Chapter 3, Problem 1RE

Question

Want to see more full solutions like this?

Answer 1

Expert Solution & Answer

Chapter 3, Problem 1RE

Explanation of Solution

a.

//Initialize the variables

int n=1; int k=2; int r=n;

//Check the condition

if (k<n)

{

//Assign k to r

r=k

}

Value of each variable after “if” statement:

n=1, k=2, r=1

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “n” is not greater than “k” and so the value of “r” remains unchanged.

Explanation of Solution

b.

//Initialize the variables

int n=1; int k=2; int r;

//Check the condition

if (n<k)

{

    //Assign k to r

    r=k

}

//Otherwise

else

{

    //Add k+n and store it in r

    r=k+n;

}

Value of each variable after “if”statement:

n=1, k=2, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement is true. As the value of “k” is greater than “n” and so the value of “r” is changed to “2”.

Explanation of Solution

c.

//Initialize the variables

int n=1; int k=2; int r=k;

//Check the condition

if (r<k)

{

    //Assign k to r

    n=r

}

//Otherwise

else

{

    //Assign n to k

    k=n;

}

Value of each variable after “if”statement:

n=1, k=1, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “k” and it moves to the “else” part where the value of “k” is changed to value of “n” that is “1”. In the first statement, the value of “r” is initialized to value of “k” that is “2”.

Explanation of Solution

d.

//Initialize the variables

int n=1; int k=2; int r=3;

//Check the condition

if (r<n+k)

{

    //Assign k to r

    r=2n

}

//Otherwise

else

{

    //Assign n to k

    k=2r;

}

Value of each variable after “if”statement:

n=1, k=6, r=3

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “n+k” and it moves to the “else” part where the value of “k” is changed to value of “2*r” that is “6”. In the first statement, the value of “r” is initialized to “3”.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

You have learned in class the major steps that occur when a laptop requests a webpage after connecting to a network. In this assignment, you will apply that knowledge to another scenario: opening and playing a YouTube video that resides in Google's data-center infrastructure. Explain, in as much detail as you can, all the steps involved from your device's initial connection to the home/university network, to DNS resolution, routing across multiple networks, reaching Google's servers, and finally receiving the video data. To support your explanation, use tools such as ipconfig, nslookup, and tracert on your own computer, as well as any online IP-lookup tools of your choice. For each stage, include relevant information such as IP addresses, MAC addresses, router hops, and any other details you can gather. You are not expected to find every piece of information, but be as comprehensive as possible based on what you have learned in class, and justify your reasoning with screenshots from…

I need help with this question, please don,t use AI or chatgpt.

NO USE OF AI PLEASE

Answer 2

Expert Solution & Answer

Chapter 3, Problem 1RE

Explanation of Solution

a.

//Initialize the variables

int n=1; int k=2; int r=n;

//Check the condition

if (k<n)

{

//Assign k to r

r=k

}

Value of each variable after “if” statement:

n=1, k=2, r=1

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “n” is not greater than “k” and so the value of “r” remains unchanged.

Explanation of Solution

b.

//Initialize the variables

int n=1; int k=2; int r;

//Check the condition

if (n<k)

{

    //Assign k to r

    r=k

}

//Otherwise

else

{

    //Add k+n and store it in r

    r=k+n;

}

Value of each variable after “if”statement:

n=1, k=2, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement is true. As the value of “k” is greater than “n” and so the value of “r” is changed to “2”.

Explanation of Solution

c.

//Initialize the variables

int n=1; int k=2; int r=k;

//Check the condition

if (r<k)

{

    //Assign k to r

    n=r

}

//Otherwise

else

{

    //Assign n to k

    k=n;

}

Value of each variable after “if”statement:

n=1, k=1, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “k” and it moves to the “else” part where the value of “k” is changed to value of “n” that is “1”. In the first statement, the value of “r” is initialized to value of “k” that is “2”.

Explanation of Solution

d.

//Initialize the variables

int n=1; int k=2; int r=3;

//Check the condition

if (r<n+k)

{

    //Assign k to r

    r=2n

}

//Otherwise

else

{

    //Assign n to k

    k=2r;

}

Value of each variable after “if”statement:

n=1, k=6, r=3

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “n+k” and it moves to the “else” part where the value of “k” is changed to value of “2*r” that is “6”. In the first statement, the value of “r” is initialized to “3”.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Expert Solution & Answer

Chapter 3, Problem 1RE

Explanation of Solution

a.

