers and Scientists, Chapter 5, Problem 1PP

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Answer 3

Textbook Question

Chapter 5, Problem 1PP

(Probability) The probability that a phone call will last less than t minutes can be pproximated by the exponential probability function:

Probability that a call lasts less than t m i n u t e s = 1 − e − t / a

a i s t h e a v e r a g e c a l l l e n g t h . e i s E u l e r ’ s n u m b e r ( 2.71828 ) .

For example, assuming the average call length is 2 minutes, the probability that a call will last

less than 1 minute is calculated as 1 − e − 1 / 2 = 0.3297. Using this probability equation, write a

C++ program that calculates and displays a list of probabilities of a call lasting less than 1 minute to less than 10 minutes, in 1-minute increments.

Expert Solution & Answer

Program Plan Intro

Program plan:

Include the header files and using the namespace for standard I/O.
Define the main function.
Declare the variables x and z of integer type and y of double data type.
Declare the essential variables.
Use the loop to iterate.
Calculate the probability that the call last less than t minutes.
Display the list of probabilities in tabular format

Program description:

The main purpose of the program is to calculate theprobability of that a call will last less than one minute. This is calculated by the below formula: -

p=1−e−ta ∀ e is the Euler's number (2.71828) a is the average call length t is the minutes

Explanation of Solution

Program:

//Importing the essential headers
#include <iostream>
#include <iomanip>
#include <math.h>
//Using the namespace for standard I/O
usingnamespacestd;
//Defining the main function
intmain()
{
//Declaring the essential variables 
double p;//to store the Probability
double e =2.71828;//to store the Euler’s number
int a=2;//to store the average call length
cout<<"Call Time\tProbability\n";
//Using the loop to iterate 
for(int t =1; t <10; t++)
{
//Calculating the probability that the call last less than t minutes
        p =1-pow(e,(-1*t)/(a));
//Displaying the list of probabilities in tabular format 
cout<<setprecision(0)<< fixed << t <<"\t\t"<<setprecision(4)<< p <<endl;
}
}

Sample output:

C++ for Engineers and Scientists, Chapter 5, Problem 1PP

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Answer 4

Textbook Question

Chapter 5, Problem 1PP

(Probability) The probability that a phone call will last less than t minutes can be pproximated by the exponential probability function:

Probability that a call lasts less than t m i n u t e s = 1 − e − t / a

a i s t h e a v e r a g e c a l l l e n g t h . e i s E u l e r ’ s n u m b e r ( 2.71828 ) .

For example, assuming the average call length is 2 minutes, the probability that a call will last

less than 1 minute is calculated as 1 − e − 1 / 2 = 0.3297. Using this probability equation, write a

C++ program that calculates and displays a list of probabilities of a call lasting less than 1 minute to less than 10 minutes, in 1-minute increments.

Expert Solution & Answer

Program Plan Intro

Program plan:

Include the header files and using the namespace for standard I/O.
Define the main function.
Declare the variables x and z of integer type and y of double data type.
Declare the essential variables.
Use the loop to iterate.
Calculate the probability that the call last less than t minutes.
Display the list of probabilities in tabular format

Program description:

The main purpose of the program is to calculate theprobability of that a call will last less than one minute. This is calculated by the below formula: -

p=1−e−ta ∀ e is the Euler's number (2.71828) a is the average call length t is the minutes

Explanation of Solution

Program:

//Importing the essential headers
#include <iostream>
#include <iomanip>
#include <math.h>
//Using the namespace for standard I/O
usingnamespacestd;
//Defining the main function
intmain()
{
//Declaring the essential variables 
double p;//to store the Probability
double e =2.71828;//to store the Euler’s number
int a=2;//to store the average call length
cout<<"Call Time\tProbability\n";
//Using the loop to iterate 
for(int t =1; t <10; t++)
{
//Calculating the probability that the call last less than t minutes
        p =1-pow(e,(-1*t)/(a));
//Displaying the list of probabilities in tabular format 
cout<<setprecision(0)<< fixed << t <<"\t\t"<<setprecision(4)<< p <<endl;
}
}

Sample output:

C++ for Engineers and Scientists, Chapter 5, Problem 1PP

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

Expert Solution & Answer

Program Plan Intro

Program plan:

Include the header files and using the namespace for standard I/O.
Define the main function.
Declare the variables x and z of integer type and y of double data type.
Declare the essential variables.
Use the loop to iterate.
Calculate the probability that the call last less than t minutes.
Display the list of probabilities in tabular format

