Chapter 3, Problem 1RE

Question

Want to see more full solutions like this?

Answer 1

Expert Solution & Answer

Chapter 3, Problem 1RE

Explanation of Solution

a.

//Initialize the variables

int n=1; int k=2; int r=n;

//Check the condition

if (k<n)

{

//Assign k to r

r=k

}

Value of each variable after “if” statement:

n=1, k=2, r=1

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “n” is not greater than “k” and so the value of “r” remains unchanged.

Explanation of Solution

b.

//Initialize the variables

int n=1; int k=2; int r;

//Check the condition

if (n<k)

{

    //Assign k to r

    r=k

}

//Otherwise

else

{

    //Add k+n and store it in r

    r=k+n;

}

Value of each variable after “if”statement:

n=1, k=2, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement is true. As the value of “k” is greater than “n” and so the value of “r” is changed to “2”.

Explanation of Solution

c.

//Initialize the variables

int n=1; int k=2; int r=k;

//Check the condition

if (r<k)

{

    //Assign k to r

    n=r

}

//Otherwise

else

{

    //Assign n to k

    k=n;

}

Value of each variable after “if”statement:

n=1, k=1, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “k” and it moves to the “else” part where the value of “k” is changed to value of “n” that is “1”. In the first statement, the value of “r” is initialized to value of “k” that is “2”.

Explanation of Solution

d.

//Initialize the variables

int n=1; int k=2; int r=3;

//Check the condition

if (r<n+k)

{

    //Assign k to r

    r=2n

}

//Otherwise

else

{

    //Assign n to k

    k=2r;

}

Value of each variable after “if”statement:

n=1, k=6, r=3

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “n+k” and it moves to the “else” part where the value of “k” is changed to value of “2*r” that is “6”. In the first statement, the value of “r” is initialized to “3”.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

Need help writing code to answer this question in Python! (image attached)

Need help with python code! How do I simplify my code for a beginner to understand, simple fixed format and centering? Such as: print(f"As an int variable: {age_int:^7}") print(f"In numeric binary: {age_int:^7b}") My Code:name = input("Enter your name: ")print(f"In text name is: {' '.join(name)}")decimal_values = []binary_values = []for letter in name: ascii_val = ord(letter) binary_val = format(ascii_val, '08b') decimal_values.append(str(ascii_val)) binary_values.append(binary_val)# Loop through each letter:print(f"In ASCII decimal: {' '.join(decimal_values)}")print(f"In ASCII binary: {' '.join(binary_values)}")# Ageage_str = input("Enter your age: ")age_int = int(age_str)print(f"As a string \"{age_str}\": {' '.join(age_str)}")age_decimal_values = []age_binary_values = []for digit in age_str: ascii_val = ord(digit) binary_val = format(ascii_val, '07b') age_decimal_values.append(str(ascii_val)) age_binary_values.append(binary_val)print(f"In ASCII decimal: {'…

Don't use chatgpt or any other AI

Answer 2

Expert Solution & Answer

Chapter 3, Problem 1RE

Explanation of Solution

a.

//Initialize the variables

int n=1; int k=2; int r=n;

//Check the condition

if (k<n)

{

//Assign k to r

r=k

}

Value of each variable after “if” statement:

n=1, k=2, r=1

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “n” is not greater than “k” and so the value of “r” remains unchanged.

Explanation of Solution

b.

//Initialize the variables

int n=1; int k=2; int r;

//Check the condition

if (n<k)

{

    //Assign k to r

    r=k

}

//Otherwise

else

{

    //Add k+n and store it in r

    r=k+n;

}

Value of each variable after “if”statement:

n=1, k=2, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement is true. As the value of “k” is greater than “n” and so the value of “r” is changed to “2”.

Explanation of Solution

c.

//Initialize the variables

int n=1; int k=2; int r=k;

//Check the condition

if (r<k)

{

    //Assign k to r

    n=r

}

//Otherwise

else

{

    //Assign n to k

    k=n;

}

Value of each variable after “if”statement:

n=1, k=1, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “k” and it moves to the “else” part where the value of “k” is changed to value of “n” that is “1”. In the first statement, the value of “r” is initialized to value of “k” that is “2”.

Explanation of Solution

d.

//Initialize the variables

int n=1; int k=2; int r=3;

//Check the condition

if (r<n+k)

{

    //Assign k to r

    r=2n

}

//Otherwise

else

{

    //Assign n to k

    k=2r;

}

Value of each variable after “if”statement:

n=1, k=6, r=3

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “n+k” and it moves to the “else” part where the value of “k” is changed to value of “2*r” that is “6”. In the first statement, the value of “r” is initialized to “3”.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Expert Solution & Answer

Chapter 3, Problem 1RE

Explanation of Solution

a.