//Initialize the variables

int n=1; int k=2; int r=n;

//Check the condition

if (k<n)

{

//Assign k to r

r=k

}

Value of each variable after “if” statement:

n=1, k=2, r=1

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “n” is not greater than “k” and so the value of “r” remains unchanged.

Explanation of Solution

b.

//Initialize the variables

int n=1; int k=2; int r;

//Check the condition

if (n<k)

{

    //Assign k to r

    r=k

}

//Otherwise

else

{

    //Add k+n and store it in r

    r=k+n;

}

Value of each variable after “if”statement:

n=1, k=2, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement is true. As the value of “k” is greater than “n” and so the value of “r” is changed to “2”.

Explanation of Solution

c.

//Initialize the variables

int n=1; int k=2; int r=k;

//Check the condition

if (r<k)

{

    //Assign k to r

    n=r

}

//Otherwise

else

{

    //Assign n to k

    k=n;

}

Value of each variable after “if”statement:

n=1, k=1, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “k” and it moves to the “else” part where the value of “k” is changed to value of “n” that is “1”. In the first statement, the value of “r” is initialized to value of “k” that is “2”.

Explanation of Solution

d.

//Initialize the variables

int n=1; int k=2; int r=3;

//Check the condition

if (r<n+k)

{

    //Assign k to r

    r=2n

}

//Otherwise

else

{

    //Assign n to k

    k=2r;

}

Value of each variable after “if”statement:

n=1, k=6, r=3

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “n+k” and it moves to the “else” part where the value of “k” is changed to value of “2*r” that is “6”. In the first statement, the value of “r” is initialized to “3”.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Expert Solution & Answer

Chapter 3, Problem 1RE

Explanation of Solution

a.

//Initialize the variables

int n=1; int k=2; int r=n;

//Check the condition

if (k<n)

{

//Assign k to r

r=k

}

Value of each variable after “if” statement:

n=1, k=2, r=1

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “n” is not greater than “k” and so the value of “r” remains unchanged.

Explanation of Solution

b.

//Initialize the variables

int n=1; int k=2; int r;

//Check the condition

if (n<k)

{

    //Assign k to r

    r=k

}

//Otherwise

else

{

    //Add k+n and store it in r

    r=k+n;

}

Value of each variable after “if”statement:

n=1, k=2, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement is true. As the value of “k” is greater than “n” and so the value of “r” is changed to “2”.

Explanation of Solution

c.

//Initialize the variables

int n=1; int k=2; int r=k;

//Check the condition

if (r<k)

{

    //Assign k to r

    n=r

}

//Otherwise

else

{

    //Assign n to k

    k=n;

}

Value of each variable after “if”statement:

n=1, k=1, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “k” and it moves to the “else” part where the value of “k” is changed to value of “n” that is “1”. In the first statement, the value of “r” is initialized to value of “k” that is “2”.

Explanation of Solution

d.

//Initialize the variables

int n=1; int k=2; int r=3;

//Check the condition

if (r<n+k)

{

    //Assign k to r

    r=2n

}

//Otherwise

else

{

    //Assign n to k

    k=2r;

}

Value of each variable after “if”statement:

n=1, k=6, r=3

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “n+k” and it moves to the “else” part where the value of “k” is changed to value of “2*r” that is “6”. In the first statement, the value of “r” is initialized to “3”.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Expert Solution & Answer

Answer 6

Expert Solution & Answer

Answer 7

Chapter 3, Problem 1RE

Explanation of Solution

a.

//Initialize the variables

int n=1; int k=2; int r=n;

//Check the condition

if (k<n)

{

//Assign k to r

r=k

}

Value of each variable after “if” statement:

n=1, k=2, r=1

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “n” is not greater than “k” and so the value of “r” remains unchanged.

Explanation of Solution

b.

//Initialize the variables

int n=1; int k=2; int r;

//Check the condition

if (n<k)

{

    //Assign k to r

    r=k

}

//Otherwise

else

{

    //Add k+n and store it in r

    r=k+n;

}

Value of each variable after “if”statement:

n=1, k=2, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement is true. As the value of “k” is greater than “n” and so the value of “r” is changed to “2”.

Explanation of Solution

c.

//Initialize the variables

int n=1; int k=2; int r=k;

//Check the condition

if (r<k)

{

    //Assign k to r

    n=r

}

//Otherwise

else

{

    //Assign n to k

    k=n;

}

Value of each variable after “if”statement:

n=1, k=1, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “k” and it moves to the “else” part where the value of “k” is changed to value of “n” that is “1”. In the first statement, the value of “r” is initialized to value of “k” that is “2”.

Explanation of Solution

d.