Program description:

The main purpose of the program is to calculate theprobability of that a call will last less than one minute. This is calculated by the below formula: -

p=1−e−ta ∀ e is the Euler's number (2.71828) a is the average call length t is the minutes

Explanation of Solution

Program:

//Importing the essential headers
#include <iostream>
#include <iomanip>
#include <math.h>
//Using the namespace for standard I/O
usingnamespacestd;
//Defining the main function
intmain()
{
//Declaring the essential variables 
double p;//to store the Probability
double e =2.71828;//to store the Euler’s number
int a=2;//to store the average call length
cout<<"Call Time\tProbability\n";
//Using the loop to iterate 
for(int t =1; t <10; t++)
{
//Calculating the probability that the call last less than t minutes
        p =1-pow(e,(-1*t)/(a));
//Displaying the list of probabilities in tabular format 
cout<<setprecision(0)<< fixed << t <<"\t\t"<<setprecision(4)<< p <<endl;
}
}

Sample output:

C++ for Engineers and Scientists, Chapter 5, Problem 1PP

Answer 8

Expert Solution & Answer

Program Plan Intro

Program plan:

Include the header files and using the namespace for standard I/O.
Define the main function.
Declare the variables x and z of integer type and y of double data type.
Declare the essential variables.
Use the loop to iterate.
Calculate the probability that the call last less than t minutes.
Display the list of probabilities in tabular format

Program description:

The main purpose of the program is to calculate theprobability of that a call will last less than one minute. This is calculated by the below formula: -

p=1−e−ta ∀ e is the Euler's number (2.71828) a is the average call length t is the minutes

Explanation of Solution

Program:

//Importing the essential headers
#include <iostream>
#include <iomanip>
#include <math.h>
//Using the namespace for standard I/O
usingnamespacestd;
//Defining the main function
intmain()
{
//Declaring the essential variables 
double p;//to store the Probability
double e =2.71828;//to store the Euler’s number
int a=2;//to store the average call length
cout<<"Call Time\tProbability\n";
//Using the loop to iterate 
for(int t =1; t <10; t++)
{
//Calculating the probability that the call last less than t minutes
        p =1-pow(e,(-1*t)/(a));
//Displaying the list of probabilities in tabular format 
cout<<setprecision(0)<< fixed << t <<"\t\t"<<setprecision(4)<< p <<endl;
}
}

Sample output:

C++ for Engineers and Scientists, Chapter 5, Problem 1PP

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Program Plan Intro

Program plan:

Include the header files and using the namespace for standard I/O.
Define the main function.
Declare the variables x and z of integer type and y of double data type.
Declare the essential variables.
Use the loop to iterate.
Calculate the probability that the call last less than t minutes.
Display the list of probabilities in tabular format

Program description:

The main purpose of the program is to calculate theprobability of that a call will last less than one minute. This is calculated by the below formula: -

p=1−e−ta ∀ e is the Euler's number (2.71828) a is the average call length t is the minutes

Answer 12

Explanation of Solution

Program:

//Importing the essential headers
#include <iostream>
#include <iomanip>
#include <math.h>
//Using the namespace for standard I/O
usingnamespacestd;
//Defining the main function
intmain()
{
//Declaring the essential variables 
double p;//to store the Probability
double e =2.71828;//to store the Euler’s number
int a=2;//to store the average call length
cout<<"Call Time\tProbability\n";
//Using the loop to iterate 
for(int t =1; t <10; t++)
{
//Calculating the probability that the call last less than t minutes
        p =1-pow(e,(-1*t)/(a));
//Displaying the list of probabilities in tabular format 
cout<<setprecision(0)<< fixed << t <<"\t\t"<<setprecision(4)<< p <<endl;
}
}

Sample output:

C++ for Engineers and Scientists, Chapter 5, Problem 1PP

Answer 13

Ch. 5.1 - (For review) List the three repetition statements...Ch. 5.1 - Prob. 2E Ch. 5.1 - (For review) a. What’s the difference between a...Ch. 5.2 - (Practice) Rewrite Program 5.1 to print the...Ch. 5.2 - (Practice) Rewrite Program 5.4 to produce a table...Ch. 5.2 - (Conversion) Write a C++ program that converts...Ch. 5.2 - (Practice) An automobile travels at an average...Ch. 5.2 - (Numerical analysis) a. The following is an...Ch. 5.2 - Prob. 9E Ch. 5.3 - Prob. 1E

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