//Initialize the variables

int n=1; int k=2; int r=n;

//Check the condition

if (k<n)

{

//Assign k to r

r=k

}

Value of each variable after “if” statement:

n=1, k=2, r=1

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “n” is not greater than “k” and so the value of “r” remains unchanged.

Explanation of Solution

b.

//Initialize the variables

int n=1; int k=2; int r;

//Check the condition

if (n<k)

{

    //Assign k to r

    r=k

}

//Otherwise

else

{

    //Add k+n and store it in r

    r=k+n;

}

Value of each variable after “if”statement:

n=1, k=2, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement is true. As the value of “k” is greater than “n” and so the value of “r” is changed to “2”.

Explanation of Solution

c.

//Initialize the variables

int n=1; int k=2; int r=k;

//Check the condition

if (r<k)

{

    //Assign k to r

    n=r

}

//Otherwise

else

{

    //Assign n to k

    k=n;

}

Value of each variable after “if”statement:

n=1, k=1, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “k” and it moves to the “else” part where the value of “k” is changed to value of “n” that is “1”. In the first statement, the value of “r” is initialized to value of “k” that is “2”.

Explanation of Solution

d.

//Initialize the variables

int n=1; int k=2; int r=3;

//Check the condition

if (r<n+k)

{

    //Assign k to r

    r=2n

}

//Otherwise

else

{

    //Assign n to k

    k=2r;

}

Value of each variable after “if”statement:

n=1, k=6, r=3

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “n+k” and it moves to the “else” part where the value of “k” is changed to value of “2*r” that is “6”. In the first statement, the value of “r” is initialized to “3”.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Expert Solution & Answer

Chapter 3, Problem 1RE

Explanation of Solution

a.

//Initialize the variables

int n=1; int k=2; int r=n;

//Check the condition

if (k<n)

{

//Assign k to r

r=k

}

Value of each variable after “if” statement:

n=1, k=2, r=1

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “n” is not greater than “k” and so the value of “r” remains unchanged.

Explanation of Solution

b.

//Initialize the variables

int n=1; int k=2; int r;

//Check the condition

if (n<k)

{

    //Assign k to r

    r=k

}

//Otherwise

else

{

    //Add k+n and store it in r

    r=k+n;

}

Value of each variable after “if”statement:

n=1, k=2, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement is true. As the value of “k” is greater than “n” and so the value of “r” is changed to “2”.

Explanation of Solution

c.

//Initialize the variables

int n=1; int k=2; int r=k;

//Check the condition

if (r<k)

{

    //Assign k to r

    n=r

}

//Otherwise

else

{

    //Assign n to k

    k=n;

}

Value of each variable after “if”statement:

n=1, k=1, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “k” and it moves to the “else” part where the value of “k” is changed to value of “n” that is “1”. In the first statement, the value of “r” is initialized to value of “k” that is “2”.

Explanation of Solution

d.

//Initialize the variables

int n=1; int k=2; int r=3;

//Check the condition

if (r<n+k)

{

    //Assign k to r

    r=2n

}

//Otherwise

else

{

    //Assign n to k

    k=2r;

}

Value of each variable after “if”statement:

n=1, k=6, r=3

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “n+k” and it moves to the “else” part where the value of “k” is changed to value of “2*r” that is “6”. In the first statement, the value of “r” is initialized to “3”.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Expert Solution & Answer

Answer 6

Expert Solution & Answer

Answer 7

Chapter 3, Problem 1RE

Explanation of Solution

a.

//Initialize the variables

int n=1; int k=2; int r=n;

//Check the condition

if (k<n)

{

//Assign k to r

r=k

}

Value of each variable after “if” statement:

n=1, k=2, r=1

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “n” is not greater than “k” and so the value of “r” remains unchanged.

Explanation of Solution

b.

//Initialize the variables

int n=1; int k=2; int r;

//Check the condition

if (n<k)

{

    //Assign k to r

    r=k

}

//Otherwise

else

{

    //Add k+n and store it in r

    r=k+n;

}

Value of each variable after “if”statement:

n=1, k=2, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement is true. As the value of “k” is greater than “n” and so the value of “r” is changed to “2”.

Explanation of Solution

c.

//Initialize the variables

int n=1; int k=2; int r=k;

//Check the condition

if (r<k)

{

    //Assign k to r

    n=r

}

//Otherwise

else

{

    //Assign n to k

    k=n;

}

Value of each variable after “if”statement:

n=1, k=1, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “k” and it moves to the “else” part where the value of “k” is changed to value of “n” that is “1”. In the first statement, the value of “r” is initialized to value of “k” that is “2”.