//Initialize the variables

int n=1; int k=2; int r=3;

//Check the condition

if (r<n+k)

{

    //Assign k to r

    r=2n

}

//Otherwise

else

{

    //Assign n to k

    k=2r;

}

Value of each variable after “if”statement:

n=1, k=6, r=3

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “n+k” and it moves to the “else” part where the value of “k” is changed to value of “2*r” that is “6”. In the first statement, the value of “r” is initialized to “3”.

Answer 8

Chapter 3, Problem 1RE

Explanation of Solution

a.

//Initialize the variables

int n=1; int k=2; int r=n;

//Check the condition

if (k<n)

{

//Assign k to r

r=k

}

Value of each variable after “if” statement:

n=1, k=2, r=1

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “n” is not greater than “k” and so the value of “r” remains unchanged.

Answer 9

Chapter 3, Problem 1RE

Explanation of Solution

a.

//Initialize the variables

int n=1; int k=2; int r=n;

//Check the condition

if (k<n)

{

//Assign k to r

r=k

}

Value of each variable after “if” statement:

n=1, k=2, r=1

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “n” is not greater than “k” and so the value of “r” remains unchanged.

Answer 10

Explanation of Solution

b.

//Initialize the variables

int n=1; int k=2; int r;

//Check the condition

if (n<k)

{

    //Assign k to r

    r=k

}

//Otherwise

else

{

    //Add k+n and store it in r

    r=k+n;

}

Value of each variable after “if”statement:

n=1, k=2, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement is true. As the value of “k” is greater than “n” and so the value of “r” is changed to “2”.

Answer 11

Explanation of Solution

b.

//Initialize the variables

int n=1; int k=2; int r;

//Check the condition

if (n<k)

{

    //Assign k to r

    r=k

}

//Otherwise

else

{

    //Add k+n and store it in r

    r=k+n;

}

Value of each variable after “if”statement:

n=1, k=2, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement is true. As the value of “k” is greater than “n” and so the value of “r” is changed to “2”.

Answer 12

Explanation of Solution

c.

//Initialize the variables

int n=1; int k=2; int r=k;

//Check the condition

if (r<k)

{

    //Assign k to r

    n=r

}

//Otherwise

else

{

    //Assign n to k

    k=n;

}

Value of each variable after “if”statement:

n=1, k=1, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “k” and it moves to the “else” part where the value of “k” is changed to value of “n” that is “1”. In the first statement, the value of “r” is initialized to value of “k” that is “2”.

Answer 13

Explanation of Solution

c.

//Initialize the variables

int n=1; int k=2; int r=k;

//Check the condition

if (r<k)

{

    //Assign k to r

    n=r

}

//Otherwise

else

{

    //Assign n to k

    k=n;

}

Value of each variable after “if”statement:

n=1, k=1, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “k” and it moves to the “else” part where the value of “k” is changed to value of “n” that is “1”. In the first statement, the value of “r” is initialized to value of “k” that is “2”.

Answer 14

Explanation of Solution

d.

//Initialize the variables

int n=1; int k=2; int r=3;

//Check the condition

if (r<n+k)

{

    //Assign k to r

    r=2n

}

//Otherwise

else

{

    //Assign n to k

    k=2r;

}

Value of each variable after “if”statement:

n=1, k=6, r=3

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “n+k” and it moves to the “else” part where the value of “k” is changed to value of “2*r” that is “6”. In the first statement, the value of “r” is initialized to “3”.

Answer 15

Explanation of Solution

d.

//Initialize the variables

int n=1; int k=2; int r=3;

//Check the condition

if (r<n+k)

{

    //Assign k to r

    r=2n

}

//Otherwise

else

{

    //Assign n to k

    k=2r;

}

Value of each variable after “if”statement:

n=1, k=6, r=3

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “n+k” and it moves to the “else” part where the value of “k” is changed to value of “2*r” that is “6”. In the first statement, the value of “r” is initialized to “3”.

Answer 16

Chapter 3.1, Problem 1SC Chapter 3.1, Problem 2SC Chapter 3.1, Problem 3SC Chapter 3.1, Problem 4SC Chapter 3.1, Problem 5SC Chapter 3.2, Problem 6SC Chapter 3.2, Problem 7SC Chapter 3.2, Problem 8SC Chapter 3.2, Problem 9SC Chapter 3.2, Problem 10SC

Chapter 3, Problem 1RE

Videos

Explanation of Solution

Explanation of Solution

Explanation of Solution

Explanation of Solution

Want to see more full solutions like this?

Chapter 3 Solutions

Additional Engineering Textbook Solutions