Explanation of Solution

d.

//Initialize the variables

int n=1; int k=2; int r=3;

//Check the condition

if (r<n+k)

{

    //Assign k to r

    r=2n

}

//Otherwise

else

{

    //Assign n to k

    k=2r;

}

Value of each variable after “if”statement:

n=1, k=6, r=3

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “n+k” and it moves to the “else” part where the value of “k” is changed to value of “2*r” that is “6”. In the first statement, the value of “r” is initialized to “3”.

Answer 8

Chapter 3, Problem 1RE

Explanation of Solution

a.

//Initialize the variables

int n=1; int k=2; int r=n;

//Check the condition

if (k<n)

{

//Assign k to r

r=k

}

Value of each variable after “if” statement:

n=1, k=2, r=1

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “n” is not greater than “k” and so the value of “r” remains unchanged.

Answer 9

Chapter 3, Problem 1RE

Explanation of Solution

a.

//Initialize the variables

int n=1; int k=2; int r=n;

//Check the condition

if (k<n)

{

//Assign k to r

r=k

}

Value of each variable after “if” statement:

n=1, k=2, r=1

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “n” is not greater than “k” and so the value of “r” remains unchanged.

Answer 10

Explanation of Solution

b.

//Initialize the variables

int n=1; int k=2; int r;

//Check the condition

if (n<k)

{

    //Assign k to r

    r=k

}

//Otherwise

else

{

    //Add k+n and store it in r

    r=k+n;

}

Value of each variable after “if”statement:

n=1, k=2, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement is true. As the value of “k” is greater than “n” and so the value of “r” is changed to “2”.

Answer 11

Explanation of Solution

b.

//Initialize the variables

int n=1; int k=2; int r;

//Check the condition

if (n<k)

{

    //Assign k to r

    r=k

}

//Otherwise

else

{

    //Add k+n and store it in r

    r=k+n;

}

Value of each variable after “if”statement:

n=1, k=2, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement is true. As the value of “k” is greater than “n” and so the value of “r” is changed to “2”.

Answer 12

Explanation of Solution

c.

//Initialize the variables

int n=1; int k=2; int r=k;

//Check the condition

if (r<k)

{

    //Assign k to r

    n=r

}

//Otherwise

else

{

    //Assign n to k

    k=n;

}

Value of each variable after “if”statement:

n=1, k=1, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “k” and it moves to the “else” part where the value of “k” is changed to value of “n” that is “1”. In the first statement, the value of “r” is initialized to value of “k” that is “2”.

Answer 13

Explanation of Solution

c.

//Initialize the variables

int n=1; int k=2; int r=k;

//Check the condition

if (r<k)

{

    //Assign k to r

    n=r

}

//Otherwise

else

{

    //Assign n to k

    k=n;

}

Value of each variable after “if”statement:

n=1, k=1, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “k” and it moves to the “else” part where the value of “k” is changed to value of “n” that is “1”. In the first statement, the value of “r” is initialized to value of “k” that is “2”.

Answer 14

Explanation of Solution

d.

//Initialize the variables

int n=1; int k=2; int r=3;

//Check the condition

if (r<n+k)

{

    //Assign k to r

    r=2n

}

//Otherwise

else

{

    //Assign n to k

    k=2r;

}

Value of each variable after “if”statement:

n=1, k=6, r=3

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “n+k” and it moves to the “else” part where the value of “k” is changed to value of “2*r” that is “6”. In the first statement, the value of “r” is initialized to “3”.

Answer 15

Explanation of Solution

d.

//Initialize the variables

int n=1; int k=2; int r=3;

//Check the condition

if (r<n+k)

{

    //Assign k to r

    r=2n

}

//Otherwise

else

{

    //Assign n to k

    k=2r;

}

Value of each variable after “if”statement:

n=1, k=6, r=3

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “n+k” and it moves to the “else” part where the value of “k” is changed to value of “2*r” that is “6”. In the first statement, the value of “r” is initialized to “3”.

Answer 16

Chapter 3.1, Problem 1SC Chapter 3.1, Problem 2SC Chapter 3.1, Problem 3SC Chapter 3.1, Problem 4SC Chapter 3.1, Problem 5SC Chapter 3.2, Problem 6SC Chapter 3.2, Problem 7SC Chapter 3.2, Problem 8SC Chapter 3.2, Problem 9SC Chapter 3.2, Problem 10SC

Chapter 3, Problem 1RE

Videos

Explanation of Solution

Explanation of Solution

Explanation of Solution

Explanation of Solution

Want to see more full solutions like this?

Chapter 3 Solutions

Additional Engineering Textbook Solutions